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\(\left(\frac{575757}{424242}+\frac{575757}{565656}+\frac{575757}{727272}\right)\cdot18\)
\(=\left(\frac{19}{14}+\frac{57}{56}+\frac{19}{24}\right)\cdot18\)
\(=\left(\frac{228+171+133}{168}\right)\cdot18\)
\(=\frac{532}{168}\cdot18\)
\(=\frac{19}{6}\cdot8\)
\(=\frac{76}{3}\)
1 \(A=\left(1+\frac{1}{2}\right)\times\left(1+\frac{1}{3}\right)\times\left(1+\frac{1}{4}\right)\times.........\times\left(1+\frac{1}{2016}\right)\times\left(1+\frac{1}{2017}\right)\)
\(A=\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times......\times\frac{2016}{2017}\times\frac{2018}{2017}\)
\(A=\frac{2018}{2}=1009\)
\(B=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+.......+\frac{2}{43.45}\)
\(B=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-......+\frac{1}{43}-\frac{1}{45}\)
\(B=\frac{1}{3}-\frac{1}{45}\)
\(B=\frac{14}{45}\)
2 \(\frac{2017}{2018}\times\frac{23}{47}+\frac{24}{2018}\times\frac{2017}{47}\)
\(=\frac{2017}{2018}\times\frac{23}{47}+\frac{24}{47}\times\frac{2017}{2018}\)
\(=\frac{2017}{2018}\times\left(\frac{23}{47}+\frac{24}{47}\right)\)
\(=\frac{2017}{2018}\times1\)
=\(\frac{2017}{2018}\)
bạn nào xem giải thế có đúng ko
\(6-\left(\frac76+\frac{7}{18}\right)\)
\(=6-\left(\frac{7\times3}{6\times3}+\frac{7}{18}\right)\)
\(=6-\left(\frac{21}{18}+\frac{7}{18}\right)\)
\(=6-\left(\frac{21+7}{18}\right)\)
\(=6-\frac{28}{18}\)
\(=6-\frac{28:2}{18:2}\)
\(=6-\frac{14}{9}\)
\(=\frac{6\times9}{1\times9}-\frac{14}{9}\)
\(=\frac{36}{9}-\frac{14}{9}\)
\(=\frac{54-14}{9}\)
\(=\frac{40}{9}\)
cong hai cái số trong ngoac rồi lấy 6 đổi ra 6'1 trừ đi
\(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot\left(1-\frac{1}{5}\right)=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}=\frac{1\cdot2\cdot3\cdot4}{2\cdot3\cdot4\cdot5}=\frac{1}{5}\)
Mình giải theo kiểu lớp 6 nhá !
=\(33.\left(\frac{34}{15}+\frac{34}{35}+\frac{34}{63}+\frac{34}{99}\right)\)
=\(33.\left[34.\left(\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}\right)\right]\)
=\(33.\left[34.\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right)\right]\)
=\(33.\left[34.\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right).\frac{1}{2}\right]\)
=\(33.\left[34\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right).\frac{1}{2}\right]\)
=\(33.\left[34.\left(\frac{1}{3}-\frac{1}{11}\right).\frac{1}{2}\right]\)
=\(33.\left(34.\frac{8}{33}.\frac{1}{2}\right)\)
=\(33.\frac{136}{33}\)
=\(\frac{33.136}{33}\)(*)
=\(136\)
(Bạn có thể bỏ bước có dấu *)
\(\frac{7}{4}\)x(\(\frac{33}{12}\)+\(\frac{33}{20}\)+\(\frac{33}{30}\)+\(\frac{33}{42}\))
=\(\frac{7}{4}\)x\(\frac{44}{7}\)
=\(\frac{308}{28}\)=11
=4/5x5/6x...x99/100
=4x5x6x...x99/5x6x7x...x100
=4/100=1/25
\(=\left(\frac{57}{42}+\frac{57}{56}+\frac{57}{72}\right)\times18\)
\(=\frac{19}{6}\times18=57\)
= (57/42 +57/56 + 57/72),18
=(1/6.7 +1/7.8 +1/8.9).18.57
=(1/6-1/7 +1/7 -1/8 +1/8-1/9).18.57
=(1/6-1/9) .18 .57
=57.3 - 57.2
=57