194x6x5-10x60x3-68x15

=30x194-30x60-2x34x15

=30x194-30x60-30x34

30x(194-60-34)

=30x100

=3000

194 x 6  x 5 - 10 x 60 x 3 - 68 x 15

= 194 x 30 - 30 x 60 - 34 x 2 x15 

= 194 x 30 - 30 x 60 - 34 x 30

= 30 x ( 194 - 60 - 34 )

= 30 x 100 = 3000

a: \(17,5\cdot4\cdot3\cdot25\)

\(=17,5\cdot3\cdot\left(4\cdot25\right)\)

\(=52,5\cdot100=5250\)

b: \(25,6\cdot7,5+25,6\cdot2,5\)

\(=25,6\left(7,5+2,5\right)\)

\(=25,6\cdot10=256\)

c: \(4,52\cdot12,5-2,5\cdot4,25\)

\(=2,5\left(4,52\cdot5-4,25\right)\)

\(=2,5\cdot18,35=45,875\)

d: \(7,7\cdot9+7,7\)

\(=7,7\left(9+1\right)\)

\(=7,7\cdot10=77\)

a: \(32,4\times7,5+16,2\times2,5\times2-2,4\times10\)

\(=32,4\times7,5+32,4\times2,5-24\)

\(=32,4\times\left(7,5+2,5\right)-24=324-24=300\)

b: \(\left(8,3\times7,9+7,9\times1,7\right)\times\left(25:0,25-0,09\times1000-5:0,5\right)\)

\(=7,9\times\left(8,3+1,7\right)\times\left(100-90-10\right)\)

=0

ai nhanh nhất mình k cho

Bài 1:

\(A=\frac{1}{\left(1+2\right)}+\frac{1}{\left(1+2+3\right)}+\frac{1}{\left(1+2+3+4\right)}\)\(+\frac{1}{\left(1+2+3+4+5\right)}+...+\)\(\frac{1}{\left(1+2+3+...+10\right)}\)

\(A=\frac{1}{3}+\frac{1}{6}+....+\frac{1}{55}\)

\(A=2\left(\frac{1}{6}+\frac{1}{12}+....+\frac{1}{110}\right)\)

\(A=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)\)

\(A=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{10}-\frac{1}{11}\right)\)

\(A=2.\left(\frac{1}{2}-\frac{1}{11}\right)\)

\(A=\frac{9}{11}\)

Bài 2 :

2)  Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15

= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15

Mẫu số =  11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19  + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17  

=  (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x  17 = (1+27+125+729) x 13 x 15 x 17 

\(\Rightarrow A< \frac{\left(1+27+125+729\right)\times11\times13\times15}{\left(1+27+125+729\right)\times13\times15\times17}\)

\(=\frac{11}{17}\)

\(=\frac{1111}{1717}=B\)

Vậy \(A=B\)

1)\(A=\frac{1}{3}+\frac{1}{6}+...+\frac{1}{55}=2\left(\frac{1}{6}+\frac{1}{12}+...+\frac{1}{110}\right)=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{10}-\frac{1}{11}\right)=2.\left(\frac{1}{2}-\frac{1}{11}\right)=\frac{9}{11}\)

2) Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15

= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15

Mẫu số =  11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19  + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 

lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 

=  (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x  17 = (1+27+125+729) x 13 x 15 x 17

=> \(A<\frac{\left(1+27+125+729\right)\times11\times13\times15}{\left(1+27+125+729\right)\times13\times15\times17}=\frac{11}{17}=\frac{1111}{1717}=B\)

Vậy A < B

Lời giải:
a.

$36,5\times 3+36,5\times 5+36,5\times 2=36,5\times (3+5+2)=36,5\times 10=365$

b. Dấu giữa $12,5$ và $0,4$ là gì vậy bạn?

2,5.4+7,5.4=4.(2,5+7,5)=4.10=40

2,5x4+7,5x4

=4x(2,5+7,5)

=4x10

=40

học tốt

0,2468 + 0,08 x 0,4 x 12,5 x 2,5 + 0,7532

= (0,2468 + 0,7532) + (0,08 x 12,5) x (0,4 x 2,5)

= 1 + 1 x 1

= 1 + 1 

= 2

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