75/100+75%.2+3/4.3+0.75.4

=3/4+3/4.2+3/4.3+3/4.4

=3/4.(1+2+3+4)

=3/4.10

=15/2

=75/100+75/100x2+75/100x3 +75/100 x4

=75/100x(1+2+3+4)

= 75/100x10

=15/2

hok tot

Ta có : \(\frac{\left(11,2-10-1,2\right)x\left(3,75-0,75\right)}{2011+3014}=\frac{0x3}{2011+3014}=\frac{0}{2011+3014}=0\)

\(\Rightarrow\left(2000\times7,5+2012:3\right)\times\left(21-3,5\times0,25\right)\times\frac{\left(11,2-10-1,2\right)\times\left(3,75-0,75\right)}{2011+3014}\)

\(=\left(2000\times7,5+2012:3\right)\times\left(21-3,5\times0,25\right)\times0\)

\(=0\)

a) 14,35 x 63+37 x 14,35

= (63+37) x 14,35

= 100 x 14,35 = 1435

b ) 4/3 x 699 x 0,75

= 4/3 x 699 x 3/4

= 4/3 x 3/4 x 699

= 1x699 = 699

 a,   14,35 nhân (37 +63) =1435

A = 3,46 x 0,75 + 96,54 x 0,75

A = ( 3,46 +96,54 ) x 0,75

A = 100 x 0,75

A = 75

Đúng đó

A = (3,46 + 96,54) x 0,75

= 100 x 0,75

= 75

= 0 x 0,001125

= 0

(25% : 0,45 + 50% x 50) x (0,15% - 0,75 x 0,2%)

= (25% : 0,45 + 50% x 50) x(0,15% - 0,15%)

= (25%:0,45 + 50% x 50) x 0

= 0

\(1+\left(1+2\right)+\left(1+2+3\right)+\left(1+2+3+4\right)+...+\left(1+2+3+...+100\right)\)

\(=\left(1+1+1+...+1\right)+\left(2+2+...+2\right)+\left(3+..+3\right)+...+\left(99+99\right)+100\)

( biểu thức trên có 100 số 1, 99 số 2, 98 số 3,...., 2 số 9, 1 số 100)

\(=100\times1+99\times2+98\times3+...+2\times99+1\times100\)

suy ra \(\frac{1+\left(1+2\right)+\left(1+2+3\right)+\left(1+2+3+4\right)+...+\left(1+2+3+...+100\right)}{100\times1+99\times2+98\times3+...+2\times99+1\times100}=1\)

( 48 x 0,75 - 240 : 10 ) - ( 16 x 0,5 - 16 : 4 )

= ( 36 - 24 ) - ( 8 - 4)

= 12 - 4

= 8

Hôm nào tao phô cô giáo mày giám đăng bài lên đây à 

(48×0.75-240:10)-(16×0.5-16:4)

=(36-24)-(8-4)

=12-4

=8 

tk mk nhha bn

ko biết khó quá

=2.45x(46+54)+8x(0.75+0.5)

=2.45x100+8x1.25=2.45x100+10=10x(2.45x10+1)=10x25.5=255