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\(3^2=3\cdot3=9\)
\(4^{10}=4.4.4.4.4.4.4.4.4.4=1048576\)
\(7^4=7\cdot7\cdot7\cdot7=2401\)
\(8^2=8\cdot8=64\)
a) \(2^3=2.2.2=8\)
\(2^4=2.8=16\)
\(2^5=2.16=32\)
\(2^6=2.32=64\)
\(2^7=2.64=128\)
\(2^8=2.128=256\)
\(2^9=2.256=512\)
\(2^{10}=2.512=1024\)
b) \(4^2=4.4=16\)
\(4^3=16.4=64\)
\(4^4=64.4=256\)
Còn lại tương tự
a) \(2^{3+4+5+6+7+8+9+10}=2^{52}\)
b) \(3^{14}\)\(=4782969\)
c) \(4^9\)\(=262144\)
d) \(5^9\)\(=1953125\)
e) \(6^9\)\(=10077696\)
K mk nha, mk nhanh nha
a: \(6^5=6\cdot6\cdot6\cdot6\cdot6=7776\)
\(8^2=8\cdot8=64\)
b: \(2^8=2\cdot2\cdot\ldots\cdot2\) (8 chữ số 2)
=256
\(5^0=1\)
38 = 32 . 32 . 32 . 32
= 9 . 9 . 9 . 9
= 92 . 92
= 81 . 81
= 812
= 6561
24 = 2 . 2 . 2 . 2
= 22 . 22
= 4 . 4
= 42
= 16
4^3^10=4^30=(4^2)^15=..........6^15=...........6
2^2^5=2^10=(2^4)^2 . 2^2=...........6^2 . ...........4=.............4
2^3^4=2^12=(2^4)^3=.............6^3=...............6
3^3^3=3^9=(3^4)^2 . 3=..............1^2 . 3=..............3
9^9^9=9^81=(9^2)^80 . 9=..............1^80 . 9=.................9
\(a,\) \(\left(3^2\right)^3\) = \(3^{2.3}\) = \(3^6\)
\(\left(3^3\right)^2\) = \(3^{3.2}=3^6\)
\(\left(3^2\right)^5\) = \(3^{2.5}=3^{10}\)
\(9^8=\left(3^2\right)^8=3^{2.8}=3^{16}\)
b, \(\left(5^3\right)^2=5^{3.2}=5^6\)
\(\left(5^4\right)^3=5^{4.3}=5^{12}\)
\(\left(5^2\right)^4\) = \(5^{2.4}=5^8\)
\(25^5=\left(5^2\right)^5=5^{2.5}=5^{10}\)
2\(^1\)=2
4\(^2\)= 16
8 = 8
10\(^3\)= 1000
3 = 3
5\(^2\)= 25
7\(^2\)= 49
9\(^2\)= 81
xin thank
học tốt
\(S=2\left(1+2\right)+2^3\left(1+2\right)+...+2^{11}\left(1+2\right)=3\left(2+2^3+...+2^{11}\right)⋮3\)
\(S=2\left(1+2+2^2\right)+...+2^{10}\left(1+2+2^2\right)=7\left(2+...+2^{10}\right)⋮7\)
Vì S chia hết cho 2 và S chia hết cho 3
nên \(S⋮6\)
23 = 2.2.2 = 8;
24 = 2.2.2.2 = 16;
25 = 2.2.2.2.2 = 32;
26 = 2.2.2.2.2.2 = 64;
27 = 26.2 = 64.2 = 128;
28 = 27.2 = 128.2 = 256;
29 = 28 .2 = 256.2 = 512;
210 = 29.2 = 512.2 = 1024.