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\(\frac{3}{4}x^5y^7\) : \(\left[\frac{1}{2}x^2\left(...">
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời. b) \(\frac{4}{x+2}+\frac{3}{x-2}+\frac{5x+2}{4-x^2}\left(x\ne\pm2\right)\) \(=\frac{4}{x+2}+\frac{3}{x-2}-\frac{5x-2}{\left(x-2\right)\left(x+2\right)}\) \(=\frac{4\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}+\frac{3\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}-\frac{5x-2}{\left(x-2\right)\left(x+2\right)}\) \(=\frac{4x-8+3x+6-5x+2}{\left(x-2\right)\left(x+2\right)}\) \(=\frac{2x}{\left(x-2\right)\left(x+2\right)}\) f) \(x^2+1-\frac{x^4-3x^2+2}{x^2-1}\) \(=x^2+1-\frac{\left(x^2-2\right)\left(x^2-1\right)}{\left(x+1\right)\left(x-1\right)}\) \(=x^2+1-\frac{\left(x^2-2\right)\left(x+1\right)\left(x-1\right)}{\left(x+1\right)\left(x-1\right)}\) \(=x^2+1-\left(x^2-2\right)\) \(=x^2+1-x^2+2\) \(=3\) ) \(\dfrac{x^3+8y^3}{2y+x}\) \(=\dfrac{x^3+\left(2y\right)^3}{x+2y}\) \(=\dfrac{\left(x+2y\right)\left[x^2+x.2y+\left(2y\right)^2\right]}{x+2y}\) \(=x^2+2xy+4y^2\) b) \(\dfrac{a-1}{2\left(a-4\right)}+\dfrac{a}{a-4}\) MTC: \(2\left(a-4\right)\) \(=\dfrac{a-1}{2\left(a-4\right)}+\dfrac{2a}{2\left(a-4\right)}\) \(=\dfrac{a-1+2a}{2\left(a-4\right)}\) \(=\dfrac{3a-1}{2\left(a-4\right)}\) c) \(\dfrac{x^3+3x^2y+3xy^2+y^3}{2x+2y}\) \(=\dfrac{\left(x+y\right)^3}{2\left(x+y\right)}\) \(=\dfrac{\left(x+y\right)^2}{2}\) d) \(\left(x-5\right)^2+\left(7-x\right)\left(x+2\right)\) \(=\left(x^2-2.x.5+5^2\right)+\left(7x+14-x^2-2x\right)\) \(=x^2-10x+25+7x+14-x^2-2x\) \(=39-5x\) e) \(\dfrac{3x}{x-2}-\dfrac{2x+1}{2-x}\) \(=\dfrac{3x}{x-2}+\dfrac{2x+1}{x-2}\) \(=\dfrac{3x+2x+1}{x-2}\) \(=\dfrac{5x+1}{x-2}\) h) \(\dfrac{1}{3x-2}-\dfrac{1}{3x+2}-\dfrac{3x+6}{4-9x^2}\) \(=\dfrac{1}{3x-2}-\dfrac{1}{3x+2}+\dfrac{3x+6}{9x^2-4}\) \(=\dfrac{1}{3x-2}-\dfrac{1}{3x+2}+\dfrac{3x+6}{\left(3x-2\right)\left(3x+2\right)}\) MTC: \(\left(3x-2\right)\left(3x+2\right)\) \(=\dfrac{3x+2}{\left(3x-2\right)\left(3x+2\right)}-\dfrac{3x-2}{\left(3x-2\right)\left(3x+2\right)}+\dfrac{3x+6}{\left(3x-2\right)\left(3x+2\right)}\) \(=\dfrac{\left(3x+2\right)-\left(3x-2\right)+\left(3x+6\right)}{\left(3x-2\right)\left(3x+2\right)}\) \(=\dfrac{3x+2-3x+2+3x+6}{\left(3x-2\right)\left(3x+2\right)}\) \(=\dfrac{3x+10}{\left(3x-2\right)\left(3x+2\right)}\) uuuuuuuuuuuuuuuuuuuuuuuuuuuuuu 55555555555555555 666666666666666666666666666 88888888888888888888
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