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Câu 2:
A = 1.3 + 3.5 + 5.7 + ...+ 97.99 + 99.100
A = (1.3 + 3.5 + 5.7 + ...+ 97.99) + 99.100
Đặt B = 1.3 + 3.5 + 5.7 + ...+ 97.99
6B = B = 1.3 + 3.5 + 5.7 + ...+ 97.99
6B = 1.3.6 + 3.5.6 + ...+ 97.99.6
6B = 1.3.(5+1) . 3.5.(7-1) + ..+97.99.(101-95)
6B = 1.3.5 + 1.3.1 +3.5.7- 1.3.5 +...+97.99.101-95.99.97
6B = 1.3.1 + 97.99.101
6B = 3 + 969903
6B = 969906
B = 969906 : 6
B = 161651
A = 161651 + 99.100
A = 161651 + 9900
A = 171551
Câu 3:
A = A = 2.4 + 4.6 + 6.8 +...+ 98.100 + 100.102
6A = 2.4.6 + 4.6.6 +..+98.100.6 + 100.102.6
6A = 2.4.6 + 4.6.(8-2) +...+100.102.(104 - 98)
6A = 2.4.6 + 4.6.8 - 2.4.6 + ...+ 100.102.104 - 98.100.102
6A = 100.102.104
A = 100.102.104 : 6
A = 10200.104 : 6
A = 1060800 : 6
A = 176800
a)\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(3.2\right)^8.2^2.5}=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+3^8.2^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+3^8.2^{10}.5}\)
\(=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}=\frac{-2}{6}=\frac{-1}{3}\)
b) đặt A=2100 - 299 + 298 - 297 +...+ 22 - 2
=>2A=2101-2100+299-298+...+23-22
=>2A+A=2101-2100+299-298+...+23-22+2100 - 299 + 298 - 297 +...+ 22 - 2
=>3A=2101-2
=>A=\(\frac{2^{101}-2}{3}\)
\(1^2+2^2+3^2+...+99^2+100^2\)
\(=1+2\left(1+1\right)+3\left(2+1\right)+99\left(98+1\right)+100\left(99+1\right)\)
\(=1+1.2+2+2.3+3+...+98.99+99+99.100+100\)
\(=\left(1.2+2.3+3.4+...+99.100\right)+\left(1+2+3+...+99+100\right)\)
\(=333300+5050\)
\(=338050\)
Ta có:
\(A=1+2.6+3.6^2+4.6^3+...+100.6^{99}\)
=> \(6A=6+2.6^2+3.6^3+....+99.6^{99}+100.6^{100}\)
=> A - 6A = \(1+6+6^2+6^3+...+6^{99}-100.6^{100}\)
=> \(-5A=1+6+6^2+...+6^{99}-100.6^{100}\)
Đặt: \(B=1+6+6^2+...+6^{99}\)
=> \(6B=6+6^2+6^3+...+6^{100}\)
=> 6 B - B = \(6^{100}-1\)
=> B = \(\frac{6^{100}-1}{5}\)
=> \(-5A=\frac{6^{100}-1}{5}-100.6^{100}\)
=> \(A=\frac{499.6^{100}+1}{25}\)