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\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.2^{30}.3^{18}-2^2.2^{27}.3^{20}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)
=\(\frac{5\cdot2^{30}\cdot3^{18}-2^2\cdot3^{20}\cdot2^{27}}{5\cdot2^9\cdot\left(2\cdot3\right)^{19}-7\cdot2^{29}\cdot3^{18}}\)=\(\frac{5\cdot2^{30}\cdot3^{18}-3^{20}\cdot2^{29}}{5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}\)=\(\frac{2^{29}\cdot3^{18}\cdot\left(5\cdot2-3^2\right)}{2^{28}\cdot3^{18}\left(5\cdot3-7\cdot2\right)}\)=2
Ta có: \(5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9\)
\(=5\cdot2^{30}\cdot3^{18}-2^2\cdot3^{20}\cdot2^{27}\)
\(=5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}\)
\(=2^{29}\cdot3^{18}\left(5\cdot2-3^2\right)=2^{29}\cdot3^{18}\)
Ta có: \(5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6\)
\(=5\cdot2^{10}\cdot2^{19}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}\)
\(=5\cdot2^{29}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}\)
\(=2^{29}\cdot3^{18}\left(5\cdot3-7\right)=2^{32}\cdot3^{18}\)
Ta có: \(\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6}\)
\(=\frac{2^{29}\cdot3^{18}}{2^{32}\cdot3^{18}}=\frac{1}{2^3}=\frac18\)
\(\frac{5.4^{15}.9^8-4.3^{17}.8^9}{5.2^{11}.6^{18}-7.2^{28}.27^6}\)\(=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^8-\left(2^2\right).3^{17}.\left(2^3\right)^9}{5.2^{11}.\left(2.3\right)^{18}-7.2^{28}.\left(3^3\right)^6}\)\(=\frac{5.2^{30}.3^{16}-2^2.3^{17}.2^{27}}{5.2^{11}.2^{18}.3^{18}-7.2^{28}.3^{18}}\)
\(=\frac{5.2^{30}.3^{16}-2^{29}.3^{17}}{5.2^{29}.3^{18}-7.2^{28}.3^{18}}=\frac{2^{28}.3^{16}.\left(5.2^2-2.3\right)}{2^{28}.3^{16}.\left(5.2.3^2-7.3^2\right)}\)
\(=\frac{5.2^2-2.3}{5.2.3^2-7.3^2}=\frac{5.4-6}{5.2.9-7.9}=\frac{20-6}{90-63}\)
\(=\frac{14}{27}\)
\(\frac{5.4^{15}.9^8-4.3^{17}.8^9}{5.2^{11}.6^{18}-7.2^{28}.27^6}=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^8-2^2.3^{17}.\left(2^3\right)^9}{5.2^{11}.\left(2.3\right)^{18}-7.2^{28}.\left(3^3\right)^6}\)\(=\frac{5.2^{30}.3^{16}-2^2.3^{17}.2^{27}}{5.2^{11}.2^{18}.3^{18}-7.2^{28}.3^{18}}=\frac{5.2^{30}.3^{16}-2^{29}.3^{17}}{5.2^{29}.3^{18}-7.2^{28}.3^{18}}\)\(=\frac{2^{29}.3^{16}.\left(5+2-3\right)}{2^{28}.3^{18}.\left(5+2\right)}\)\(=\frac{2.4}{3^2.7}=\frac{8}{63}\)
thế nếu phần tử mà là:.5.4^15.9^8-4-3^13.8^9(giữ nguyên mau) thì sao
giúp luôn hihi
giúp mik đi mừ