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2/7 + 3/5
= 10/35 + 21/35
= 31/35
31/35 - 2/7
= 31/35 - 10/35
= 21/35
= 3/5
31/35 - 2/5
= 31/35 - 14/35
= 17/35
3/5 + 2/7
= 21/35 + 10/35
= 31/35
2/7 + 3/5 = 10/35 + 21/35 = 31/35
31/35 - 2/7 = 31/35 - 10/35 = 21/35
31/35 - 2/5 = 31/35 - 21/35 = 10/35
3/5 + 2/7 = 21/35 + 10/35 = 31/35
\(\frac{6-2}{5}+\frac{3}{5.3}\)
\(=\frac{4}{5}+\frac{1}{5.1}\)
\(=\frac{4}{5}+\frac{1}{5}\)
\(=\frac{5}{5}=1\)
a. 6 x 3 - ( \(\frac{2}{5}+\frac{3}{5}\)) = 6 x 3 - \(\frac{5}{5}\)= 6 x 3 - 1 = 18 - 1 = 17
b.( \(\frac{31}{35}-\frac{4}{7}\)) x \(\frac{8}{7}\): 2 =\(\frac{11}{35}\)x \(\frac{8}{7}\): 2 =\(\frac{88}{245}\): 2 = \(\frac{88}{490}\)= \(\frac{44}{245}\)= ...........rút gọn đến khi hết
a) \(6-\frac{2}{5}+\frac{3}{5}\times3\)
\(=6-\frac{2}{5}+\frac{9}{5}\)
\(=\frac{30}{5}-\frac{2}{5}+\frac{9}{5}\)
\(=\frac{28}{5}+\frac{9}{5}\)
\(=\frac{37}{5}\)
b) \(\left(\frac{31}{35}-\frac{4}{7}\right)\times\frac{8}{7}:2\)
\(=\frac{11}{35}\times\frac{8}{7}:2\)
\(=\frac{88}{245}:2\)
\(=\frac{44}{245}\)
a) \(6-\dfrac{2}{5}+\dfrac{3}{5}\) x \(3\)
\(=6-\dfrac{2}{5}+\dfrac{9}{5}\)
\(=\dfrac{30}{5}-\dfrac{2}{5}+\dfrac{9}{5}\)
\(=\dfrac{30-2+9}{5}=\dfrac{37}{5}\)
b) \(\left(\dfrac{31}{35}-\dfrac{4}{7}\right)\) x \(\dfrac{8}{7}:2\)
\(=\left(\dfrac{31}{35}-\dfrac{20}{35}\right)\) x \(\dfrac{8}{7}:2\)
\(=\dfrac{11}{35}\) x \(\dfrac{8}{7}:2\)
\(=\dfrac{11}{35}\) x \(\dfrac{8}{7}\) x \(\dfrac{1}{2}\)
\(=\dfrac{\text{11 x 8 x 1}}{\text{ 35 x 7 x 2}}=\dfrac{88}{490}=\dfrac{88}{245}\)
a) 6−25+356−25+35 x 33
=6−25+95=6−25+95
=305−25+95=305−25+95
=30−2+95=375=30−2+95=375
b) (3135−47)(3135−47) x 87:287:2
=(3135−2035)=(3135−2035) x 87:287:2
=1135=1135 x 8
a: \(\frac25+\frac12=\frac{4}{10}+\frac{5}{10}=\frac{4+5}{10}=\frac{9}{10}\)
b: \(\frac43-\frac27=\frac{28}{21}-\frac{6}{21}=\frac{28-6}{21}=\frac{22}{21}\)
c: \(\frac{31}{35}-\frac27=\frac{31}{35}-\frac{10}{35}=\frac{31-10}{35}=\frac{21}{35}=\frac35\)
d: \(2-\frac14=\frac84-\frac14=\frac74\)
e: \(\frac45+3=\frac45+\frac{15}{5}=\frac{19}{5}\)
\(6-\frac{2}{5}+\frac{3}{5}\times3\)
\(=\frac{30}{5}-\frac{2}{5}+\frac{9}{5}\)
\(=\frac{30-2+9}{5}\)
\(=\frac{37}{5}\)
\(\left(\frac{31}{35}-\frac{4}{7}\right)\times\frac{8}{7}\div2\)
\(=\left(\frac{31}{35}-\frac{20}{35}\right)\times\frac{8}{14}\)
\(=\frac{11}{35}\times\frac{4}{7}\)
\(=\frac{44}{245}\)
a)\(\dfrac{5}{7}+\dfrac{4}{9}=\dfrac{45}{63}+\dfrac{28}{63}=\dfrac{73}{63}\) ; \(\dfrac{9}{11}+\dfrac{3}{8}=\dfrac{72}{88}+\dfrac{33}{88}=\dfrac{105}{88}\)
\(\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\); \(\dfrac{16}{25}-\dfrac{2}{5}=\dfrac{16}{25}-\dfrac{10}{25}=\dfrac{6}{25}\)
b)\(5+\dfrac{3}{5}=\dfrac{25}{5}+\dfrac{3}{5}=\dfrac{28}{5};10-\dfrac{9}{16}=\dfrac{160}{16}-\dfrac{9}{16}=\dfrac{151}{16}\)
\(\dfrac{2}{3}-\left(\dfrac{1}{6}+\dfrac{1}{8}\right)=\dfrac{2}{3}-\left(\dfrac{8}{48}+\dfrac{6}{48}\right)=\dfrac{2}{3}-\dfrac{14}{48}=\dfrac{32}{48}-\dfrac{14}{48}=\dfrac{3}{8}\)
a,\(\frac{26}{7}\)
b,\(\frac{78}{19}\)
c,\(\frac{13}{11}\)
d,\(1\)
a, \(4-\frac{2}{7}\)=\(\frac{26}{7}\)
b,5-\(\frac{17}{19}=\frac{78}{19}\)
c,\(\frac{35}{11}-2=\frac{13}{11}\)
d,\(\frac{68}{17}-3=1\)
k mình nha
2 7 + 3 5 = 10 35 + 21 35 = 31 35 31 35 - 2 7 = 31 35 - 2 × 5 7 × 5 = 31 35 - 10 35 = 21 35 31 35 - 3 5 = 31 35 - 3 × 7 5 × 7 = 31 35 - 21 35 = 10 35 3 5 + 2 7 ≡ 3 × 7 5 × 7 + 2 × 5 7 × 5 = 21 35 + 10 35 = 31 35