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a)\(y+30\%y=-1,3\Rightarrow y+\frac{3}{10}y=-1,3\Rightarrow y\left(1+\frac{3}{10}\right)=-1,3\Rightarrow y\times1,3\)\(=-1,3\Rightarrow y=-1\)
b)\(y-25\%y=\frac{1}{2}\Rightarrow y-\frac{1}{4}y=\frac{1}{2}\Rightarrow y\left(1-\frac{1}{4}\right)=\frac{1}{2}\Rightarrow y\times\frac{3}{4}=\frac{1}{2}\Rightarrow y=\frac{1}{2}:\frac{3}{4}\Rightarrow y=\frac{2}{3}\)
c)\(3\frac{1}{3}y+16\frac{3}{4}=13,25\Rightarrow\frac{10}{3}y+\frac{67}{4}=\frac{53}{4}\Rightarrow\frac{10}{3}y=\frac{53}{4}-\frac{67}{4}\Rightarrow\frac{10}{3}y=\frac{-7}{2}\Rightarrow y=\frac{-21}{20}\)
a) ta có : y + 30/100y = -1,3
hay y(1+ 3/10) = - 13/10
y.13/10 = -13/10
y= -13/10:13/10
y= -1
b) y - 25/100y=1/2
hay y(1-1/4)=1/2
y.3/4 = 1/2
y=2/3
c) 10/3y + 16,75 = -13,25
10/3y= -13,25 - 16,75
10/3y= -30
y= - 30:10/3
y= -9
y+30%y=-1,3
y+0,3y=-1,3
y.(1+0,3)=-1,3
y.1,3=-1,3
y=-1.3:1.3
y=-1
1, y + 30%y = -1,3
y + 3/10 y = -13/10
y.1 + 3/10 y = -13/10
y.( 1 + 3/10 ) = -13/10
y.13/10 = -13/10
y = -13/10 : 13/10
y = -1
vậy y = -1
2, y - 25%y = 1/2
y - 1/4 y = 1/2
y.1 - 1/4 y = 1/2
y.( 1 - 1/4 ) = 1/2
y.3/4 = 1/2
y = 1/2 : 3/4
y = 2/3
vậy y = 2/3
3, 3 1/3 y + 16 3/4 = -13,25
10/3 y + 67/4 = -53/4
10/3 y = -53/4 - 67/4
10/3 y = -30
y = -30 : 10/3
y = -9
vậy y = -9
các bạn hãy tk cho mk nhé,ko pik kết quả có đúg 100% ko nhưng cách làm đúg đó
a/ <=> y + 0,3y = -1,3
<=> 1,3y = -1,3
<=> y = -1
b/ <=> y - 1/4y = 1/2
<=> 3/4y = 1/2
<=> y = 2/3
c/ <=> 10/3y + 67/4 = -53/4
<=> 10/3y = -30
<=> y = -9
Tìm x mà biến y!
a) y + 30%y = -1,3
<=> 100%y + 30%y = -1,3
<=> 130% y= -1,3
=> y = -1,3: 130% = -1,3 x 100 : 130 = -1
b) ..... <=> 100% y - 25%y = 0,5
<=> 75% y = 0,5 => y = 0,5 : 75% = 0,5x100 : 75 = 2/3
c) ...<=> 10/3y + 16,75 = - 13,25
<=> 10/3y = -13,25 - 16,75
<=> 10/3 y = - 30
=> y = -30 : 10/3 = -9
a) \(y+30\%y=-1.3\)
\(y+\dfrac{3}{10}y=\dfrac{-13}{10}\)
\(y\left(1+\dfrac{3}{10}\right)=\dfrac{-13}{10}\)
\(y\left(\dfrac{10}{10}+\dfrac{3}{10}\right)=\dfrac{-13}{10}\)
\(y\cdot\dfrac{13}{10}=\dfrac{-13}{10}\)
\(y=\dfrac{-13}{10}:\dfrac{13}{10}\)
\(y=\dfrac{-13}{10}\cdot\dfrac{10}{13}\)
\(y=-1\)
Vậy \(y=-1\).
b) \(y-25\%y=\dfrac{1}{2}\)
\(y-\dfrac{1}{4}y=\dfrac{1}{2}\)
\(y\left(1-\dfrac{1}{4}\right)=\dfrac{1}{2}\)
\(y\left(\dfrac{4}{4}-\dfrac{1}{4}\right)=\dfrac{1}{2}\)
\(y\cdot\dfrac{3}{4}=\dfrac{1}{2}\)
\(y=\dfrac{1}{2}:\dfrac{3}{4}\)
\(y=\dfrac{1}{2}\cdot\dfrac{4}{3}\)
\(y=\dfrac{2}{3}\)
Vậy \(y=\dfrac{2}{3}\).
c) \(3\dfrac{1}{3}y+16\dfrac{3}{4}=-13.25\)
\(\dfrac{10}{3}y+\dfrac{67}{4}=\dfrac{-53}{4}\)
\(\dfrac{10}{3}y=\dfrac{-53}{4}-\dfrac{67}{4}\)
\(\dfrac{10}{3}y=-30\)
\(y=-30:\dfrac{10}{3}\)
\(y=-30\cdot\dfrac{3}{10}\)
\(y=-9\)
Vậy \(y=-9\).
a) y+30%y=−1.3y+30%y=−1.3
y+310y=−1310y+310y=−1310
y(1+310)=−1310y(1+310)=−1310
y(1010+310)=−1310y(1010+310)=−1310
y⋅1310=−1310y⋅1310=−1310
y=−1310:1310y=−1310:1310
y=−1310⋅1013y=−1310⋅1013
y=−1y=−1
Vậy y=−1y=−1.
b) y−25%y=12y−25%y=12
y−14y=12y−14y=12
y(1−14)=12y(1−14)=12
y(44−14)=12y(44−14)=12
y⋅34=12y⋅34=12
y=12:34y=12:34
y=12⋅43y=12⋅43
y=23y=23
Vậy y=23y=23.
c) 313y+1634=−13.25313y+1634=−13.25
103y+674=−534103y+674=−534
103y=−534−674103y=−534−674
103y=−30103y=−30
y=−30:103y=−30:103
y=−30⋅310y=−30⋅310
y=−9y=−9
Vậy y=−9y=−9.
a) y-25%y=1/2
y.1-1/4y=1/2
y(1-1/4)=1/2
y.3/4=1/2
y=1/2:3/4
y=1/2.4/3
y=2/3
bài này dễ vl ra sao phải đăng lên hỏi làm j
Mất hết cả tia hi vọng
Dễ mà bn
Vì lười nên không thèm suy nghĩ mà lm lun
a) y+ 30%y = -1,3 b) y- 25% y = 1/2 c) \(3\frac{1}{3}y+16\frac{3}{4}=-13,25\)
y+3/10y = -1,3 y- 1/4y =1/2 \(\frac{10}{3}y+16,75=-13,25\)
13/10 y = -1,3 3/4 y =1/2 \(\frac{10}{3}y=-20\)
y = -1 y = 2/3 \(y=-6\)
k mình đê bạn ơi
:w
a) \(y+30\%.y=-1,3\)
\(y.10+\frac{3}{10}.y.10=-1,3\)
10.y + 3.y = -13.10
13.y = -13
y = -13 : 13
y = -1
=> y = -1
b) \(y-25\%.y=\frac{1}{2}\)
\(y-\frac{1}{4}.y=\frac{1}{2}\)
\(y.4-\frac{1}{4}.y=\frac{1}{2}.4\)
4y - y = 2
3y = 2
y = 2 : 3
\(y=\frac{2}{3}\)
\(\Rightarrow y=\frac{2}{3}\)
c) \(3\frac{1}{3}y+16\frac{3}{4}=-13,25\)
\(\frac{10}{3}.y+\frac{67}{4}=-13,25\)
\(\frac{10}{3}.y=-13,25-\frac{67}{4}\)
\(\frac{10}{3}.y=-30\)
\(y=-30:\left(\frac{10}{3}\right)\)
y = -9
=> y = -9
K hiểu phần nào ib tớ giải thích
\(\text{a) }y+30\%y=-1,3\)
\(\Rightarrow y+\frac{3}{10}y=-\frac{13}{10}\)
\(\Rightarrow y\left(1+\frac{3}{10}\right)=-\frac{13}{10}\)
\(\Rightarrow y.\frac{13}{10}=-\frac{13}{10}\)
\(\Rightarrow y=-1\)
\(\text{b) }y-25\%y=\frac{1}{2}\)
\(\Rightarrow y-\frac{1}{4}y=\frac{1}{2}\)
\(\Rightarrow y\left(1-\frac{1}{4}\right)=\frac{1}{2}\)
\(\Rightarrow y.\frac{3}{4}=\frac{1}{2}\)
\(\Rightarrow y=\frac{2}{3}\)
\(\text{c) }3\frac{1}{3}y+16\frac{3}{4}=-13,25\)
\(\Rightarrow\frac{10}{3}y+\frac{67}{4}=-\frac{1325}{1000}\)
\(\Rightarrow\frac{10}{3}y=-\frac{1325}{1000}-\frac{67}{4}\)
\(\Rightarrow\frac{10}{3}y=-\frac{53}{40}-\frac{67}{4}\)
\(\Rightarrow\frac{10}{3}y=\frac{-723}{40}\)
\(\Rightarrow y=-5,4225\)
câu c tui tính nhầm nha sorry nhiều
sao mỗi người 1 kết quả
câu c bạn sp đúng nha
a)y+30%y =-1,3
y.(30%+1) =-13/10
y.(30/100+1) =-13/10
y.(3/10+1) =-13/10
y.(3/10+10/10) =-13/10
y.13/10 =-13/10
y =-13/10:13/10
y =-1
b)y-25%y =1/2
y.(1-25%) =1/2
y.(1-25/100) =1/2
y.(1-1/4) =1/2
y.3/4 =1/2
y =1/2:3/4
y =1/2.4/3
y =2/3
tớ chỉ giúp cậu được 2 câu đầu thôi
sp : câu c) đúng nha