phamthiminhtrang

\(a,x=\frac{3}{6}-\frac{8}{16}\)

\(\Rightarrow x=0\)

\(b,\frac{12}{16}:x=\frac{32}{64}\)

\(x=\frac{12}{16}:\frac{32}{64}\)

\(x=\frac{12}{16}\cdot\frac{64}{32}\)

\(x=\frac{3}{8}\)

\(a,\)\(x\)\(=\frac{3}{6}-\frac{8}{16}=\frac{1}{2}-\frac{1}{2}=0\)

\(b,\)\(\frac{12}{16}\)\(:\)\(x\)\(=\frac{32}{64}\)

\(=>\)        \(x\)\(=\)\(\frac{12}{16}:\frac{32}{64}\)

                        \(x\) \(=\)\(\frac{12}{16}.\frac{64}{32}\)

                        \(x\)\(=\)\(\frac{3}{4}.2\)

                        \(x\)\(=\)\(\frac{6}{4}=\frac{3}{2}\)

a) \(2^{4x+1}-8^{x+2}=0\)\(\Leftrightarrow2^{4x+1}-2^{3\left(x+2\right)}=0\)

\(\Leftrightarrow2^{4x+1}-2^{3x+6}=0\)\(\Leftrightarrow2^{4x+1}=2^{3x+6}\)

\(\Leftrightarrow4x+1=3x+6\)\(\Leftrightarrow4x-3x=6-1\)\(\Leftrightarrow x=5\)

Vậy \(x=5\)

b) \(3^2.9^{2x}=27^{x+3}\)\(\Leftrightarrow3^2.3^{2.2x}=3^{3\left(x+3\right)}\)\(\Leftrightarrow3^2.3^{4x}=3^{3x+9}\)

\(\Leftrightarrow3^{2+4x}=3^{3x+9}\)\(\Leftrightarrow2+4x=3x+9\)\(\Leftrightarrow4x-3x=9-2\)\(\Leftrightarrow x=7\)

Vậy \(x=7\)

c) \(8^{2x}.64^2=16^{x+4}\)\(\Leftrightarrow2^{3.2x}.2^{6.2}=2^{4\left(x+4\right)}\)\(\Leftrightarrow2^{6x}.2^{12}=2^{4\left(x+4\right)}\)

\(\Leftrightarrow2^{6x+12}=2^{4x+16}\)\(\Leftrightarrow6x+12=4x+16\)\(\Leftrightarrow6x-4x=16-12\)

\(\Leftrightarrow2x=4\)\(\Leftrightarrow x=2\)

Vậy \(x=2\)

a) \(3^{x-2}=27\cdot9\)

\(3^{x-2}=3^3\cdot3^2=3^5\)

\(\Rightarrow\)\(x-2=5\Rightarrow x=7\)

b) \(2^{x+1}+2^{x+3}=80\)

\(\Rightarrow2^{x+1}\left(1+2^2\right)=80\)

\(\Rightarrow2^{x+1}\cdot5=80\)

\(\Rightarrow2^{x+1}=16=2^4\)

\(\Rightarrow x+1=4\Rightarrow x=3\)

c) \(2^{2x-3}=16\cdot8\)

\(2^{2x-3}=2^4\cdot2^3=2^7\)

\(\Rightarrow2x-3=7\)

\(\Rightarrow2x=4\Rightarrow x=2\)

d) \(2^{x-2}\cdot2^x=64\)

\(\Rightarrow2^{x-2+x}=64=2^6\)

\(\Rightarrow x-2+x=6\)

\(\Rightarrow2x-2=6\)

\(\Rightarrow2x=8\Rightarrow x=4\)

Giải:

a) \(3^{x-2}=27.9\)

\(\Leftrightarrow3^{x-2}=3^3.3^2\)

\(\Leftrightarrow3^{x-2}=3^5\)

Vì \(3=3\)

Nên \(x-2=5\)

\(\Leftrightarrow x=5+2\)

\(\Leftrightarrow x=7\)

Vậy x = 7.

b) \(2^{x+1}+2^{x+3}=80\)

\(\Leftrightarrow2^{x+1}\left(1+2^2\right)=80\)

\(\Leftrightarrow2^{x+1}.5=80\)

\(\Leftrightarrow2^{x+1}=\dfrac{80}{5}=16\)

\(\Leftrightarrow2^{x+1}=2^4\)

Vì \(2=2\)

Nên \(x+1=4\)

\(\Leftrightarrow x=4-1\)

\(\Leftrightarrow x=3\)

Vậy x = 3.

c) \(2^{2x-3}=16.8\)

\(\Leftrightarrow2^{2x-3}=2^4.2^3\)

\(\Leftrightarrow2^{2x-3}=2^7\)

Vì \(2=2\)

Nên \(2x-3=7\)

\(\Leftrightarrow2x=7+3=10\)

\(\Leftrightarrow x=\dfrac{10}{2}=5\)

Vậy x = 5.

d) \(2^{x-2}.2^x=64\)

\(2^{2x-2}=2^6\)

Vì \(2=2\)

Nên \(2x-2=6\)

\(\Leftrightarrow2x=6+2=8\)

\(\Leftrightarrow x=\dfrac{8}{2}=4\)

Vậy x = 4.

Chúc bạn học tốt!

a: \(\Leftrightarrow x^3=\dfrac{539}{64}\)

hay \(x=\dfrac{7\sqrt{11}}{4}\)

c: \(\Leftrightarrow2^{2x-1}=2^9\cdot2^2=2^{11}\)

=>2x-1=11

hay x=6

d: \(\Leftrightarrow x^{17}-x=0\)

\(\Leftrightarrow x\left(x-1\right)\left(x+1\right)=0\)

hay \(x\in\left\{0;1;-1\right\}\)

D, x = 1

C, x = 6

màu giải như cái lồnn vậy

Thèo đề bài, ta có:

\(\frac{x^3}{2^3}=\frac{y^3}{4^3}=\frac{z^3}{6^3}=\frac{x}{2}=\frac{y}{4}=\frac{z}{6}=\frac{x^2}{4}=\frac{y^2}{16}=\frac{z^2}{36}=\frac{x^2+y^2+z^2}{4+16+36}=\frac{14}{56}=\frac{1}{4}\)

x ; y ; z thì bạn tự tìm nhé , chắc cái này không khó đâu nhỉ ??

\(\frac{x^3}{8}=\frac{y^3}{64}=\frac{z^3}{216}\Rightarrow\frac{x}{2}=\frac{y}{4}=\frac{z}{6}\Rightarrow\frac{x^2}{4}=\frac{y^2}{16}=\frac{z^2}{36}\) \(=\frac{x^2+y^2+z^2}{4+16+36}=\frac{14}{56}=\frac{1}{4}\)

\(\frac{x}{2}=\frac{1}{4}\Rightarrow x=\frac{1}{2}\)

\(\frac{y}{4}=\frac{1}{4}\Rightarrow y=1\)

\(\frac{z}{6}=\frac{1}{4}\Rightarrow z=\frac{3}{2}\)

a) \(14:\frac{0,4x+0,6}{x}=7\)

\(\frac{0,4x+0,6}{x}=2\)

0,4x + 0,6 = 2.x

2x - 0,4x = 0,6

1,6x = 0,6

x = 0,375

b) \(\left(160\%+\frac{2}{3}x-x\right).12=660\)

\(\left(160\%+\frac{2}{3}x-x\right)=55\)

\(x\left(\frac{2}{3}-1\right)=53,4\)

\(-\frac{1}{3}x=\frac{267}{5}\)

\(x=\frac{267}{5}.\frac{3}{-1}\)

\(x=-160,2\)

c) \(1:\frac{1.2.3.4.....31}{2.2.2.3.2.4.....2.32}=2^x\)

\(1:\frac{1.2.3.4.....31}{2^{31}.2.3.4.....31.2^5}=2^x\)

\(1:\frac{1}{2^{36}}=2^x\)

\(2^{36}=2^x\)

\(x=36\)

a)  ( 2x - 3 )⁶ = 64

      ( 2x - 3 )⁶ = 2⁶

<=> 2x - 3 = 2

            2x = 5

              x = 5/2

Tha lỗi cho mink mink ko biết làm bài này, MINK xin lỗi PHƯƠNG ANH CÔNG CHÚA STELLA

a)\(\frac{3}{4}+\frac{1}{4}:x=-3\)

                \(\frac{1}{4}:x=-3-\frac{3}{4}\)

                 \(\frac{1}{4}:x=\frac{-15}{4}\)

                        \(x=\frac{1}{4}:\frac{-15}{4}\)

                        \(x=\frac{-1}{15}\)

b)         \(\frac{-5}{x}=\frac{20}{28}\)

 \(\Rightarrow\)\(-5:x=\frac{20}{28}\)

                   \(x=-5:\frac{20}{28}\)

                   \(x=-7\)

c)\(\frac{2}{3}x-\frac{1}{2}=\frac{1}{10}\)

   \(\frac{2}{3}x\)          \(=\frac{1}{10}+\frac{1}{2}\)

   \(\frac{2}{3}x\)          \(=\frac{6}{10}\)

        \(x\)          \(=\frac{6}{10}:\frac{2}{3}\)

        \(x\)          \(=\frac{9}{10}\)

d)\(1\frac{2}{9}x+\frac{8}{3}=\frac{-2}{3}\)

   \(1\frac{2}{9}x\)        \(=\frac{-2}{3}-\frac{8}{3}\)

   \(1\frac{2}{9}x\)        \(=\frac{-10}{3}\)

           \(x\)        \(=\frac{-10}{3}:1\frac{2}{9}\)

           \(x\)        \(=\frac{-30}{11}\)

Câu Cuối)\(\frac{x}{2}-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)

\(\Rightarrow\)     \(x:2-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)

              \(x:2-\frac{11}{5}=\frac{448}{392}\)

              \(x:2\)           \(=\frac{448}{392}+\frac{11}{5}\)

              \(x:2\)           \(=\frac{117}{35}\)

              \(x\)               \(=\frac{117}{35}.2\)

              \(x\)               \(=\frac{234}{35}\)

Bạn cho mình 1 .

Chúc bạn học tốt .

đếch giúp!ai bảo câu hỏi của ngọc trả lời ko tử tế cơ!thằng nào ngu như mày thì thằng đó chết nhe răng giống mày!