a)\(\left(\frac{3}{29}-\frac{1}{5}\right)\cdot\frac{29}{3}\)

\(=\left(\frac{3}{29}\cdot\frac{29}{3}\right)-\left(\frac{1}{5}\cdot\frac{29}{3}\right)\)

\(=1-\frac{29}{15}\)

\(=\frac{-14}{15}\)

b)\(\frac{16}{15}\cdot\frac{-5}{14}\cdot\frac{54}{24}\cdot\frac{56}{21}\)

=\(=\frac{16\cdot\left(-5\right)\cdot54\cdot56}{15\cdot14\cdot24\cdot21}\)

\(=\frac{2^4\cdot\left(-5\right)\cdot2\cdot3^3\cdot2^3\cdot7}{3\cdot5\cdot7\cdot2\cdot2^3\cdot3\cdot7}\)

\(=2^4\)

c)\(\frac{37}{7}\cdot\frac{8}{11}+\frac{37}{7}\cdot\frac{5}{11}-\frac{37}{7}\cdot\frac{2}{11}\)

\(=\frac{37}{7}\cdot\left(\frac{8}{11}+\frac{5}{11}-\frac{2}{11}\right)\)

\(=\frac{37}{7}\cdot1\)

\(=\frac{37}{7}\)

Đúng nhớ k nhen!

b)\(-2^4\)nãy mk nhầm

a, \(\frac{17}{y}=\frac{-7}{11}\)

\(\Rightarrow17\cdot11=-7\cdot y\)

\(\Rightarrow187=-7\cdot y\)

\(\Rightarrow\frac{187}{-7}=y\)

b, \(\frac{-8}{3x-1}=\frac{4}{7}\)

\(\Rightarrow\frac{-8}{3x-1}=\frac{-8}{-14}\)

\(\Rightarrow3x-1=-14\)

\(\Rightarrow3x=-14+1\)

\(\Rightarrow3x=-13\)

\(\Rightarrow x=\frac{-13}{3}\)

c, \(\frac{x}{-3}=\frac{-3}{x}\)

\(\Rightarrow x\cdot x=-3\cdot\left(-3\right)\)

\(\Rightarrow x^2=9\)

\(\Rightarrow x^2=\left(\pm3\right)^2\)

\(\Rightarrow x=\pm3\)

d, \(\frac{-4}{y}=\frac{x}{2}\)

\(\Rightarrow-4\cdot2=x\cdot y\)

\(\Rightarrow-8=x\cdot y\)

\(\Rightarrow x;y\inƯ\left(-8\right)=\left\{-1;1;-2;2;-4;4;-8;8\right\}\)

ta có bảng :

a)\(\frac{14}{y}\)\(=\)   \(\frac{-7}{11}\)

\(\Rightarrow\)\(14\cdot11=y\cdot\left(-7\right)\)

                   \(y=\)\(\frac{14\cdot11}{-7}\)

                   \(y=22\)

c) \(\frac{x}{-3}\) =    \(\frac{-3}{x}\)

\(\Rightarrow\) \(x\cdot x=\left(-3\right)\cdot\left(-3\right)\)

\(\Rightarrow\)\(x^2=9\)

\(\Rightarrow\)\(x^2=9\)hoặc  \(x^2=-9\)

\(TH1:\) \(x^2=9\)

     \(\Rightarrow\)\(x=3\)

\(TH2:\)\(x^2=-9\)

     \(\Rightarrow\)\(x=-3\)

|\(\frac32x\) + \(\frac12\)| = |4\(x\) - 1|

\(\left[\begin{array}{l}\frac32x+\frac12=-4x+1\\ \frac32x+\frac12=4x-1\end{array}\right.\)

\(\left[\begin{array}{l}\frac32x+4x=1-\frac12\\ \frac32x-4x=-1-\frac12\end{array}\right.\)

\(\left[\begin{array}{l}\frac{11}{2}x=\frac12\\ -\frac52x=-\frac32\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac12:\frac{11}{2}\\ x=-\frac32:\frac{-5}{2}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac12\times\frac{2}{11}\\ x=-\frac32\times\frac{-2}{5}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{1}{11}\\ x=\frac35\end{array}\right.\)

Vậy \(x\in\) {\(\frac{1}{11};\frac35\)}

|\(\frac54x\) - \(\frac72\)| - |\(\frac58x\) + \(\frac35\)| = 0

|\(\frac54x\) - \(\frac72\)| = |\(\frac58x\) + \(\frac35\)|

\(\left[\begin{array}{l}\frac54x-\frac72=-\frac58x-\frac35\\ \frac54x-\frac72=\frac58x+\frac35\end{array}\right.\)

\(\left[\begin{array}{l}\frac54x+\frac58x=\frac72-\frac35\\ \frac54x-\frac58x=\frac72+\frac35\end{array}\right.\)

\(\left[\begin{array}{l}\frac{15}{8}x=\frac{29}{20}\\ \frac58x=\frac{41}{10}\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{29}{10}:\frac{15}{8}\\ x=\frac{41}{10}:\frac58\end{array}\right.\)

\(\left[\begin{array}{l}x=\frac{116}{75}\\ x=\frac{164}{25}\end{array}\right.\)

Vậy \(x\in\) {\(\frac{116}{75}\); \(\frac{164}{25}\)}

a) \(\frac{9}{20}\)                                                   c) \(\frac{-55}{4}\)                                                                                                                                 

b) \(\frac{116}{75}\)                                                d) \(\frac{-76}{45}\)

đúng hết đấy nhé mình tính kĩ lắm ko sai đâu

       chúc may mắn

\(\frac{x}{2}=\frac{3}{9}\)

\(\Leftrightarrow\frac{x}{2}=\frac{1}{3}\)

\(\Leftrightarrow3x=2\)

\(\Leftrightarrow x=\frac{2}{3}\)

b)  \(\frac{x}{4}=\frac{-15}{12}=\frac{y+4}{16}\)(có lẽ đề như vậy)

\(\Rightarrow\frac{x}{4}=\frac{-15}{12}\)

\(\Rightarrow12x=-60\)

\(\Rightarrow x=-\frac{60}{12}=-5\)

\(\Rightarrow\frac{x}{4}=\frac{y+4}{16}\)

\(\Rightarrow16x=4y+16\)

\(\Rightarrow-80=4y+16\)

\(\Rightarrow4y=-96\)

\(\Rightarrow y=24\)

câu a hoàn toàn tương tự nên bạn làm nốt nhé!

a)Ta có:

\(\frac{y}{35}=-\frac{6}{14}\Rightarrow y=\frac{-6.35}{14}=-15\)

\(\frac{3}{x}=-\frac{15}{35}\Rightarrow x=\frac{3.35}{-15}=-7\)

Vậy: x=-15;y=-7

b)ta có:

\(\frac{x}{4}=-\frac{15}{12}\Rightarrow x=\frac{-15.4}{12}=-5\)

\(-\frac{15}{12}=\frac{y+4}{16}\Rightarrow y+4=\frac{-15.16}{12}=-20\Rightarrow y=-20-4=-24\)

Vậy x=-5; y=-24

Xin các bạn làm dùm mình, mình sẽ k cho bạn làm nhanh nhất

a) \(x+\frac{3}{4}=\frac{-3}{7}\Leftrightarrow x=\frac{-3}{7}-\frac{3}{4}=-\frac{33}{28}\)

b) \(\frac{5}{2}-\left(\frac{3}{2}+x\right)=\frac{7}{4}+\frac{3}{5}=\frac{47}{20}\Rightarrow\frac{3}{2}+x=\frac{5}{2}-\frac{47}{20}=\frac{3}{20}\Rightarrow x=\frac{3}{20}-\frac{3}{2}=-\frac{27}{20}\)

c) \(\frac{3}{7}-\left(\frac{7}{4}-x\right)=\frac{5}{14}\Leftrightarrow\frac{7}{4}-x=\frac{3}{7}-\frac{5}{14}=\frac{1}{14}\Leftrightarrow x=\frac{7}{4}-\frac{1}{14}=\frac{47}{28}\)

d) \(\left[\frac{8}{3}-\left(-x\right)\right]-\left(\frac{-1}{2}\right)=\frac{5}{3}+\frac{1}{6}=\frac{11}{6}\Rightarrow\frac{8}{3}+x+\frac{1}{2}=\frac{11}{6}\)

\(\Rightarrow\frac{8}{3}+x=\frac{11}{6}-\frac{1}{2}=\frac{4}{3}\Rightarrow x=\frac{4}{3}-\frac{8}{3}=-\frac{4}{3}\)

e) \(\frac{3-x}{9}=\frac{4}{3-x}\Leftrightarrow\left(3-x\right)^2=4.9=36\Rightarrow3-x=6\Leftrightarrow x=3-6=-3\)

\(\frac{3}{7}=\frac{y}{21}\Rightarrow y=\frac{3\times21}{7}=9\)

\(\frac{3}{x-5}=\frac{-4}{x+2}\)

\(\Leftrightarrow3.\left(x+2\right)=-4\left(x-5\right)\)

\(\Leftrightarrow3x+6=-4x+20\)

\(\Leftrightarrow3x+4x=20-6\)

\(\Leftrightarrow7x=14\)

\(\Leftrightarrow x=2\)

Cảm ơn