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a, ta có:27:3,6=7,5
=>-2x7,5=15
vậy x cần tìm là 15
b, -0,52:x=\(-\frac{4}{7}\)
\(\frac{-13}{25}\): x=\(\frac{-4}{7}\)
x=\(\frac{-13}{25}:\frac{-4}{7}\)
x=0,91
a)\(\frac{x}{27}=\frac{-2}{3,6}\)
=>x.3,6=27.(-2)
=>x.3,6=-54
=>x=-15
b)-0,52:x=-9,36:16,38
=>-0,52:x=-4/7
=>x=0,91
c)\(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
=>\(2\frac{7}{8}.x=4\frac{1}{4}.1,61\)
=>\(2\frac{7}{8}.x=\frac{2737}{400}\)
=>x=\(\frac{119}{50}\)
a,\(\frac{x}{27}=-\frac{2}{3,6}\)
\(\Leftrightarrow x.3,6=27.-2\)
\(\Leftrightarrow x.3,6=-54\)
\(\Leftrightarrow x=-15\)
b,\(-0,52\div x=-9,36\div16,38\)
\(\Leftrightarrow-0,52\div x=-\frac{4}{7}\)
\(\Leftrightarrow x=\frac{91}{100}\)
c,\(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
\(\Leftrightarrow\frac{4,25}{2,875}=\frac{x}{1,61}\)
\(\Leftrightarrow x.2,875=4,25.1,61\)
\(\Leftrightarrow x.2,875=6,8425\)
\(\Leftrightarrow x=2,38\)
\(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
\(\Leftrightarrow\frac{\frac{17}{4}}{\frac{23}{8}}=\frac{x}{1,61}\)
\(\Leftrightarrow\frac{34}{23}=\frac{x}{1,61}\)
\(\Leftrightarrow x=\frac{34}{23}.1,61\)
\(\Leftrightarrow x=\frac{119}{50}\)
a) - 0,52 : x = - 9,36 : 16,38
- 0,52 : x = \(-\frac{4}{7}\)
\(x=\left(-0,52\right):\left(-\frac{4}{7}\right)=\frac{91}{100}=0,91\)
b) \(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
\(\frac{\frac{17}{4}}{\frac{23}{8}}=\frac{x}{1,61}\)
\(\frac{x}{1,61}=\frac{34}{23}\)
\(x=\frac{34}{23}.1,61=2,38\)
\(\frac{x}{27}=-\frac{2}{3,6}\)
\(x=\frac{-2\times27}{3,6}\)
\(x=-15\)
***
\(\frac{-0,52}{x}=\frac{-9,36}{16,38}\)
\(x=\frac{-0,52\times16,38}{-9,36}\)
\(x=0,91\)
***
\(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
\(\frac{4,25}{2,875}=\frac{x}{1,61}\)
\(x=\frac{4,25\times1,61}{2,875}\)
\(x=2,38\)
\(a.\)
\(\frac{x}{27}=\frac{-2}{3,6}\)
\(\Rightarrow x=\frac{\left(-2\right).27}{3,6}\)
\(\Rightarrow x=\frac{-54}{3,6}\)
\(\Rightarrow x=-15\)
Vậy : \(x=-15\)
\(b.\)
\(-0,52:x=-9,36:16,38\)
\(\Rightarrow\frac{-0,52}{x}=-\frac{4}{7}\)
\(\Rightarrow x=\frac{-0,52.7}{-4}\)
\(\Rightarrow x=0,91\)
Vậy : \(x=0,91\)
\(c.\)
\(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)
\(\Rightarrow\frac{\frac{17}{4}}{\frac{23}{8}}=\frac{x}{1,61}\)
\(\Rightarrow\frac{17}{4}.\frac{8}{23}=\frac{x}{1,61}\)
\(\Rightarrow\frac{34}{23}=\frac{x}{1,61}\)
\(\Rightarrow x=\frac{1,61.34}{23}\)
\(\Rightarrow x=\frac{119}{50}\)
Vậy : \(x=\frac{119}{50}\)
Bài 1a:
\(\frac{4,6}{1,4}\) = \(\frac{11,5}{5x}\)
4,6 x 5\(x\) = 11,5 x 1,4
23\(x\) = 16,1
\(x\) = 16,1 : 23
\(x\) = 0,7
Vậy \(x\) = 0,7
Bài 1b:
\(\frac{x^2}{6}\) = \(\frac{24}{25}\)
25\(x^2\) = 24.6
25\(x^2\) = 144
\(x^2\) = 144/25
\(x\) = - 12/5 hoặc \(x\) = 12/5
Vậy \(x\) ∈ {-12/5; 12/5}
Bài 1c:
\(\frac{x+2}{2}\) = \(\frac{1}{1-x}\)
(\(x\) + 2)(1 - \(x\)) = 1.2
\(x\) - \(x^2\) + 2 - 2\(x\) = 2
\(x^2\) + (2\(x\) - \(x\)) + 2 - 2 = 0
\(x^2\) + \(x\) + 0 = 0
\(x\)(\(x\) + 1) = 0
\(x\) = 0
\(x\) + 1 = 0
\(x\) = - 1
Vậy \(x\) ∈ {-1; 0}
a) \(\frac{x}{27}=\frac{-2}{3,6}\Leftrightarrow x=\frac{-2.27}{3,6}=-15\)
b) \(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\Leftrightarrow\frac{4,25}{2,875}=\frac{x}{1,61}\Leftrightarrow x=\frac{4,25.1,61}{2,875}=2,38\)
a) \(\frac{x}{27}=-\frac{2}{3,6}\Rightarrow x=\frac{-2.27}{3,6}=-15\)
b) \(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\Rightarrow\frac{\frac{17}{4}}{\frac{23}{8}}=\frac{x}{1,61}\Leftrightarrow\frac{17}{4}\cdot\frac{8}{23}=\frac{x}{1,61}\)
\(\frac{34}{23}=\frac{x}{1,61}\Rightarrow x=\frac{1,61.34}{23}=2,38\)