a,  4^x + 13 =29

      4^x = 29 - 13

      4^x = 16

      4^x = 4²

=> x = 2

a) x+2²= 4¹⁰:4⁸

    x+2²= 4²

    x+4  = 16

    x      =16-4

    x      =12

b) 33-x= 2².5

    33-x= 4.5

    33-x= 20

         x= 33-20

         x= 13

x+2^2=2^2.10:2^2.8

<=>x+2^2=2^20:2^16

<=>x+2^2=2^4

<=>x=2^4-2^2=12

b) 33-x=2^2.5=20

<=> x = 33-20 = 13

* = 1 ; 2 ; 3 ; 4 5 ; 6 ; 7 ; 8 ; 9 ; 0 

  b/ 120 - x : 4 = 3⁴ : 3¹¹ 

      120 - x : 4 = 3⁷

       120 - x : 4 = 2187 

                x : 4 = 120 - 2187 

               x : 4 = -2067 

              => x = -8268

a) 3*2 có tận cùng là 2 nên chia hết cho 2

vậy * = 0;1;2 ... 9

b) 120 - x : 4 = \(3^4:3^{11}\)

  120  - x : 4 = \(-\left(3^7\right)\)

x : 4 = 120 - \(\left[-\left(3^7\right)\right]\)

x : 4 = 2307

x = 2307 x 4

x = 9228

cau nay kho qua bang a

A=5+5²+5³+...+5¹⁰⁰ = (5+5²)+(5³+5⁴)+...+(5⁹⁹+5¹⁰⁰)

A=(5+5²)+5².(5+5²)+5⁴.(5+5²)+...+5⁹⁸.(5+5²)

A=30+30.5²+30.5⁴+...+30.5⁹⁸ = 30.(1+5²+5⁴+...+5⁹⁸)\(⋮\)30

=>A\(⋮\)6

a) 740:(x+10)=10²-2x13

=>740:(x+10)=100-2x13

=>740:(x+10)=1274

=>x=10,5808477237048(6)
6 là chu kì (có nghĩa là 6soos 6 kéo dài mãi mãi không giới hạn)
 

A =118.75

B=125 -5 .(3.X -1) =25

5.(3.X-1) =100

3.X-1=20

3X =21

X=7

Câu a:

(x - 5)^2 - 2x - 2^4 = 2x

(x - 5)(x - 5) - 2x - 16 - 2x = 0

x^2 - 5x - 5x + 25 - 2x - 16 - 2x = 0

x^2 - (5x + 5x +2x + 2x) + (25 - 16) = 0

x^2 - 14x + 9 = 0

(x^2 - 7x) - (7x - 49) - 40 = 0

x(x - 7) - 7(x - 7) - 40 = 0

(x - 7)(x - 7) - 40 = 0

(x - 7)^2 = 40

x - 7 = \(\sqrt{40}\) hoặc x - 7 = -\(\sqrt{40}\)

x - 7 = - \(\sqrt{40}\)

x = 7 - \(\sqrt{40}\)

x - 7 = \(\sqrt{40}\)

x = 7+ \(\sqrt{40}\)

Vậy x ∈ {7 - \(\sqrt{40}\) ; 7+ \(\sqrt{40}\))

Câu b:

3^(x -1) - 7^2 = 2^5 + 0^3

3^(x -1) - 49 = 32 + 0

3^(x - 1) - 49 = 32

3^(x -1) = 32 + 49

3^(x -1) = 81

3^(x-1) = 3^4

x - 1 = 4

x = 4 + 1

x = 5

Vậy x = 5