\(7\frac{5}{6}\)- x = 9
b, 25%x + 2x = 4,5
c, ( x - Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời. a)\(\frac{1}{4}x+2x=\frac{9}{2}\) \(x.\left(\frac{1}{4}+2\right)=\frac{9}{2}\) \(x.\frac{9}{4}=\frac{9}{2}\) x\(=\frac{9}{2}:\frac{9}{4}\) \(x=2\) b)x=2 và x =(-1) c)x=4 a. 25%x +2x=4,5 0,25x +2x =4,5 (0,25+2)x=4,5 2,25 x=4,5 x=4,5:2,25 x=2 |\(\frac32x\) + \(\frac12\)| = |4\(x\) - 1| \(\left[\begin{array}{l}\frac32x+\frac12=-4x+1\\ \frac32x+\frac12=4x-1\end{array}\right.\) \(\left[\begin{array}{l}\frac32x+4x=1-\frac12\\ \frac32x-4x=-1-\frac12\end{array}\right.\) \(\left[\begin{array}{l}\frac{11}{2}x=\frac12\\ -\frac52x=-\frac32\end{array}\right.\) \(\left[\begin{array}{l}x=\frac12:\frac{11}{2}\\ x=-\frac32:\frac{-5}{2}\end{array}\right.\) \(\left[\begin{array}{l}x=\frac12\times\frac{2}{11}\\ x=-\frac32\times\frac{-2}{5}\end{array}\right.\) \(\left[\begin{array}{l}x=\frac{1}{11}\\ x=\frac35\end{array}\right.\) Vậy \(x\in\) {\(\frac{1}{11};\frac35\)} |\(\frac54x\) - \(\frac72\)| - |\(\frac58x\) + \(\frac35\)| = 0 |\(\frac54x\) - \(\frac72\)| = |\(\frac58x\) + \(\frac35\)| \(\left[\begin{array}{l}\frac54x-\frac72=-\frac58x-\frac35\\ \frac54x-\frac72=\frac58x+\frac35\end{array}\right.\) \(\left[\begin{array}{l}\frac54x+\frac58x=\frac72-\frac35\\ \frac54x-\frac58x=\frac72+\frac35\end{array}\right.\) \(\left[\begin{array}{l}\frac{15}{8}x=\frac{29}{20}\\ \frac58x=\frac{41}{10}\end{array}\right.\) \(\left[\begin{array}{l}x=\frac{29}{10}:\frac{15}{8}\\ x=\frac{41}{10}:\frac58\end{array}\right.\) \(\left[\begin{array}{l}x=\frac{116}{75}\\ x=\frac{164}{25}\end{array}\right.\) Vậy \(x\in\) {\(\frac{116}{75}\); \(\frac{164}{25}\)} a) \(\frac{9}{20}\) c) \(\frac{-55}{4}\) b) \(\frac{116}{75}\) d) \(\frac{-76}{45}\) đúng hết đấy nhé mình tính kĩ lắm ko sai đâu chúc may mắn a \(5\frac{4}{7}:x+=13\) \(\frac{39}{7}:x=13\) \(x=\frac{39}{7}:13\) \(x=\frac{3}{7}\) \(\frac{4}{7}x=\frac{9}{8}-0,125\) \(\frac{4}{7}x=1\) \(x=1:\frac{4}{7}\) \(x=\frac{7}{4}=1\frac{3}{4}\) a) \(\left(4,5-2x\right)\cdot1\frac{4}{7}=\frac{11}{7}\) \(\left(\frac{9}{2}-2x\right)\cdot\frac{11}{7}=\frac{11}{7}\) \(\left(\frac{9}{2}-2x\right)=\frac{11}{7}\div\frac{11}{7}\) \(\left(\frac{9}{2}-2x\right)=1\) \(2x=\frac{9}{2}-1\) \(x=\frac{7}{2}\div2\) \(x=\frac{7}{4}\) b) \(|\frac{3}{4}\cdot x-\frac{1}{2}|-1=\frac{1}{4}\) \(|\frac{3}{4}\cdot x-\frac{1}{2}|=\frac{1}{4}+1\) \(|\frac{3}{4}\cdot x|=\frac{5}{4}+\frac{1}{2}\) \(x=\frac{7}{4}\div\frac{3}{4}\) \(x=\frac{7}{3}\) c) \(\frac{1}{4}-|3-x|=-\frac{3}{4}\) \(|3-x|=\frac{1}{4}-\left(-\frac{3}{4}\right)\) \(|3-x|=1\) \(x=3-1\) \(\Rightarrow x=2\) d) \(4\cdot\left(x-\frac{6}{7}\right)-\frac{3}{5}=1,4\) \(4\cdot\left(x-\frac{6}{7}\right)-\frac{3}{5}=\frac{7}{5}\) \(4\cdot\left(x-\frac{6}{7}\right)=\frac{7}{5}+\frac{3}{5}\) \(4\cdot\left(x-\frac{6}{7}\right)=2\) \(\left(x-\frac{6}{7}\right)=2\div4\) \(x=\frac{1}{2}+\frac{6}{7}\) \(x=\frac{19}{14}\) \(\) \(a,2\frac{x}{7}=\frac{75}{35}\) \(\frac{75}{35}=2\frac{5}{35}=2\frac{1}{7}\) \(\Rightarrow x=1\) \(b,47:4=...\left(+3\right)\) \(\Rightarrow\left(47-3\right):4=11\) \(\Rightarrow x=11\) \(c,\frac{112}{5}=\frac{336}{15}=22\left(+6\right)\) \(\Rightarrow x=22\frac{x=6}{15}\) \(d,7,5x=\frac{75x}{100}:\left(9-6\frac{13}{21}\right)=2\frac{13}{25}\) \(\frac{75x}{100}:\left(9-\frac{139}{21}\right)=\frac{63}{25}\) \(\frac{75x}{100}:\frac{50}{21}=\frac{63}{25}\) \(\Rightarrow\frac{63^3}{25^{\left(1\right)}}\cdot\frac{50^{\left(2\right)}}{21^1}=6=\frac{6}{1}\) \(\Rightarrow\frac{6}{1}=\frac{600}{100}\) Con d sai đề a) = 3/3 x ( -24/54 +45/54 ) : 7/12 = 1 x 21/54 x 12/7 = 18/27 ( hiện tại mik chỉ lm đc thế này thui. thông cảm nk ) S = \(\frac12\times\frac13\) + \(\frac13\times\frac14\) + \(\frac14\times\frac15\) + \(\frac15\times\frac16\) + \(\frac17\times\frac18\) + \(\frac18\times\frac19\) S = \(\frac12\) - \(\frac13\) + \(\frac13\) - \(\frac14\) + \(\frac14\) - \(\frac15\) + \(\frac15\) - \(\frac16\) + \(\frac17\) - \(\frac18\) + \(\frac18\) - \(\frac19\) S = \(\frac12\) - \(\frac19\) S = \(\frac{9}{18}-\frac{2}{18}\) S = \(\frac{7}{18}\) \(\frac{x}{-7}=\frac{5}{-35}\) \(\frac{x.5}{-35}=\frac{5}{-35}\) => x . 5 = 5 x = 5 : 5 x = 1 \(\frac{6}{11}x=\frac{9}{2}y=\frac{18}{5}z\Rightarrow\frac{6x}{11.18}=\frac{9y}{2.18}=\frac{18z}{5.18}\) \(\Rightarrow\frac{-x}{-33}=\frac{y}{4}=\frac{z}{5}=\frac{-x+y+z}{-33+4+5}=\frac{-120}{-24}=5\) \(\Rightarrow x=165;y=20;z=25\)