Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Câu a:
2.(x + 2/5) + 1 1 /4 = 11/20
2x + 4/5 + 5/4 = 11/20
2x = 11/20 - 5/4 - 4/5
2x = 11/20 - 25/20 - 16/20
2x = -30/20
2x = -3/2
x = -3/2 : 2
x = - 3/4
Vậy x = - 3/4
Câu b:
x - 1 1/8 - 2/3x - 5/6x = 75%
(x - 2/3x - 5/6x) = 75% + 1 1/8
x (1 - 2/3 - 5/6) = 3/4 + 9/8
x (6/6 - 4/6 - 5/6) = 6/8 + 9/8
x.(-1/2) = 15/8
x = 15/8 : (-1/2)
x = 15/8 x (-2)
= -15/4
a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)
\(x+\frac{2}{5}=\frac{-7}{20}\)
\(x=\frac{-13}{20}\)
Vậy \(x=\frac{-13}{20}\)
b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)
\(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x=\frac{15}{8}\)
\(x=\frac{-15}{4}\)
Vậy \(x=\frac{-15}{4}\)
Câu a:
x - 1: 4/3 + 9/16 = - 5^2/4^2
x - 1 x 3/4 + 9/16 = - 25/16
x - 3/4 + 9/16 = - 25/16
x - 3/4 = -25/16 - 9/16
x - 3/4 = -17/8
x = - 17/8 + 3/4
x = -11/8
Vậy x = -11/8
Câu b:
5/2x + 2 - 3 1/2 = 1/6
5/2x + 2 - 7/2 = 1/6
5/2x = 1/6 + 7/2 - 2
5/2x = 1/6 + 21/6 - 12/6
5/2x = 5/3
x = 5/3 : 5/2
x = 2/3
Câu a:
1 1/3 + 2/3x = 5 1/3
2/3x = 5 1/3 - 1 1/3
2/3x = 4
x = 4 : 2/3
x = 4 x 3/2
x = 6
Vậy x = 6
a, x-1:4/3+9/16=-5^(^laf mũ)2/4^2
x-1:4/3+9/16=25/16
x-1:4/3=25/16-9/16
x-1:4/3=1
x-1=1.4/3
x-1=4/3
x=4/3+1
x=7/3
kl:...................(hì tự viết nha mik lười viết)
b, 5/2x+2-31/2=1/6
5/2x+2=1/6+31/2
5/2x+2=16
5/2x=16-2
5/2x=14
x=14:5/2
x=28/5(vì 28 ko chia hết cho 5 nên mik viết như vậy)
*chúc bn học tốt nha* ^-^ *_*
\(\frac{6}{11}\cdot\frac{3}{14}+\frac{-5}{16}+\frac{3}{14}\cdot\frac{5}{11}+\frac{-3}{16}\)
\(=\frac{6}{11}\cdot\frac{3}{14}+\frac{3}{14}\cdot\frac{5}{11}+\frac{-5}{16}+\frac{-3}{16}\)
\(=\frac{3}{14}\cdot\left(\frac{6}{11}+\frac{5}{11}\right)+\left(\frac{-5}{16}+\frac{-3}{16}\right)\)
\(=\frac{3}{14}\cdot\frac{6+5}{11}+\frac{-5+\left(-3\right)}{16}\)
\(=\frac{3}{14}\cdot\frac{11}{11}+\frac{-8}{16}\)
\(=\frac{3}{14}\cdot1+\frac{-1}{2}\)
\(=\frac{3}{14}+\frac{-1}{2}\)
\(=\frac{3}{14}+\frac{-7}{14}\)
\(=\frac{3+\left(-7\right)}{14}\)\(=\frac{-4}{14}=\frac{-2}{7}\)
\(\frac{-5}{6}+\left(7x-\frac{1}{2}\right)\cdot\frac{2}{9}=-1\frac{1}{3}\)
\(\frac{-5}{6}+\frac{14}{9}\cdot x-\frac{1}{9}=-\frac{4}{3}\)
\(\frac{14}{9}\cdot x-\frac{1}{9}=-\frac{4}{3}+\frac{5}{6}\)
\(\frac{14}{9}\cdot x-\frac{1}{9}=-\frac{1}{2}\)
\(\frac{14}{9}\cdot x=-\frac{1}{2}+\frac{1}{9}\)
\(\frac{14}{9}\cdot x=-\frac{7}{18}\)
\(x=-\frac{7}{18}:\frac{14}{9}\)
\(x=-\frac{1}{4}\)
a) | x - 3 | - ( -3 ) = 4
| x - 3 | = 4 + ( -3 )
| x - 3 | = 1
=> x - 3 = -1 => x = ( -1 ) + 3 = -2
hoặc x - 3 = 1 => x = 1 + 3 = 4
vậy x = 1 hoặc x = 4
\(a)\left(3\frac{1}{2}-x\right).1\frac{1}{4}=\frac{15}{6}\)
\(\left(\frac{7}{2}-x\right).\frac{5}{4}=\frac{15}{6}\)
\(\frac{7}{2}-x=\frac{15}{6}:\frac{5}{4}\)
\(\frac{7}{2}-x=2\)
\(x=\frac{7}{2}-2\)
\(\Rightarrow x=\frac{3}{2}\)
\(\left(x+\frac{1}{3}\right)\left(\frac{3}{4}-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{3}=0\\\frac{3}{4}-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{3}\\x=\frac{3}{8}\end{cases}}\)
Vậy \(x\in\left\{\frac{-1}{2};\frac{3}{8}\right\}\)
Làm đầy đủ hộ mình đi được k bạn
\(a,1\frac{1}{3}+\frac{2}{3}x=5\frac{1}{3}\)
\(\Rightarrow\frac{4}{3}+\frac{2}{3}x=\frac{16}{3}\)
\(\Rightarrow\frac{2}{3}x=\frac{16}{3}-\frac{4}{3}\)
\(\Rightarrow\frac{2}{3}x=4\)
\(\Rightarrow x=4:\frac{2}{3}=4.\frac{3}{2}=6\)
Vậy x=6
\(b,\left(x+\frac{1}{3}\right)\left(\frac{3}{4}-2x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{1}{3}=0\\\frac{3}{4}-2x=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=\frac{-1}{3}\\-2x=\frac{3}{4}\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=\frac{-1}{3}\\x=\frac{-3}{8}\end{cases}}\)
Vậy.................
\(c,\frac{-4}{5}x+1\frac{1}{3}x=-1\frac{1}{3}\)
\(\Rightarrow\frac{-4}{5}x+\frac{4}{3}x=\frac{-4}{3}\)
\(\Rightarrow\frac{-2}{3}x=\frac{-4}{3}\)
\(\Rightarrow x=\frac{-4}{3}:\frac{-2}{3}=\frac{-4}{3}.\frac{3}{-2}=2\)
Vậy x=2
a) \(1\frac{1}{3}+\frac{2}{3}.x=5\frac{1}{3}\)
=> \(\frac{4}{3}+\frac{2}{3}x=\frac{16}{3}\)=> \(\frac{2}{3}x=\frac{16}{3}-\frac{4}{3}=4\)
=> \(x=4:\frac{2}{3}\)=6
vậy x=6
b) \(\left(x+\frac{1}{3}\right)\left(\frac{3}{4}-2x\right)=0\)
=> \(\orbr{\begin{cases}x+\frac{1}{3}=0\\\frac{3}{4}-2x=0\end{cases}}\)=> \(\orbr{\begin{cases}x=0-\frac{1}{3}\\2x=\frac{3}{4}\end{cases}}\)=> \(\orbr{\begin{cases}x=\frac{-1}{3}\\x=\frac{3}{8}\end{cases}}\)
vậy \(x=\frac{-1}{3}\)hoặc x=\(\frac{3}{8}\)
c) \(\frac{-4}{5}x+1\frac{1}{3}x=-1\frac{1}{3}\)
=> \(\frac{-4}{5}x+\frac{4}{3}x=\frac{-4}{3}\)
=> \(x\left(\frac{-4}{5}+\frac{4}{3}\right)=\frac{-4}{3}\)=> \(x\left(\frac{-12}{15}+\frac{20}{15}\right)=\frac{-4}{3}\)
=> \(x.\frac{8}{15}=\frac{-4}{3}\)=> \(x=\frac{-4}{3}:\frac{8}{15}\)=> x=\(\frac{-4}{3}.\frac{15}{8}=\frac{-5}{2}\)
vậy x = \(\frac{-5}{2}\)