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a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)
\(x+\frac{2}{5}=\frac{-7}{20}\)
\(x=\frac{-13}{20}\)
Vậy \(x=\frac{-13}{20}\)
b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)
\(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x=\frac{15}{8}\)
\(x=\frac{-15}{4}\)
Vậy \(x=\frac{-15}{4}\)
Câu a:
x - 1: 4/3 + 9/16 = - 5^2/4^2
x - 1 x 3/4 + 9/16 = - 25/16
x - 3/4 + 9/16 = - 25/16
x - 3/4 = -25/16 - 9/16
x - 3/4 = -17/8
x = - 17/8 + 3/4
x = -11/8
Vậy x = -11/8
Câu b:
5/2x + 2 - 3 1/2 = 1/6
5/2x + 2 - 7/2 = 1/6
5/2x = 1/6 + 7/2 - 2
5/2x = 1/6 + 21/6 - 12/6
5/2x = 5/3
x = 5/3 : 5/2
x = 2/3
a, x-1:4/3+9/16=-5^(^laf mũ)2/4^2
x-1:4/3+9/16=25/16
x-1:4/3=25/16-9/16
x-1:4/3=1
x-1=1.4/3
x-1=4/3
x=4/3+1
x=7/3
kl:...................(hì tự viết nha mik lười viết)
b, 5/2x+2-31/2=1/6
5/2x+2=1/6+31/2
5/2x+2=16
5/2x=16-2
5/2x=14
x=14:5/2
x=28/5(vì 28 ko chia hết cho 5 nên mik viết như vậy)
*chúc bn học tốt nha* ^-^ *_*
Bài 2a:
Tìm x
5/3x + 2/3 = 1/4
5/3x = 1/4 - 2/3
5/3x = 3/12 - 8/12
5/3x = - 5/12
x = -5/12 : 5/3
x = -5/12 x 3/5
x = - 1/4
Vậy x = -1/ 4
a,5mũ 36=(5mũ3)mũ12=125 mũ12
11^24=(11^2)12=121^12
vì 121<125 nên 5^36>11^24
A . 89 - ( 73 - x ) = 20
73 - x = 89 - 20
73 - x = 69
\(\Rightarrow\)x = 4
B .
Câu a:
7/10.4/9 + 3/10.4/9 - 1 7/9
= 4/9.(7/10 + 3/10) - 16/9
= 4/9 - 16/9
= - 12/9
= - 4/3
Câu b:
- 5/6 + 4/9.(5/4 - 2/3).(-3)^2 + 5/9.30%
= - 5/6 + [5/9 - 8/27].9 + 5/9.3/10
= - 5/6 + 5 - 8/3 + 1/6
= (-5/6 + 1/6) - 8/3 + 5
= - 4/6 - 8/3 + 15/3
= - 2/3 - 8/3 + 15/3
= - 10/3 + 15/3
= 5/3
Câu a:
2.(x + 2/5) + 1 1 /4 = 11/20
2x + 4/5 + 5/4 = 11/20
2x = 11/20 - 5/4 - 4/5
2x = 11/20 - 25/20 - 16/20
2x = -30/20
2x = -3/2
x = -3/2 : 2
x = - 3/4
Vậy x = - 3/4
Câu b:
x - 1 1/8 - 2/3x - 5/6x = 75%
(x - 2/3x - 5/6x) = 75% + 1 1/8
x (1 - 2/3 - 5/6) = 3/4 + 9/8
x (6/6 - 4/6 - 5/6) = 6/8 + 9/8
x.(-1/2) = 15/8
x = 15/8 : (-1/2)
x = 15/8 x (-2)
= -15/4
Câu c:
(3/4 + |x - 7/2|).(16/25 = [(-2)^4]^0 - (3/5)^2
(3/4 + |x - 7/2|).16/25 = 1 - 9/25
(3/4 + |x - 7/2|).16/25 = 16/25
3/4 + |x - 7/2| = 16/25 : 16/25
3/4 + |x - 7/2| = 1
|x - 7/2| = 1 - 3/4
|x - 7/2| = 1/4
x - 7/2 = -1/4 hoặc x - 7/2 = 1/4
x - 7/2 = -1/4
x = - 1/4 + 7/2
x = -1/4 + 14/4
x = 13/4
x - 7/2 = 1/4
x = 1/4 + 7/2
x = 1/4 + 14/4
x = 15/4
Vậy x ∈ {13/4; 15/4}