tui đang cần gấp ai trả lời nhanh tui sẽ kick cho

1) a) -8 + 19 = 11

b) (-17) : (-3) = \(\frac{17}{3}\)

c) 4 - (-13) = 17

2) a) -9 - 13 - (-24) + 11 = 13

b) 323 - 6\([3-7.\left(-9\right)]\)= -73

c) (-3)⁵ : (-3)³ - 9 =0

d) (-8).16 - 13.8 = -232

3) a) -15 : x = 3

         x = 3.(-15) = -45

b) -3x + 8 = -7

    -3x = -15

    x = 5

c) (x - 6).(7 - x) =0

=> x - 6 = 0                         hoặc 7 - x = 0

     x = 6                                          x = 7

~ Học tốt ~

Bài 1:

a) -8+19=11                          

b) (-27):(-3)=9

c) 4-(-13)=17

Bài 2:

a) -19-13-(-24)+11=13

b) 323-6[3-7.(-9)]=-73

c) (-3)⁵:(-3)³-9=0

d) (-8).16-13.8=-232

Bài 3:

a) -15:x=3

     x=3.(-15)

     x=-45

b)-3x+8=-7

     -3x=(-7)-8

     -3x=-15

        x=(-15):(-3)=5

c) (x-6).(7-x)=0

     =>x-6=0             hoặc                7-x=0

          x=6                                         x=7        

         x=6     

1) x - 36 + 12 = - x+ 10

=> x + x  = 10 + 24

=> 2x = 34

=> x = 34/2 = 17

2) (x + 15) - (11 - x) = (-2)²

=> x + 15 - 11 + x = 4

=> 2x = 4 - 4

=> 2x = 0

=> x = 0

3) 40 - 4x² = (-6)²

=> 40 -  4x² = 36

=> 4x² = 40 - 36

=> 4x² = 4

=> x² = 1

=> x = \(\pm\)1

4) (-50) + 10x² = (-25) x |-2|

=> -50 + 10x² = -50

=> 10x² = -50 + 50

=> 10x² = 0

=> x² = 0

=> x = 0

5) |x + 1| = 2020

=> \(\orbr{\begin{cases}x+1=2020\\x+1=-2020\end{cases}}\)

=> \(\orbr{\begin{cases}x=2019\\x=-2021\end{cases}}\)

6) (x + 1)⁵ + 8 = 0 (xem lại đề)

7) (-20) + x³ : 16 = -24

=> x³ : 16 = -24 + 20

=> x³ : 16 = -4

=> x³ = -4 . 16

=> x³ = -64 = (-4)³

=> x = -4

9) x¹⁴ = x¹⁷

=> x¹⁴ - x¹⁷ = 0

=> x¹⁴(1 - x³) = 0

=> \(\orbr{\begin{cases}x^{14}=0\\1-x^3=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=0\\x=1\end{cases}}\)

10) (-36) + (1 - x)² = 0

=> (1 - x)² = 36

=> (1 - x)² = 6²

=> \(\orbr{\begin{cases}1-x=6\\1-x=-6\end{cases}}\)

=> \(\orbr{\begin{cases}x=-5\\x=7\end{cases}}\)

giải được câu b thôi.

b, (|x| + 2) . (6 - 2|x|) = 0

=> Với mọi số nguyên x thuộc Z thì |x| > 2

=> 6 - 2|x| = 0

=> 2|x| = 6 - 0

=> 2|x| = 6

=> |x| = 6 / 3

=> |x| = 2 và x = 2 hoặc x = -2

Bài 1 câu a:

1/-8 + -5/8

= -1/8 - 5/8

= -6/8

= -3/4

Câu b:

-1/21 + -1/28

= -4/84 - 3/84

= - 7/854

Câu c:

-5/9 + 8/15 + -2/11 + 4/-9 + 7/15

= (8/15+ 7/15) - (5/9 + 4/9) - 2/11

= 1 - 1 - 2/11

= 0 - 2/11

= - 2/11

Câu d:

-25/-75 + 17/34 + 121/- 132

= 1/3 + 1/2 - 11/12

= 4/12 + 6/12 - 11/12

= 10/12 - 11/12

= - 1/12

Bài 2a:

51/23 = 5151/2323 = 515151/232323

\(\frac{5151}{2323}\) = \(\frac{5151:101}{2323:101}\) = \(\frac{51}{23}\) (1)

\(\frac{515151}{232323}\) = \(\frac{515151:10101}{232323:10101}\) = \(\frac{51}{23}\) (2)

Từ (1) và (2) ta có:

\(\frac{51}{23}=\frac{5151}{2323}=\frac{515151}{232323}\) (đpcm)

\(a.2^x=128:4=32\)

\(\Rightarrow x=5\)

\(\text{b.(x - 6)3 = (x - 6)2}\)

\(\Rightarrow\hept{\begin{cases}x-6=1\\x-6=0\end{cases}\Rightarrow\hept{\begin{cases}x=7\\x=6\end{cases}}}\)

\(c.x=1;0\)

\(d.\text{ (7x - 11)3 = 25 . 52 + 200}\)

\(\text{ (7x - 11)3 = 1500}\)

\(\text{x là số thập phân}\)

\(\text{e. (2x - 2)3 = 8}\)

\(2x-2=2\)

\(x=2\)

\(\text{f, 3+2x-1 = 24 - [ 42 - ( 22 - 1) ]}\)

\(\text{f, 3+2x-1 =203 }\)

\(2x-1=200\)

\(2x=201\)

\(x=100.5\)

a) \(2^x\cdot4=128\)

\(2^{x+2}=2^7\)

\(x=5\)

b) \(\left(x-6\right)^3=\left(x-6\right)^2\)

\(\left(x-6\right)^3:\left(x-6\right)^2=1\)

\(x-6=1\)

\(x=7\)

c) \(x^{17}=x\)

\(x\in\left\{-1;0;1\right\}\)

d) \(\left(7x-11\right)^3=2^5\cdot5^2+200\)

\(\left(7x-11\right)^3=1000\)

\(7x-11=10\)

\(7x=21\)

\(x=3\)

e) \(\left(2x-2\right)^3=8\)

\(2x-2=2\)

\(2x=4\)

\(x=2\)

f) \(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)

\(3+2^{x-1}=11\)

\(2^{x-1}=8\)

\(x-1=3\)

\(x=4\)

A, 89 -(73-x)=20

=> 73 - x = 89 - 20

=> 73 - x = 69

=> x = 73 - 69

=> x = 4

B, 7x - 2x = 6¹⁷:6¹⁵ + 44:11

=> ( 7 - 2 ) x = 36 + 4

=> 5x = 40

=> x = 8

C, x - [ 42+(-28)]=-8

=> x - 14 = - 8

=> x = - 8 + 14

=> x = 6

D, 62 - (2x-3):3=23

=> ( 2x - 3 ) : 3 = 62 - 23

=> ( 2x - 3 ) : 3 = 39

=> 2x - 3 = 117

=> 2x = 120

=> x = 60

E, 4(x-3)=7² - 1¹⁰

=> 4 ( x - 3 ) = 49 - 1

=> 4 ( x - 3 ) = 48

=> x - 3 = 12

=> x = 15

a,  A = \(\dfrac{3^9\times3^{20}\times2^8}{3^{24}\times243\times2^6}\)

     A = \(\dfrac{3^{29}\times2^8}{3^{24}\times3^5\times2^6}\)

     A = \(\dfrac{3^{39}\times3^{20}\times2^8}{3^{29}\times2^6}\)

     A = 2² 

     A = 4

b, \(\dfrac{2^{15}\times5^3\times2^6\times3^4}{8\times2^{18}\times81\times5}\)

B = \(\dfrac{2^{21}\times3^4\times5^3}{2^3\times2^{18}\times3^4\times5}\)

B = \(\dfrac{2^{21}\times3^4\times5^3}{2^{21}\times3^4\times5}\)

B =  5²

B = 25