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\(1) 420+65.4=(x+175):5+30\)
\(\implies 420+260=(x+175):5+30\)
\(\implies 680=(x+175):5+30\)
\(\implies 650=(x+175):5\)
\(\implies 650.5-175=x\)
\(\implies 3075=x\)
\(2)x-4867=(175.2050.70):25+23\)
\(\implies x-4867=1004500+23\)
\(\implies x-4867=1004523\)
\(\implies x=1009390\)
\(3) 134-[(96-7x):4-2]=126\)
\(\implies (96-7x):4-2=8\)
\(\implies(96-7x):4=10\)
\(\implies 96-7x=40\)
\(\implies 7x=56\)
\(\implies x=8\)
\(4) 4-\{100-[(100-5x):8-5]:10\}:25=0\)
\(\implies 4-\{100-[(100-5x):8-5]:10\}=0\)
\(\implies 100-[(100-5x):8-5]:10=4\)
\(\implies 100-[(100-5x):8-5]=40\)
\(\implies (100-5x):8-5=60\)
\(\implies (100-5x):8=65\)
\(\implies 100-5x=520\)
\(\implies 5x=-420\)
\(\implies x=-84\)
~ Hok tốt a~
Tìm x biết :
45 - [ ( 72 - 8 . x ) : 4 + 7 ] . 3 = 0
[ ( 72 - 8 . x ) :4 + 7 ] . 3 = 45 - 0
[ ( 72 - 8 . x) : 4 + 7 ] . 3 = 45
( 72 - 8 . x ) : 4 + 7 = 45 : 3
( 72 - 8 . x ) : 4 + 7 = 15
( 72 - 8 . x ) : 4 = 15 - 7
( 72 - 8 . x ) : 4 = 8
72 - 8 . x = 8 × 4
72 - 8 . x = 32
8 . x = 72 - 32
8 . x = 40
x = 40 : 8
x = 5
Vậy x = 5
\([\left(72-8\cdot x\right):4+7]\cdot3=45-0\)
\([\left(72-8\cdot x\right):4+7]\cdot3=45\)
\(\left(72-8\cdot x\right):4+7=45:3\)
\(\left(72-8\cdot x\right):4+7=15\)
\(\left(72-8\cdot x\right):4=15-7\)
\(\left(72-8\cdot x\right):4=8\)
\(72-8\cdot x=8\cdot4\)
\(72-8\cdot x=32\)
\(8x=72-32\)
\(8x=40\)
\(x=40:8\)
\(x=5\)
\(\frac{4}{x}=\frac{1}{5}\)
Vì \(\frac{4}{x}=\frac{1}{5}\)
=> \(4.5=1.x\)
=> \(20=1.x\)
=> \(x=\frac{20}{1}=20\)
Vậy x = 20
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\(53.39+47.39-53.21+47.21\)
\(=39.\left(53-39\right)-\left(53-47\right).21\)
\(=39.14-6.21\)
\(=39.7.2-6.2.7\)
\(=7.2.\left(39-6\right)\)
\(=14.33\)
\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)
\(\frac{x}{27}=\frac{6}{18}-\frac{2}{9}\)
\(\frac{x}{27}=\frac{3}{9}-\frac{2}{9}\)
\(\frac{x}{27}=\frac{1}{9}\)
\(\frac{x}{27}=\frac{3}{27}\)
\(x=3\)
Ấy nhầm, làm lại nha:
\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)
\(\frac{x}{27}=\frac{6}{18}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{3}{9}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{5}{9}\)
\(\frac{x}{27}=\frac{15}{27}\)
\(x=15\)
1)GT => (156-5x)/32=3
=> 156-5x=96
=> 5x=60
=> x=12
Tìm x :
( 156 - 5 . x ) : 32 + 130 = 133
( 156 - 5 . x ) : 32 = 133 - 130
( 156 - 5 . x ) : 32 = 3
156 - 5 . x = 3 × 32
156 - 5 . x = 96
5 . x = 156 - 96
5 . x = 60
x = 60 : 5
x = 12
Vậy x = 12
60 - [ (195 - 7 . x) : 5 + 2] . 3 = 0
=>[ (195 - 7 . x) : 5 + 2] . 3=60
=>(195 - 7 . x) : 5 + 2 =60:3=20
=>(195 - 7 . x) : 5=18
=>195 - 7 . x=90
=>7x=105
=>x=15
\(\left(156-5x\right):32+130=133.\)
\(\left(156-5x\right):32=133-130\)
\(\left(156-5x\right):32=3\)
\(\left(156-5x\right)=3\times32\)
\(156-5x=96\)
\(5x=156-96\)
\(5x=60\)
\(x=\frac{60}{5}=12\)
\(60-\left[\left(195-7x\right):5+2\right]\times3=0\)
\(\left[\left(195-7x\right):5+2\right]\times3=60-0\)
\(\left[\left(195-7x\right):5+2\right]\times3=60\)
\(\left[\left(195-7x\right):5+2\right]=60:3\)
\(\left(195-7x\right):5+2=20\)
\(\left(195-7x\right):5=20-2\)
\(\left(195-7x\right):5=18\)
\(195-7x=18\times5\)
\(195-7x=90\)
\(7x=195-90\)
\(7x=105\)
\(x=105:7\)
\(x=15\)
\(\)
\(\left(156-5x\right):32+130=133\)
\(\left(156-5x\right):32=133-130\)
\(\left(156-5x\right):32=3\)
\(\left(156-5x\right)=3.32\)
\(156-5x=96\)
\(5x=156-96\)
\(5x=60\)
\(x=60:5\)
\(x=12\)
\(60-\left[\left(195-7x\right):5+2\right].3=0\)
\(\left[\left(195-7x\right):5+2\right].3=60-0\)
\(\left[\left(195-7x\right):5+2\right].3=60\)
\(\left(195-7x\right):5+2=60:3\)
\(\left(195-7x\right):5+2=20\)
\(\left(195-7x\right):5=20-2\)
\(\left(195-7x\right):5=18\)
\(195-7x=18.5\)
\(195-7x=90\)
\(7x=195-90\)
\(7x=105\)
\(x=105:7\)
\(x=15\)
\(\left(156-5x\right)\div32+130=133\)
\(\left(156-5x\right)\div32=133-130\)
\(\left(156-5x\right)\div32=3\)
\(156-5x=3\times32\)
\(156-5x=96\)
\(5x=156-96\)
\(5x=60\)
\(x=60\div5\)
\(x=12\)
\(60-\left(195-7x\right)\div5+2)\times3=0\)
\(\left(195-7x\right)\div5+2)\times3=60-0\)
\(\left(195-7x\right)\div5-2)\times3=60\)
\(\left(195-7x\right)\div5+2=60\div3\)
\(\left(195-7x\right)\div5+2=20\)
\(\left(195-7x\right)\div5=20-2\)
\(\left(195-7x\right)\div5=18\)
\(195-7x=18\times5\)
\(195-7x=90\)
\(7x=195-90\)
\(7x=105\)
\(x=105\div7\)
\(x=15\)