a. \(5^{10}.125^2.625^3=5^{10}.\left(5^3\right)^2.\left(5^4\right)^3=5^{10}.5^6.5^{12}=5^{10+6+12}=5^{28}\)

a: \(=5^{10}\cdot5^6\cdot5^{12}=5^{28}\)

b: \(=10^3\cdot10^8\cdot10^{15}=10^{26}\)

c: \(=2^{20}\cdot2^{20}=2^{40}\)

d: \(=2^{16}\cdot2^{16}\cdot3^8=2^{32}\cdot3^8\)

e: \(=\dfrac{3^{24}}{3^8}=3^{16}\)

f: \(=2^{12}\cdot2^{20}\cdot2^5=2^{37}\)

\(a,70-5\times\left(x-3\right)=45\)

\(5\times\left(x-3\right)=70-45\)

\(5\times\left(x-3\right)=25\)

\(x-3=25:5\)

x - 3 = 5

x = 5 + 3 = 8

vậy x = 8

\(b,12+\left(5+x\right)=20\)

12 + 5 + x = 20

17 + x = 20

x = 20 - 17 = 3

vậy x = 3

c, 130 - (100 + x) = 25

130 - 100 - x = 25

30 - x = 25

x = 30 - 25 = 5

vậy x = 5

\(g,10+2\times x=4^5:4^3\)

\(10+2\times x=4^2\)

\(10+2\times x=16\)

\(2\times x=16-10\)

\(2\times x=6\)

x = 6 : 2 = 3

vậy x = 3

h, \(14\times x+54=82\)

\(14\times x=82-54\)

\(14\times x=28\)

\(x=28:14=2\)

vậy x = 2

\(k,15\times x-133=17\)

\(15\times x=17+133\)

\(15\times x=150\)

\(x=150:15=10\)

vậy x = 10

\(a,70-5\times\left(x-3\right)=45\)

\(5\times\left(x-3\right)=70-45\)

\(5\times\left(x-3\right)=25\)

\(x-3=25:5\)

x - 3 = 5

x = 5 + 3 = 8

vậy x = 8

\(b,12+\left(5+x\right)=20\)

12 + 5 + x = 20

17 + x = 20

x = 20 - 17 = 3

vậy x = 3

c, 130 - (100 + x) = 25

130 - 100 - x = 25

30 - x = 25

x = 30 - 25 = 5

vậy x = 5

\(g,10+2\times x=4^5:4^3\)

\(10+2\times x=4^2\)

\(10+2\times x=16\)

\(2\times x=16-10\)

\(2\times x=6\)

x = 6 : 2 = 3

vậy x = 3

h, \(14\times x+54=82\)

\(14\times x=82-54\)

\(14\times x=28\)

\(x=28:14=2\)

vậy x = 2

\(k,15\times x-133=17\)

\(15\times x=17+133\)

\(15\times x=150\)

\(x=150:15=10\)

vậy x = 10

ban nao co chuyen shin ko cho minh muon minh giai cho 10 bai nhu the i love pac pac

\(A=\frac{2^{12}.3^4-4^5.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)

\(A=\frac{2^{12}.3^4-2^{10}.3^4}{2^{12}.3^6+2^{12}.3^5}\)

\(A=\frac{2^{10}.3^4\left(2^2-1\right)}{2^{10}.3^4\left(2^2.3^2+2^2.3\right)}\)

\(A=\frac{2^2-1}{2^2.3^2+2^2.3}\)

\(A=\frac{4-1}{36+12}\)

\(A=\frac{3}{48}=\frac{1}{16}\)

a) a³.a⁵ = a³⁺⁵ = a⁸

b) x⁷.x.x⁴ = x⁷⁺¹⁺⁴ = x¹²

c) 3⁵.4⁵ = (3.4)⁵ = 12⁵

d) 8⁵.2³ = 2⁵.2⁵.2⁵.2³ = 2^5+5+5+3 = 2¹⁸

a/a\(^3\).a\(^5\)=a\(^8\)

b/x\(^7\).x.x\(^4\)=x\(^{12}\)

c/3\(^5\).4\(^5\)=2\(^{10}\).3\(^5\)

d/8\(^5\).2\(^3\)=2\(^{18}\)

a) \(\frac{24-x}{16^5}=32^6\)

=> 24 - x = 32⁶.16⁵

<=> 24 - x = (2⁵)⁶ . (2⁴)⁵

<=> 24 - x = 2³⁰ . 2²⁰

<=> 24 - x = 2⁵⁰

<=> x = 24 - 2⁵⁰

b) (-2)^x = -4⁶.8⁵

<=> (-2)^x = -(2²)⁶.(2³)⁵

<=> (-2)^x = -2¹².2¹⁵

<=> (-2)^x = -2²⁷ 

<=> (-2)^x = (-2)²⁷ 

<=> x = 27

Vậy x = 27

d) \(2^x=\frac{2^8}{4^4}\)

<=> \(2^x=\frac{2^8}{\left(2^2\right)^4}\)

<=> \(2^x=\frac{2^8}{2^8}\)

<=> 2^x = 1 <=> x = 0

a.

\(\frac{24-x}{16^5}=32^6\)

( 24 - x ) : 16⁵ = 32⁶

24 - x  = 32⁶ . 16⁵

24 - x = ( 16 )^2.6 . 16⁵

24 - x = 16¹² . 16⁵

24 - x = 16^{12 + 5}

24 - x = 16¹⁷

x = 24 - 16¹⁷

Vậy x = 24 - 16¹⁷

b. 

( - 2 )^x = - 4⁶ . 8⁵

( - 2 )^x = - 4⁶ . ( - 4 ) ^{- 2 . 5}

( - 2 )^x = - 4⁶ . ( - 4 )^{- 10}

( - 2 )^x = - 4 ^{6 + ( - 10 )}

( - 2 )^x = - 4^-4

( - 2 )^x = ( - 2 )^{-2 . ( - 4 )}

( - 2 )^x = ( - 2 )⁸

=> x = 8

Vậy x = 8

a) \(3^{7} \cdot 27^{5} \cdot 81^{3}\)

• Đổi về cơ số 3: \(27 = 3^{3} , \textrm{ }\textrm{ } 81 = 3^{4}\).

\(3^{7} \cdot \left(\right. 3^{3} \left.\right)^{5} \cdot \left(\right. 3^{4} \left.\right)^{3} = 3^{7} \cdot 3^{15} \cdot 3^{12} = 3^{7 + 15 + 12} = 3^{34} .\)

b) \(100^{6} \cdot 1000^{5} \cdot 10 \textrm{ } 000^{3}\)

• Đổi về cơ số 10: \(100 = 10^{2} , \textrm{ }\textrm{ } 1000 = 10^{3} , \textrm{ }\textrm{ } 10 \textrm{ } 000 = 10^{4}\).

\(\left(\right. 10^{2} \left.\right)^{6} \cdot \left(\right. 10^{3} \left.\right)^{5} \cdot \left(\right. 10^{4} \left.\right)^{3} = 10^{12} \cdot 10^{15} \cdot 10^{12} = 10^{39} .\)

c) \(\frac{36^{5}}{18^{5}}\)

• Do cùng số mũ:

\(\left(\left(\right. \frac{36}{18} \left.\right)\right)^{5} = 2^{5} = 32.\)

d) \(24 \cdot 5^{2} + 5^{2} \cdot 5^{3}\)

\(= 24 \cdot 25 + 25 \cdot 125 = 600 + 3125 = 3725.\)

e) \(\frac{125^{4}}{5^{8}}\)

• Đổi về cơ số 5: \(125 = 5^{3}\).

\(\left(\right. 5^{3} \left.\right)^{4} : 5^{8} = 5^{12} : 5^{8} = 5^{12 - 8} = 5^{4} = 625.\)

TÓM lại là a) \(3^{34}\)
b) \(10^{39}\)
c) \(32\)
d) \(3725\)
e) \(625\)

bạn muốn chép đáp án hay sem cách làm///??

a: \(3^7\cdot27^5\cdot81^3\)

\(=3^7\cdot\left(3^3\right)^5\cdot\left(3^4\right)^3\)

\(=3^7\cdot3^{15}\cdot3^{12}=3^{7+15+12}=3^{34}\)

b: \(100^6\cdot1000^5\cdot10000^3\)

\(=\left(10^2\right)^6\cdot\left(10^3\right)^5\cdot\left(10^4\right)^3\)

\(=10^{12}\cdot10^{15}\cdot10^{12}=10^{15+12+12}=10^{39}\)

c: \(36^5:18^5=\left(\frac{36}{18}\right)^5=2^5=32\)

d: \(24\cdot5^2+5^2\cdot5^3\)

\(=5^2\left(24+5^3\right)\)

\(=25\cdot\left(24+125\right)=25\cdot149=3725\)

e: \(125^4:5^8=\left(5^3\right)^4:5^8=5^{12}:5^8=5^{12-8}=5^4\)

a) \(x\in\left\{24;36;48\right\}\)

b) \(x\in\left\{15;30\right\}\)

c) \(x\in\left\{10;20\right\}\)

d) \(x\in\left\{1;2;4;8;16\right\}\)

sorry vì mình chỉ làm tới đây thôi chứ mình phải lo kiếm điểm càng nhanh càng tốt

còn ko thì người ta lấy mất câu hỏi thì mình trả lời làm gì nữa :(

a) \(x\in\left\{24;36;48\right\}\)

b) \(x\in\left\{15;30\right\}\)

c) \(x\in\left\{1;2;4;8;16\right\}\)

~Chúc pác hok tốt~

bạn giải chi tiết luôn nha

a/ 

<=> x - 3 + 5x = 5x + 6

<=> x + 5x - 5x = 6 + 3

<=>   x             = 9

b/ 

<=> 12 - x + 2 = 8

<=> -x             = 8 - 12 - 2

<=> -x             = -6

<=> x              = 6

c/ 

<=> (x - 2/3)^2 = (5/4)^2

<=> x - 2/3       = 5/4

<=> x               = 23/12 (tự quy đồng)

d/

<=> (3/4 - x)^3 = (-2)^3

<=> 3/4 - x      = -2

<=>      -x        = -2 - 3/4

<=>      -x        = -11/4 (tự qđồng)