A=7 B=1 OR =0 C=2 D=4.5.6

a: \(2^{x}\cdot4=128\)

=>\(2^{x}=\frac{128}{4}=32=2^5\)

=>x=5

b: \(x^{15}=x\)

=>\(x^{15}-x=0\)

=>\(x\left(x^{14}-1\right)=0\)

=>\(\left[\begin{array}{l}x=0\\ x^{14}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x^{14}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\end{array}\right.\)

c: \(\left(2x+1\right)^3=125\)

=>\(\left(2x+1\right)^3=5^3\)

=>2x+1=5

=>2x=5-1=4

=>\(x=\frac42=2\)

d: \(\left(x-5\right)^4=\left(x-5\right)^6\)

=>\(\left(x-5\right)^6-\left(x-5\right)^4=0\)

=>\(\left(x-5\right)^4\cdot\left\lbrack\left(x-5\right)^2-1\right\rbrack=0\)

=>\(\left(x-5\right)^4\cdot\left(x-5-1\right)\left(x-5+1\right)=0\)

=>\(\left(x-5\right)^4\cdot\left(x-6\right)\left(x-4\right)=0\)

=>\(\left[\begin{array}{l}x-5=0\\ x-6=0\\ x-4=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=5\\ x=6\\ x=4\end{array}\right.\)

TL ;

A = { x E N / 0 ;1 ; 2 ; 3 ; 4 ; 5 }

B = { x E N / 0 ; 1 ; 2 ; 3 }

C = { x E N / 0 ; 1 }

D = { x E N / 0 ; x ; y }

Chúc bạn học tốt nhé !

a ) x -13 = 2005

=> x = 2018

A={2018}

Vậy A có 1 phần tử

b)  (x - 8)(x - 9 ) =0

\(\Rightarrow\orbr{\begin{cases}x-8=0\\x-9=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=8\\x=9\end{cases}}\)

B= {8;9}

Vậy B có 2 phần tử

a)A={2018}

b)B={9}

c)C={0;1;2;...}

d)D={∅}

tk mk nha!

a) 70⋮x,84⋮x và x>8 => x \(\in\) ƯC_{(70; 84)}

Ta có: 70 = 2.5.7 84 = 2².3.7

=> ƯCLN_{(70; 84)}= 2.7 = 14

ƯC_{(70; 84)}= Ư₍₁₄₎= { 1; 2; 7; 14}

Vì x > 8 => x = 14

b) x⋮12,x⋮25,x⋮30 và 0<x<500 => x \(\in\) BC_{(12; 25; 30)}

Ta có: 12 = 2².3 25 = 5² 30 = 2.3.5

=> BCNN_{(12; 25;30)} = 2².3.5 = 60

BC_(12;25;30)= B₍₆₀₎= {0; 60; 120; 180; 240; 300; 360; 420; 480; 540;...}

Vì 0<x<500 nên x \(\in\) {60; 120; 180; 240; 300; 360; 420; 480}

a)

70; 84 chia hết cho x

=> x thuộc UC(70;84)

UC(70;84) = { 1;2;7;14}

Do x > 8 nên x = 14.

b) x chia hết cho 12;25;30 nên x thuộc BC(12;25;30)

a, x= 203

b, 6.x= 613+5= 618=618:6=103

c, x=1

d, x là số tự nhiên bất kì khác 0

a) \(x=2436:12=203\).
b) \(6x-5=613\)\(\Leftrightarrow6x=613+5\)\(\Leftrightarrow6x=618\)\(\Leftrightarrow x=103\).
c) \(12.\left(x-1\right)=0\)\(\Leftrightarrow x-1=0:12\)\(\Leftrightarrow x-1=0\)\(\Leftrightarrow x=0+1=1\).
d) \(0.x=0\) suy ra x là số tự nhiên bất kì khác 0.

a,

.

c, C=N

d, D=

a)A={18}

b)B={0}

c)C=N

d)D=\(\varnothing\)

a) x = {26;39;52;65}

b) x = {7;14;21;28;35;42;49;56}

c) x = {15;30}

d) x = {1;2;3;4;6;12}

k mik nha !

a,Ư(25)={1;5;25}

\(\Rightarrow\)2x+1\(\in\left\{1;5;25\right\}\)

\(\Rightarrow x\in\left\{0;2;12\right\}\)

bTa có : \(x\inƯC\left(60;150;210\right)\)

Ư(60)={1;2;3;4;5;6;10;12;15;20;30;60}

Ư(150)={1;2;3;5;6;10;15;25;30;50;125;150}

Ư(210)={1;2;3;5;6;7;10;15;30;35;42;70;105;210}

\(\Rightarrow x\in\left\{1;2;3;5;6;10;15;30\right\}\)

mà x>25 nên x=30

kcj