2014/2014

=>\(\frac{6}{5}\cdot\frac{7}{6}\cdot\frac{8}{7}\cdot...\cdot\frac{2015}{2014}=x\)

=>\(\frac{6\cdot7\cdot8\cdot...\cdot2015}{5\cdot6\cdot7\cdot...\cdot2014}=x\)

=>\(\frac{2015}{5}=x\)

=>x=403

\(1\frac{1}{5}\cdot1\frac{1}{6}\cdot...\cdot1\frac{1}{2014}=x\)

\(\frac{6}{5}\cdot\frac{7}{6}\cdot...\cdot\frac{2015}{2014}=x\)

\(\frac{6\cdot7\cdot...\cdot2015}{5\cdot6\cdot...\cdot2014}=x\)

\(\frac{2015}{5}=x\)

\(2015:5=x\)

 \(403=x\)

Vậy  : \(x=403\)

\(=\frac{6}{5}.\frac{7}{6}.\frac{8}{7}............\frac{2015}{2014}=\frac{2015}{5}=403\)

=> \(\frac{6}{5}.\frac{7}{6}.\frac{8}{7}...\frac{2014}{2013}.\frac{2015}{2014}=x\)

=> \(\frac{6.7.8.9...2014.2015}{5.6.7.8...2013.2014}=x\)

=> \(x=\frac{2015}{5}=403\)

\(1\frac{1}{5}\times1\frac{1}{6}\times.......\times1\frac{1}{2014}=x\)

\(\frac{6}{5}.\frac{7}{6}.........\frac{2015}{2014}=x\)

\(\frac{2015}{5}=x\)

\(x=403\)

\(1\frac{1}{5}.1\frac{1}{6}.1\frac{1}{7}...1\frac{1}{2014}=x\)

\(\frac{6}{5}.\frac{7}{6}.\frac{8}{7}...\frac{2015}{2014}=x\)

\(\frac{2015}{5}=x\)

\(x=403\)

Vậy x = 403

Ủng hộ mk nha ^_^

1 1/5=6/5 ,,1 1/6=7/6........

ta có:X=6/5+7/6+.....+2015/2014.

dùng phương pháp "khử liên tiếp"ta có:........từ đó ra

vẫn như thế.dùng phương pháp khử liên tiếp ta có:

  6/5+7/6+.......+2015/2014

=đang duyệt...........!!!!!!!!!!!!!

\(=\frac{6}{5}\times\frac{7}{6}\times....\times\frac{2015}{2014}=\frac{\left(6\times7\times....\times2014\right)\times2015}{\left(6\times7\times....\times2014\right)\times5}=\frac{2015}{5}=403\)