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\(\frac{2^{4-x}}{16^5}=32^6\)
=> \(\frac{2^{4-x}}{\left(2^4\right)^5}=\left(2^5\right)^6\)
=> \(\frac{2^{4-x}}{2^{20}}=2^{30}\)
=> \(2^{4-x}=2^{30}.2^{20}\)
=> \(2^{4-x}=2^{50}\)
=> 4 - x = 50
=> x = 4 - 50 = -46
\(\frac{3^{2x+3}}{9^3}=9^{14}\)
=> \(\frac{3^{2x+3}}{\left(3^2\right)^3}=\left(3^2\right)^{14}\)
=> \(\frac{3^{2x+3}}{3^6}=3^{28}\)
=> \(3^{2x+3}=3^{28}.3^6\)
=> \(3^{2x+3}=3^{34}\)
=> 2x + 3 = 34
=> 2x = 34 - 3
=> 2x = 31
=> x = 31/2
\(a,x^2=16\)
\(x^2=4^2=\left(-4\right)^2\)
\(x=2\) hoặc \(x=-2\)
\(b,x^3=-8\)
\(x^3=\left(-2\right)^3\)
\(x=-2\)
\(c,\left(x+2\right)^2=4\)
\(\left(x+2\right)^2=2^2=\left(-2\right)^2\)
\(x+2=2\Rightarrow x=0\) hoặc \(x+2=-2\Rightarrow x=-4\)
\(d,\left(1-x\right)^3=1\)
\(1-x=1\)
\(x=0\)
e,phần này mk chưa nghĩ ra,sorry bn nha!
Ta có:
(-3/2:3/-4)*(-9/2)-1/4<x/8<-1/2:3/4:1/8+1
Xét VT = (-3/2.-4/3).(-9/2)-1/4
= 2.-9/2-1/4
=-9-1/4=-37/4=--222/24
Xét VP = -1/2:3/4:1/8+1
=-1/2.4/3.8+1
=-16/3+1
=-13/3=-104/24
=>-222/24<x/8<-104/24=>-222/24<x.3/24<-104/24=>-222<x.3<-104
=>x.3={-221;-220;...;--105}Mà x.3 chia hết cho 3=>x.3 thuộc{-219;-216;...;-105}
=>x={-73;-72;.....-35}
Vậy ..........
1)
2x=48=216
vay x=16
2)
2x=8-4=2-12
=>x=-12
3)
3x=212/212=1
=>x=0
4)
24-x=326.165=230.220=250=>4-x=50=>x=-46
I : V~ ảnh
1, 2x = 48
2x = (22)8
2x = 216
2, \(2^x=8^3.\left(\frac{1}{8}\right)^{10}.8^3\)
\(2^x=8^6.\left(\frac{1}{8}\right)^{10}\)
chán qá, ko làm nữa @@
a)\(16^x=32^8\)
\(\Rightarrow\left(2^4\right)^x=\left(2^5\right)^8\)
\(\Rightarrow2^{4x}=2^{40}\)
\(\Rightarrow4x=40\)
\(\Rightarrow x=10\)
b)\(4^x=32^{40}\)
\(\Rightarrow\left(2^2\right)^x=\left(2^5\right)^{40}\)
\(\Rightarrow2^{2x}=2^{200}\)
\(\Rightarrow2x=200\)
\(\Rightarrow x=100\)
c)\(\left(\dfrac{2}{3}\right)^x=\left(\dfrac{4}{9}\right)^4\)
\(\Rightarrow\left(\dfrac{2}{3}\right)^x=\left[\left(\dfrac{2}{3}\right)^2\right]^4\)
\(\Rightarrow\left(\dfrac{2}{3}\right)^x=\left(\dfrac{2}{3}\right)^8\)
\(\Rightarrow x=8\)
d)\(2^{3x+1}=32^2\)
\(\Rightarrow2^{3x+1}=\left(2^5\right)^2=2^{10}\)
\(\Rightarrow3x+1=10\)
\(\Rightarrow3x=9\)
\(\Rightarrow x=3\)
e)\(\left(2x-1\right)^3:7=49\)
\(\Rightarrow\left(2x-1\right)^3=343\)
\(\Rightarrow\left(2x-1\right)^3=7^3\)
\(\Rightarrow2x-1=7\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=4\)
a) Ta có: \(16^x=32^8\)
=> \(\left(2^4\right)^x=\left(2^5\right)^8\)
=> \(2^{4.x}=2^{5.8}\)
=> 4x = 40
=> x = 10
Vậy x =10
b) Ta có : \(4^x=32^{40}\)
=> \(\left(2^2\right)^x=\left(2^5\right)^{40}\)
=> \(2^{2x}=2^{5.40}\)
=> 2x = 200
=> x =100
Vậy x = 100
c) Ta có : \(\left(\dfrac{2}{3}\right)^x=\left(\dfrac{4}{9}\right)^4\)
=> \(\left(\dfrac{2}{3}\right)^x=\left(\dfrac{2}{3}\right)^{2.4}\)
=> x = 8
Vậy x =8
d) Ta có : \(2^{3x+1}=32^2\)
=> \(2^{3x+1}=\left(2^5\right)^2\)
=> 3x+1 =5.2
=> 3x+1 = 10
=> 3x = 10-1=9
=> x= \(\dfrac{9}{3}\)=3
Vậy x = 3
e) (2x-1)\(^3\) : 7 = 49
(2x-1)\(^3\) = 49.7
(2x-1)\(^3\) = 343
(2x-1)\(^3\) = \(7^3\)
=> 2x-1 = 7
2x = 8
x = 8:2
x = 4
Vậy x = 4
1/ 2x = 45.46
=> 2x = 45 + 6
=> 2x = 411
=> 2x = (22)11
=> 2x = 222
=> x = 22
vậy_
2/ 2x = 46.163
=> 2x = (22)6.(24)3
=> 2x = 212.212
=> 2x = 212 + 12
=> 2x = 224
=> x = 24
3/ 2x = 45.162
=> 2x = (22)5.(24)2
=> 2x = 210.28
=> 2x = 210 + 8
=> 2x = 218
=> x = 18
vậy_
\(\frac{1}{2^x}=4^5.4^3=4^{5+3}=4^8\)
\(\Rightarrow1=4^8.2^x=2^{2.8+x}=2^{16+x}\)
ta có 1 < 21 => 216+x < 21
=> 216+x = 20
=> 16+x=0
=> x= -16
a, => 2^x = (2^3)^4/(2^4)^3 = 2^12/2^12 = 1 = 2^0
=> x = 0
c, => 4^x = 4^10.(4-3) = 4^10
=> x=10
d, => 2^2.3^x-1 + 2.3^x.9 = 2^2.3^6+2.3^9
=> 2.3^x-1 . (2+3.9) = 2.3^6.(2+3^3)
=> 2.3^x-1 . 27 = 2.3^6 . 27
=> 3^x-1 = 3^6
=> x-1 = 6
=> x = 7
e, => 2^x.(1/3+1/6+2) = 2^11.(2+1/2)
=> 2^x. 5/2 = 2^11. 5/2
=> 2^x = 2^11
=> x = 11
Tk mk nha
Câu a) số lớn lắm
b) \(3^{-3}\cdot3^5\cdot3^x=3^8\)
=> \(\frac{1}{27}\cdot3^5\cdot3^x=3^8\)
=> \(\frac{1}{27}\cdot3^x=3^3\)
=> \(3^x=3^3:\frac{1}{27}=3^3:\left(\frac{1}{3}\right)^3=3^3:\frac{1^3}{3^3}=3^3\cdot3^3=3^6\)
=> x = 6
b) \(\left(7x+2\right)^{-1}=3^{-2}\)
=> \(\frac{1}{7x+2}=\frac{1}{9}\)
=> 7x + 2 = 9
=> 7x = 7
=> x = 1
Bài 2:
a) \(3^4\cdot\frac{1}{729}\cdot81^3\cdot\frac{1}{9^2}\)
\(=3^4\cdot\left(\frac{1}{3}\right)^6\cdot\left(3^4\right)^3\cdot\left(\frac{1}{3}\right)^4\)
\(=3^4\cdot\left(\frac{1}{3}\right)^6\cdot3^{12}\cdot\left(\frac{1}{3}\right)^4=3^{16}\cdot\left(\frac{1}{3}\right)^{10}=\frac{3^{16}}{3^{10}}=3^6\)
b) \(\left(8\cdot2^5\right):\left(2^4\cdot\frac{1}{32}\right)=\left(2^3\cdot2^5\right):\left(2^4\cdot\left(\frac{1}{2}\right)^5\right)\)
\(=2^8:\left(2^4\cdot\frac{1^5}{2^5}\right)=2^8:\left(\frac{2^4}{2^5}\right)=2^8:2^{-1}=512\)
c) \(12^8\cdot9^{12}=\left(2^2\cdot3\right)^8\cdot\left(3^2\right)^{12}=2^{16}\cdot3^8\cdot3^{24}=2^{16}\cdot3^{32}\)
d) Tương tự
1)))) 4x=84
(22)x=(23)4
22x=212
=>2x=12
x=6
2)))) 4x=3224
(22)x=(25)24
22x=2120
=>2x=120
x=60
3))))8x=1612
(22)x=(24)12
22x=248
=>2x=48
x=24
4))))4x=812
(22)x=(23)12
22x=236
=>2x=36
x=18
tìm số nguyên x
|x|=|14|