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a) \(\frac{x-3}{3}-1=\frac{x}{-4}\)
\(\Leftrightarrow\frac{x-3}{3}-\frac{3}{3}=\frac{x}{-4}\)
\(\Leftrightarrow\frac{x-6}{3}=\frac{x}{-4}\)
\(\Leftrightarrow-4\left(x-6\right)=3x\)
\(\Leftrightarrow-4x+24=3x\)
\(\Leftrightarrow24=3x+4x\)
\(\Leftrightarrow7x=24\)
\(\Leftrightarrow x=\frac{24}{7}\)
b) \(\frac{5}{8}-\left(x-\frac{1}{2}\right)=\frac{-3}{4}\)
\(\Leftrightarrow\frac{5}{8}-x+\frac{1}{2}=\frac{-3}{4}\)
\(\Leftrightarrow\frac{5}{8}+\frac{4}{8}-x=\frac{-3}{4}\)
\(\Leftrightarrow\frac{9}{8}-x=\frac{-3}{4}\)
\(\Leftrightarrow x=\frac{9}{8}+\frac{3}{4}\)
\(\Leftrightarrow x=\frac{15}{8}\)
\(\frac{1}{4}.\frac{2}{3}-\frac{3}{2}.\frac{1}{6}+\frac{1}{12}\)
\(=\frac{1}{6}+\frac{-1}{4}+\frac{1}{12}\)
\(=\frac{2}{12}+\frac{-3}{12}+\frac{1}{12}=\frac{0}{12}=0\)
~ Hok tốt ~
A, \(=\frac{1}{6}-\frac{5}{3}+\frac{1}{12}\)
\(=\frac{2}{12}-\frac{20}{12}+\frac{1}{12}\)
\(=\frac{2-20+1}{12}=-\frac{17}{12}\)
Hok tốt
Câu a:
-4/11.2/5 + 6/11.(-3/10)
= -4/11.2/5 - 3/11.3/5
= - 8/55 - 9/55
= - 17/55
a: \(=\left(-\dfrac{25}{140}+\dfrac{245}{140}+\dfrac{32}{140}\right)\cdot\dfrac{-69}{20}\)
\(=\dfrac{252}{140}\cdot\dfrac{-69}{20}\)
\(=\dfrac{9}{5}\cdot\dfrac{-69}{20}=\dfrac{-621}{100}\)
b: \(=\left(6-2-\dfrac{4}{5}\right)\cdot\dfrac{25}{8}-\dfrac{8}{5}\cdot4\)
\(=\dfrac{16}{5}\cdot\dfrac{25}{8}-\dfrac{32}{5}=\dfrac{18}{5}\)
c: \(=\left(\dfrac{2}{24}+\dfrac{18}{24}+\dfrac{14}{24}\right):\dfrac{-17}{8}\)
\(=\dfrac{34}{24}\cdot\dfrac{-8}{17}=\dfrac{-1}{3}\cdot2=-\dfrac{2}{3}\)
\(\frac37+\frac{5}{13}+\frac{4}{13}\)
=\(\frac37+\left(\frac{5}{13}+\frac{4}{13}\right)\)
=\(\frac37+\frac{9}{13}\)
=\(\frac{39}{91}+\frac{63}{91}\)
=\(\frac{102}{91}\)
\(\left(\frac38+\frac{-3}{4}+\frac{7}{12}\right):\frac56+\frac12\)
=\(\left(\frac{9}{24}+\frac{-18}{24}+\frac{7}{24}\right)\times\frac65+\frac12\)
=\(\frac{5}{24}\times\frac65+\frac12\)
=\(\frac14+\frac12\)
=\(\frac14+\frac24\)
=\(\frac34\)
Câu 1a:
75% - 1 1/2 + 0,5 : 5/12 - (-1/2)^2
= 0,75 - 1,5 + 0,5 x 12/5 - 0,25
= (0,75 - 0,25) - 1,5 + 1,2
= 0,5 - 1,5 + 1,2
= - 1 + 1,2
= 0,2
Bài 1b:
(5/7.0,6 - 5: 3 1/2). (40% - 1,4).(-2)^3
= (3/7 - 5 x 2/7).(0,4 - 1,4).8
= - 1.(-1).8
= 8
\(\frac{1}{2}a-\frac{3}{4}=\frac{5}{15}\)
\(\Leftrightarrow\frac{1}{2}a-\frac{3}{4}=\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{2}a=\frac{1}{3}+\frac{3}{4}\)
\(\Leftrightarrow\frac{1}{2}a=\frac{4}{12}+\frac{9}{12}\)
\(\Leftrightarrow\frac{1}{2}a=\frac{13}{12}\)
\(\Leftrightarrow a=\frac{13}{12}\div\frac{1}{2}\)
\(\Leftrightarrow a=\frac{13}{12}\times\frac{2}{1}\)
\(\Leftrightarrow a=\frac{13}{6}\)
\(\left(x+\frac{1}{8}\right):\frac{2}{3}=3-\frac{3}{4}\)
\(\left(x+\frac{1}{8}\right):\frac{2}{3}=\frac{9}{4}\)
\(x+\frac{1}{8}=\frac{9}{4}.\frac{2}{3}\)
\(x+\frac{1}{8}=\frac{3}{2}\)
\(x=\frac{3}{2}-\frac{1}{8}\)
\(x=\frac{11}{8}\)
Vậy \(x=\frac{11}{8}\)
\(1\frac{8}{15}-\frac{2}{3}=0,2\)
\(\Leftrightarrow\frac{23}{15}a-\frac{2}{3}=\frac{1}{5}\)
\(\Leftrightarrow\frac{23}{15}a=\frac{1}{5}+\frac{2}{3}\)
\(\Leftrightarrow\frac{23}{15}a=\frac{3}{15}+\frac{10}{15}\)
\(\Leftrightarrow\frac{23}{15}a=\frac{13}{15}\)
\(\Leftrightarrow a=\frac{13}{15}\div\frac{23}{15}\)
\(\Leftrightarrow a=\frac{13}{23}\)
\(\left(x+\frac{1}{8}\right)\div\frac{2}{3}=3-\frac{3}{4}\)
\(\Leftrightarrow\left(x+\frac{1}{8}\right)\div\frac{2}{3}=\frac{12}{4}-\frac{3}{4}\)
\(\Leftrightarrow\left(x+\frac{1}{8}\right)\div\frac{2}{3}=\frac{9}{4}\)
\(\Leftrightarrow x+\frac{1}{8}=\frac{9}{4}.\frac{2}{3}\)
\(\Leftrightarrow x+\frac{1}{8}=\frac{9}{6}\)
\(\Leftrightarrow x+\frac{3}{24}=\frac{36}{24}\)
\(\Leftrightarrow x=\frac{36}{24}-\frac{3}{24}\)
\(\Leftrightarrow x=\frac{33}{24}=\frac{11}{8}\)
\(\frac{1}{2}a-\frac{3}{4}=\frac{5}{15}\)
\(\frac{1}{2}a-\frac{3}{4}=\frac{1}{3}\)
\(\frac{1}{2}a=\frac{1}{3}+\frac{3}{4}\)
\(\frac{1}{2}a=\frac{4}{12}+\frac{9}{12}\)
\(\frac{1}{2}a=\frac{13}{12}\)
\(a=\frac{13}{12}:\frac{1}{2}\)
\(a=\frac{13}{12}.2\)
\(a=\frac{13}{6}\)
Vậy\(a=\frac{13}{6}\)
\(\left(x+\frac{1}{8}\right):\frac{2}{3}=3-\frac{3}{4}\)
\(\left(x+\frac{1}{8}\right):\frac{2}{3}=\frac{12}{4}-\frac{3}{4}\)
\(\left(x+\frac{1}{8}\right):\frac{2}{3}=\frac{9}{4}\)
\(x+\frac{1}{8}=\frac{9}{4}\times\frac{2}{3}\)
\(x+\frac{1}{8}=\frac{3}{2}\)
\(x=\frac{3}{2}-\frac{1}{8}\)
\(x=\frac{12}{8}-\frac{1}{8}\)
\(x=\frac{11}{8}\)
Vậy\(x=\frac{11}{8}\)
Câu thứ 2 e chưa cho số cần tìm nha e