Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Đặt A=\(\frac{16.17-5}{16.16+11}\)
\(\Rightarrow A=\frac{16.\left(16+1\right)-5}{16.16+11}\)
\(\Rightarrow A=\frac{16.16+16-5}{16.16+11}\)
\(\Rightarrow A=\frac{16.16+11}{16.16+11}\)
=> A=1
3/14 × 5/17 + 11/14 × 5/17 + 12/17 × 5/16 + 12/17 × 11/16
= 5/17 × ( 3/14 + 11/14) + 12/17 × ( 5/16 + 11/16)
= 5/17 × 1 + 12/17 × 1
= 5/17 + 12/17
= 1
3/14 × 5/17 + 11/14 × 5/17 + 12/17 × 5/16 + 12/17 × 11/16
= 5/17 × ( 3/14 + 11/14) + 12/17 × ( 5/16 + 11/16)
= 5/17 × 1 + 12/17 × 1
= 5/17 + 12/17
= 1
\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^3\cdot2^{22}-2^{36}}\)
\(=\dfrac{3^2\cdot2^{36}}{2^{25}\left(11-2^{11}\right)}=\dfrac{3^2\cdot2^{11}}{11-2048}=\dfrac{-3\cdot2^{11}}{679}\)
\(\left(-\frac{1}{2}\right)^2\cdot2\cdot\frac{7}{4}\div\left(\frac{5}{8}-1\frac{3}{16}\right)\)
\(=\frac{1}{4}\cdot2\cdot\frac{7}{4}\div\left(\frac{10}{16}-\frac{19}{16}\right)\)
\(=\frac{7}{8}\div\left(-\frac{9}{10}\right)\)
\(=\frac{7}{8}\cdot\left(-\frac{10}{9}\right)\)
\(=-\frac{35}{36}\)
-1/2^2.7/4:(5/8-1 3/16)=1/4.7/4:(5/8-19/16)=1/4.7/4:(10/16-19/16)=1/4.7/4:-9/16=1/4.7/4.-16/9=1/4.-28/9=-7/9
\(\frac{272-5}{256+11}\)= \(\frac{267}{267}\) = \(1\)
Vậy tổng của bài bằng 1