\(\frac{18}{37}+\frac{8}{24}+\frac{19}{37}-1\frac{23}{24}+\frac{2}{3}\\ =\left(\frac{18}{37}+\frac{19}{37}\right)+\left(\frac{1}{3}+\frac{2}{3}\right)-1\frac{23}{24}\\ =1+1-1\frac{23}{24}\\ =2-1\frac{23}{24}\\ =\frac{1}{24}\)

\(\frac{18}{37}+\frac{8}{24}+\frac{19}{37}-1\frac{23}{24}+\frac{2}{3}\)

= \(\frac{18}{37}+\frac{8}{24}+\frac{19}{37}-\frac{47}{24}+\frac{16}{24}\)

= \(\left(\frac{18}{37}+\frac{19}{37}\right)+\left(\frac{8}{24}-\frac{47}{24}+\frac{16}{24}\right)\)

= \(1+\frac{-23}{24}\)

= \(\frac{24}{24}+\frac{-23}{24}\)

= \(\frac{1}{24}\)

dễ mà bạn đây là bài cơ bản lớp 6 dấy

 câu a nhé bạn bạn nếu ko làm kiểu khó thì đổi về phaan số bình thường nà sau đó tính trong ngoặc trước rồi tính xoong bỏ dấu ngoặc nhưng ko đổi dấu né thế lad đc tương tự như các câu dưới
 

a)\(8\frac{2}{3}:2\frac{1}{6}-2\frac{27}{51}=\frac{26}{3}.\frac{6}{13}-\frac{43}{17}=4-\frac{43}{17}=\frac{25}{17}\)

b)\(\frac{27}{20}.\frac{15}{4}+\frac{19}{8}=\frac{119}{16}\)

c)\(\left(\frac{1}{12}+\frac{5}{6}\right)+\left(\frac{13}{35}+\frac{23}{35}\right)=\frac{11}{12}+\frac{36}{35}=\frac{817}{420}\)

d)\(\frac{24}{37}.\left(\frac{13}{18}+\frac{2}{9}+\frac{1}{18}\right)=\frac{24}{37}.1=\frac{24}{37}\)

\(\left(6+\left(\frac{1}{2}\right)^3-\left|-\frac{1}{2}\right|\right):\frac{3}{12}\)

\(=\left(6+\frac{1}{8}+\frac{1}{2}\right):\frac{1}{4}\)

=\(\frac{53}{8}:\frac{1}{4}\)

\(=\frac{53}{2}\)

a)30/60,-40/60,45/60,48/60

45/60>30/60>-40/60>-48/60

=3/4>1/2>-2/3>-4/5

Bài 2:

- \(\frac75\) + \(x\) = - \(\frac34\)

\(x\) = - \(\frac34+\frac75\)

\(x=-\frac{15}{20}\) + \(\frac{28}{20}\)

\(x\) = \(\frac{13}{20}\)

Vậy \(x=\frac{13}{20}\)

Bài 3:

- \(\frac74\) + \(\frac14:x\) = \(\frac32\)

\(\frac14:x\) = \(\frac32+\frac74\)

\(\frac14:x\) = \(\frac64+\frac74\)

\(\frac14:x=\frac{13}{4}\)

\(x=\frac14:\frac{13}{4}\)

\(x=\frac14\times\frac{4}{13}\)

\(x=\frac{1}{13}\)

Vậy \(x=\frac{1}{13}\)

bài 1 a)

\(\frac{15}{7}\times\frac43+\frac63\)

=\(\frac{60}{21}+\frac63\)

=\(\frac{60}{21}+\frac{42}{21}\)

=\(\frac{102}{21}\)

=\(\frac{34}{7}\)

b)\(\frac{-13}{41}\times\frac{17}{11}\times\frac{11}{17}\)

=\(\frac{-13}{41}\times\left(\frac{17}{11}\times\frac{11}{17}\right)\)

=\(\frac{-13}{41}\times1\)

=\(\frac{-13}{41}\)

\(A=-\frac{2}{3}+1\frac{1}{4}-\frac{1}{6}=-\frac{2}{3}+\frac{5}{4}-\frac{1}{6}=\frac{5}{12}\)

\(B=\frac{13}{15}\cdot0,25\cdot3+\left(\frac{8}{15}-1\frac{19}{60}\right)\div1\frac{23}{24}\)

\(B=\frac{13}{15}\cdot\frac{1}{4}\cdot3+\left(\frac{8}{15}-\frac{79}{60}\right)\div\frac{47}{24}\)

\(B=\frac{13}{20}-\frac{47}{60}\cdot\frac{24}{47}\)

\(B=\frac{13}{20}-\frac{2}{5}=\frac{1}{4}\)

\(1\frac{13}{15}.\left(0,5\right)^2.3+\left(\frac{8}{15}.1\frac{19}{60}\right):1\frac{23}{24}\)

\(=\frac{28}{15}.\frac{1}{4}.3+\left(\frac{8}{15}.\frac{79}{60}\right):\frac{47}{24}\)\(\\ \)

\(=\frac{28.1.3}{15.4}+\frac{8.79}{15.60}.\frac{24}{47}\)

\(=\frac{7}{5}+\frac{8.79.24}{15.60.47}\)

\(=\frac{7}{5}+\frac{1264}{3525}\)

\(=\frac{6199}{3525}\)

Vậy : \(1\frac{13}{15}.\left(0,5\right)^2.3+\left(\frac{8}{15}.1\frac{19}{60}\right):1\frac{23}{24}=\frac{6199}{3525}\)

\(\frac37+\frac{5}{13}+\frac{4}{13}\)

=\(\frac37+\left(\frac{5}{13}+\frac{4}{13}\right)\)

=\(\frac37+\frac{9}{13}\)

=\(\frac{39}{91}+\frac{63}{91}\)

=\(\frac{102}{91}\)

\(\left(\frac38+\frac{-3}{4}+\frac{7}{12}\right):\frac56+\frac12\)

=\(\left(\frac{9}{24}+\frac{-18}{24}+\frac{7}{24}\right)\times\frac65+\frac12\)

=\(\frac{5}{24}\times\frac65+\frac12\)

=\(\frac14+\frac12\)

=\(\frac14+\frac24\)

=\(\frac34\)