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a) (-124) + 24 = -100
b) 37. 78 + 37. 22
= 37 . ( 78 + 22 )
= 37 . 100
= 3700
\(A=2019^2-\left(2019-3\right)\left(2019+3\right)\\ A=2019-2019^2-2019\cdot3+2019\cdot3+3^2\\ A=9\)
\(\left[504-\left(5^2.8+70\right):3^3+6\right]:25\)
\(\left[504-\left(25.8+70\right):27+6\right]:25\)
\(\left[504-\left(200+70\right):27+6\right]:25\)
\(\left[504-270:27+6\right]:25\)
\(\left[504-10+6\right]:25\)
\(\left[494+6\right]:25\)
\(500:25\)
= 20
\(\left[504-(5^2\cdot8+70):3^3+6\right]:25\)
\(=\left[504-(25\cdot8+70):27+6\right]:25\)
\(=\left[504-(200+70):27+6\right]:25\)
\(=\left[504-270:27+6\right]:25\)
\(=\left[504-10+6\right]:25\)
\(=\left[494+6\right]:25\)
\(=500:25=20\)
\(\text{Ko chắc }:)\)
a)2.18.14+3.17.12+4.69.9
=(2.18).14+(12.3).17+(4.9).69
=36.14+36.17+36.69
=36.(14+17+69)
=36.100
=3600
b)1+(-3)+5+(-7)+9+(-11)+13+(-15)
=[1+(-3)]+[5+(-7)]+[9+(-11)]+[13+(-15)]
=(-2)+(-2)+(-2)+(-2)
=(-8)
b: Sửa đề: \(B=1\cdot3+2\cdot4+3\cdot5+4\cdot6+\cdots+2018\cdot2020\)
\(=1\left(1+2\right)+2\left(2+2\right)+\cdots+2018\left(2018+2\right)\)
\(=\left(1^2+2^2+\cdots+2018^2\right)+2\left(1+2+\cdots+2018\right)\)
\(=\frac{2018\left(2018+1\right)\left(2\cdot2018+1\right)}{6}+2\cdot\frac{2018\cdot2019}{2}\)
\(=\frac{2018\cdot2019\cdot4037}{6}+2018\cdot2019=1009\cdot673\cdot4037+2018\cdot2019\)
\(=1009\cdot673\left(4037+2\cdot3\right)=1009\cdot673\cdot4043\)
=2745427451
c: Ta có: \(C=\left(1+2+3+\cdots+2020\right)\left(20192019\cdot2020-2019\cdot20202020\right)+\left(15-12\right)^2\)
\(=\frac{2020\left(2020+1\right)}{2}\cdot2019\cdot2020\cdot\left(10001-10001\right)+3^2\)
=0+9
=9
[ 219 + (-219)] + 12.5
= 0 + 12.5
= 12.5
Sai rồi -299 mà
âm với dương cộng lại sẽ bằng trừ, mà trừ đi thì sẽ còn 0. 0+12.5=12.5