4Al + 3O₂ \(\underrightarrow{t^o}\) 2Al₂O₃

Al₂O₃ + 6HCl -> 2AlCl₃ + 3H₂O

AlCl₃ + 3NaOH -> Al(OH)₃ + 3NaCl

2Al(OH)₃ \(\underrightarrow{t^o}\) Al₂O₃ + 3H₂O

\(2Al+\dfrac{3}{2}O_2\underrightarrow{t^0}Al_2O_3\)

\(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

\(2AlCl_3+3Ba\left(OH\right)_2\rightarrow2Al\left(OH\right)_3\downarrow+3BaCl_2\)

\(2Al\left(OH\right)_3\underrightarrow{t^0}Al_2O_3+3H_2O\)

2Al(OH)3 -to-> Al2O3 + 3H2O 

Al2O3 -đpnc-> 2Al + 3/2O2 

2Al + 3H2SO4 => Al2(SO4)3 + 3H2 

Al2(SO4)3 + 3BaCl2 => 2AlCl3 + 3BaSO4

4Al + 3O2 -> 2Al2O3 ( nhiệt độ cao )
Al2O3 + 6HCl -> 2AlCl3 + 3H2O
AlCl3 + 3NaOH -> Al(OH)3 + 3NaCl ( Al(OH)3 kết tủa )
2Al(OH)3 -> Al2O3 + 3H2O ( nhiệt độ cao)
2Al2O3 -> 4Al + 3O2 ( nhiệt độ cao)

a) 2Fe+3Cl2--->2FeCl3

FeCl3+3NaOH--->3NaCl+Fe(OH)3

3Fe(OH)3-->Fe2O3+3H2O

Fe2O3+H2---->2Fe+3H2O

Fe+H2SO4---->FeSO4+H2

FeSO4+BaCl2---->FeCl2+BaSO4

b) Fe+2HCl--->FeCl2+H2

FeCl2+AgNO3--->2AgCl+Fe(NO3)2

Fe(NO3)2+2NaOH--->2NaNO3+Fe(OH)2

Fe(OH)2+Na2SO4--->2NaOH+FeSO4

FeSO4+Zn----->ZnSO4+Fe

Fe+.....Ko biết

c)4 Al+3O2--->2Al2O3

Al2O3+3H2SO4--->Al2(SO4)3+3H2O

Al2(SO4)3+3BaCl2---->2AlCl3+3BaCl2

Alcl3+3NaOH--->Al(OH)3+3NaCl

2Al(OH)3--->Al2O3+3H2O

2Al2O3--->4Al+3O2

a) 2Fe+3Cl2--->2FeCl3

FeCl3+3NaOH--->3NaCl+Fe(OH)3

3Fe(OH)3-->Fe2O3+3H2O

Fe2O3+H2---->2Fe+3H2O

Fe+H2SO4---->FeSO4+H2

FeSO4+BaCl2---->FeCl2+BaSO4

b) Fe+2HCl--->FeCl2+H2

FeCl2+AgNO3--->2AgCl+Fe(NO3)2

Fe(NO3)2+2NaOH--->2NaNO3+Fe(OH)2

Fe(OH)2+Na2SO4--->2NaOH+FeSO4

FeSO4+Zn----->ZnSO4+Fe

ko có PTHH

c)4 Al+3O2--->2Al2O3

Al2O3+3H2SO4--->Al2(SO4)3+3H2O

Al2(SO4)3+3BaCl2---->2AlCl3+3BaCl2

Alcl3+3NaOH--->Al(OH)3+3NaCl

2Al(OH)3--->Al2O3+3H2O

2Al2O3--->4Al+3O2

4Al + 3O2 → 2Al2O3

Al2O3 + 6HNO3 → 2Al(NO3)3 + 3H2O

Al(NO3)3 + 3NaOH → Al(OH)3 + 3NaNO3

Al2O3 + 6HCl → 2AlCl3 + 3H2O

(Điện phân trong dung dịch criolit (Na3AlF6))

Chúc bạn học tốt! Thân ái!

a)

+ 4Al + 3O₂ =(nhiệt)=> 2Al₂O₃

+ Al₂O₃ + 6HNO₃ ===> 2Al(NO₃)₃ + 3H₂O

+ Al(NO₃)₃ + 3NaOH ===> 3NaNO₃ + Al(OH)₃

+ 2Al(OH)₃ =(nhiệt)=> Al₂O₃ + 3H₂O

+ Al₂O₃ + 6HCl ===> 2AlCl₃ + 3H₂O

+ 2AlCl₃ =(điện phân nóng chảy)=> 2Al + 3Cl₂

bạn tự cân bằng nhé chứ ko lâu lắm

a) \(S+O_2-to>SO_2\)

\(SO_2+O_2-\frac{to}{xt}>SO_3\)

\(SO_3+H_2O->H_2SO_4\)

\(NaOH+H_2SO_4->Na_2SO_4+H_2O\)

\(BaCl_2+Na_2SO_4->BaSO_4+NaCl\)

b)\(Na_2O+SO_2->Na_2SO_3\)

\(Na_2SO_3+H_2SO_4->Na_2SO_4+H_2O+CO_2\)

\(Ba\left(OH\right)_2+Na_2SO_4->BaSO_4+NaOH\)

\(NaOH+CO_2->Na_2CO_3+H_2O\)

\(2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+3BaCl_2\to 2AlCl_3+3BaSO_4\downarrow\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow +3NaCl\\ 2Al(OH)_3\xrightarrow{t^o}Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow{đpnc}4Al+3O_2\)

\(\left(1\right)2Al_2O_3\xrightarrow[Na_3AlF_6]{đpnc}4Al+3O_2\uparrow\)

\(\left(2\right)2Al+3H_2SO_4--->Al_2\left(SO_4\right)_3+3H_2\uparrow\)

\(\left(3\right)Al_2\left(SO_4\right)_3+3BaCl_2--->3BaSO_4\downarrow+2AlCl_3\)

\(\left(4\right)AlCl_3+3NaOH--->Al\left(OH\right)_3\downarrow+3NaCl\)