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ban nao co chuyen shin ko cho minh muon minh giai cho 10 bai nhu the i love pac pac
\(A=\frac{2^{12}.3^4-4^5.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)
\(A=\frac{2^{12}.3^4-2^{10}.3^4}{2^{12}.3^6+2^{12}.3^5}\)
\(A=\frac{2^{10}.3^4\left(2^2-1\right)}{2^{10}.3^4\left(2^2.3^2+2^2.3\right)}\)
\(A=\frac{2^2-1}{2^2.3^2+2^2.3}\)
\(A=\frac{4-1}{36+12}\)
\(A=\frac{3}{48}=\frac{1}{16}\)
.(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)
=(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)
=(5.3^11+4.3^11.3):[3^9.(5^2-2^3)]
=(5.3^11+12.3^11):[3^9.17]
=3^11.(5+12):(3^9.17)
=(3^11.17):(3^9.17)
=17.(3^11:3^9)
=17.3^2
=17.9
=153
tk nha
bai cua kacura dung nhung 4 dong cuoi la sai to
co khong co kieu phan phoi nhu vay ma phai thay la 3^11:3^9( nhan 17 chia 17 thi khi nao cung nhan duoc ket qua giong nhau)
=3^2=9
câu 2:
\(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{2450}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{49.50}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{49}-\frac{1}{50}\)
\(=1-\frac{1}{50}\)
\(=\frac{49}{50}\)
a) =\(\left[\left(12+1\right)^2+\left(12+2\right)^2\right]:\left(13^2+14^2\right)\)
=1
b)=(1.2.3....8).(9-1-8)
=(1.2.3....8).0
=0
mik chỉ giải được zậy thôi.
t mik nha.
a. 4.52.5.25.2
=(4.25).(5.2).52
=100.10.52
=1000.52
=52000
b. 2.32 + 4.32
=32 . (2+4)
=9.6
=54
a)4.52.5.25.2
=(4.25).(5.2).52
=100.10.52
=52000
b)2.32+4.33
=2.32+4.33
=18+108
=126
a, 4.52.5.25.2
= ( 4.25 ) . (5.2).2
=100 . 10 .52
=52000
b, 2.32 + 4.33
=(2+4).32
=9.6
=54
a) 4 . 52 . 5 . 25 . 2 = ( 4 . 25 ) . ( 5 . 2 ) . 52
= 100 . 10 . 52
= 52 000
b) 2 . 3^2 + 4 . 3^3 = 3^2 . 3^3 + ( 2 + 4 )
= 3^5 . ( 2 + 4)
= 15 . 6
= 90
Học tốt nhé!
a,\(\text{4 .52.5.25.2}=\left(\text{4 .25}\right).\left(5.2\right).52\)
\(=100.10.52=1000.52=52000\)
b,\(2.3^2+\text{4}.3^3=2.3^2\left(1+2.3\right)=18.7=126\)