\(\frac{\frac{1}{9}-\frac{5}{6}-4}{\frac{7}{12}-\fr...">
K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

18 tháng 4 2018

Bấm máy tính ý ngu ạ

18 tháng 4 2018

1/9-5/6-4/7/12-1/36-10

=6/54-45/54-216/54/21/36-1/36-360/36

=-255/54/-340/36

=-85/18-85/9

=-85/18-170/18

=-255/18

=-85/6

tính mà rối loạn lão

VC
26 tháng 2 2020

a) \(\left(\frac{-1}{6}+\frac{5}{-12}\right)+\frac{7}{12}=\left(\frac{-2}{12}+\frac{-5}{12}\right)+\frac{7}{12}=\left(\frac{-7}{12}\right)+\frac{7}{12}=0\)

b)\(\frac{7}{36}-\frac{8}{-9}+\frac{-2}{3}=\frac{7}{36}+\frac{32}{36}-\frac{24}{36}=\frac{15}{36}=\frac{5}{12}\)

c) \(\frac{3}{5}-\frac{2}{5}.\frac{10}{12}=\frac{3}{5}-\frac{2}{5}.\frac{5}{6}=\frac{3}{5}-\frac{1}{3}=\frac{9}{15}-\frac{5}{15}=\frac{4}{15}\)

d) \(\frac{2}{\left(-3\right)^2}+\frac{5}{-13}-\frac{-3}{4}=\frac{2}{9}-\frac{5}{13}+\frac{3}{4}=\frac{8}{36}-\frac{15}{36}+\frac{27}{36}=\frac{5}{9}\)

24 tháng 4 2018

a) \(\left(2\frac{5}{6}+1\frac{4}{9}\right):\left(10\frac{1}{12}-9\frac{1}{2}\right)\)

\(=\left(\frac{17}{6}+\frac{13}{9}\right):\left(\frac{121}{12}-\frac{19}{2}\right)\)

\(=\frac{77}{18}:\frac{7}{12}\)

\(=\frac{22}{3}\)

b) \(1\frac{5}{18}-\frac{5}{18}.\left(\frac{1}{15}+1\frac{1}{12}\right)\)

\(=\frac{23}{18}-\frac{5}{18}.\left(\frac{1}{15}+\frac{13}{12}\right)\)

\(=\frac{23}{18}-\frac{5}{18}.\frac{23}{20}\)

\(=\frac{23}{18}-\frac{23}{72}\)

\(=\frac{23}{24}\)

c) \(-1\frac{1}{7}.\left(9\frac{1}{2}-8,75\right):\frac{2}{7}+0,625:1\frac{2}{3}\)

\(=\frac{-8}{7}.\left(\frac{19}{2}-\frac{35}{4}\right):\frac{2}{7}+\frac{5}{8}:\frac{5}{3}\)

\(=\frac{-8}{7}.\frac{3}{4}:\frac{2}{7}+\frac{3}{8}\)

\(=\frac{-8}{7}.\frac{3}{4}.\frac{7}{2}+\frac{3}{8}\)

\(=-3+\frac{3}{8}\)

\(=\frac{-21}{8}\)

Chúc bn học tốt !!

5 tháng 5 2019

a. \(1\frac{5}{7}\)-\(\frac{9}{7}\)*\(\frac{16}{9}\)

  =\(\frac{12}{7}\)-\(\frac{16}{7}\)

  =\(\frac{-4}{7}\)

b. \(\frac{-5}{8}\):\(\frac{1}{4}\)-\(\frac{6}{13}\)*4+\(\frac{3}{8}\)

  =\(\frac{-5}{8}\cdot\)4-\(\frac{6}{13}\)*4+\(\frac{3}{8}\)

  =4*(\(\frac{-5}{8}\)-\(\frac{6}{13}\))+\(\frac{3}{8}\)

  =4*\(\frac{-113}{104}\)+\(\frac{3}{8}\)

  =\(\frac{-113}{26}\)+\(\frac{3}{8}\)

  =\(\frac{-413}{104}\)

c.( \(\frac{3}{8}\)+\(\frac{-1}{4}\)-\(\frac{5}{12}\)):\(\frac{1}{3}\)

 =\(\frac{-7}{24}\)*3

 =\(\frac{-7}{8}\)

Học tốt

9 tháng 2

Câu 1:

A = (4/9 + 5/6) : (7/8 - 7/12)

A = (8/18 + 15/18) :(21/24 - 14/24)

A = 23/18 : 7/24

A = 23/18 x 24/7

A = 92/21

9 tháng 2

Câu B = 3/4.8/9.15/16...9999/10000

B = \(\frac{1.3}{2.2}\).\(\frac{2.4}{3.3}\)....\(\frac{99.101}{100.100}\)

B = \(\frac{1.2.3\ldots99}{2.3\ldots100}\). \(\frac{3.4.\ldots101}{2.3\ldots100}\)

B = \(\frac{1}{100}\) x \(\frac{101}{2}\)

B = \(\frac{101}{200}\)

4 tháng 3 2025

B1a)\(11\frac34-\left(6\frac56-4\frac12\right)+1\frac23\)

=\(11\frac34-6\frac56+4\frac12+1\frac23\)

=\(\left(11-6+4+1\right)+\left(\frac34-\frac56+\frac12+\frac23\right)\)

=\(10+\left(\frac{9}{12}-\frac{10}{12}+\frac{6}{12}+\frac{8}{12}\right)\)

=\(10+\left(-\frac{1}{12}+\frac{6}{12}+\frac{8}{12}\right)\)

=10+\(\frac{13}{12}\)

=\(\frac{120}{12}+\frac{13}{12}\)

=\(\frac{133}{12}\)

4 tháng 3 2025

b)\(2\frac{17}{20}-1\frac{11}{5}+6\frac{9}{20}:3\)

= \(\frac{57}{20}-\frac{16}{5}+\frac{129}{20}\times\frac13\)

=\(\frac{57}{20}-\frac{16}{5}+\frac{129}{60}\)

=\(\frac{171}{60}-\frac{192}{60}+\frac{129}{60}\)

=\(\frac{108}{60}\)

=\(\frac95\)

11 tháng 5 2018

a. \(\frac{2}{3}+\frac{1}{3}.\left(\frac{-4}{9}+\frac{5}{6}\right):\frac{7}{12}\)

\(=1.\frac{7}{12}:\frac{7}{12}\)

\(=1\)

b. 

\(\frac{5}{9}.\frac{8}{11}+\frac{5}{9}.\frac{9}{11}-\frac{5}{9}.\frac{6}{11}\)

\(=\frac{5}{9}.\left(\frac{8}{11}+\frac{9}{11}-\frac{6}{11}\right)\)

\(=\frac{5}{9}.1\)

\(=\frac{5}{9}\)

Tk mk nha!

11 tháng 5 2018

b)  \(=\frac{5}{9}.\left(\frac{8}{11}+\frac{9}{11}-\frac{6}{11}\right)\)

\(=\frac{5}{9}.1\)

\(=\frac{5}{9}\)

9 tháng 2

Câu a:

(4 5/37 - 3 4/5 + 8 15/29) - (3 5/37 - 6 14/29)

= (4 5/37 - 3 5/37) + (8 15/29 + 6 14/29) - 3 4/5

= 1 + 15 - 3 4/5

= 16 - 3 - 4/5

= 13 - 4/5

= 61/5

9 tháng 2

Câu b:

(2\(\frac56\) + 1\(\frac49\)) : (10\(\frac{1}{12}\) - 9\(\frac12\))

= (17/6 + 13/9) :(121/12 - 19/2)

= (51/18 + 26/18) :(121/12 - 114/2)

= 77/18 : 7/12

= 77/18 x 12/7

= 22/3