\(\dfrac{5}{-6}=\dfrac{-55}{66};\dfrac{-10}{11}=\dfrac{-60}{66}\Rightarrow\dfrac{-55}{66}>\dfrac{-60}{66}\Rightarrow\dfrac{5}{-6}>\dfrac{-10}{11}\\ \dfrac{-3}{20}=\dfrac{-45}{300};\dfrac{2}{-15}=\dfrac{-40}{300}\Rightarrow\dfrac{-45}{300}< \dfrac{-40}{300}\Rightarrow\dfrac{-3}{20}< \dfrac{2}{-15}\\ -0,305>-0,36\)

\(^\circ\) \(\dfrac{5}{-6}\) và \(\dfrac{-10}{11}\)

Ta có \(:\)

\(\dfrac{5}{-6} = \dfrac{ 5 . 11 }{ -6 . 11 } = \dfrac{ 55 }{ -66} \)

\(\dfrac{-10}{11} = \dfrac{-10 . ( -6 )}{11.(-6)} = \dfrac{60}{-66}\)

Do \(55 < 60\)

\(=> \dfrac{55}{-66} > \dfrac{60}{-66}\)

Vậy \(\dfrac{55}{-66} > \dfrac{60}{-66}\)

\(\dfrac{-3}{20}\) và \(\dfrac{2}{-15}\)

Ta có :

\(\dfrac{-3}{20} = \dfrac{-3.3}{20.3}=\dfrac{-9}{60}\)

\(\dfrac{2}{-15} = \dfrac{2.4}{-15.4}= \dfrac{8}{-60}= \dfrac{-8}{60}\)

Do \(-9 <-8\)

\(=> \dfrac{-3}{20} < \dfrac{-2}{15}\)

Vậy \( \dfrac{-3}{20} < \dfrac{-2}{15}\)

\(\dfrac{5}{-6}\) và \(\dfrac{-10}{11}\) 

\(5\cdot11=55\)

\(\left(-10\right)\cdot\left(-6\right)=60\)

Mà \(55< 60\Rightarrow\) \(\dfrac{5}{-6}< \dfrac{-10}{11}\)

\(\dfrac{-3}{20}\) và \(\dfrac{2}{-15}\)

\(\left(-3\right)\cdot\left(-15\right)=45\)

\(2\cdot20=40\)

Mà \(45>40\Rightarrow\) \(\dfrac{-3}{20}>\dfrac{2}{-15}\)

\(-0,305\) và \(-0,36\)

\(-0,305=-\left(3+0+5\right)=-8\)

\(-0,36=-\left(3+6\right)=9\)

Mà \(\left(-8\right)>\left(-9\right)\Rightarrow\)\(-0,305>-0,36\)

ko làm từng câu 1

\(-0,305\) và \(-0,36\)

Do \(0,305 < 0,36\)

\(=> -0,305 > -0,36\)

Vậy \(-0,305 > -0,36\)