a) 81⁸⁰ < 27⁹⁰

b) 3⁷⁷ > 7³⁸

c) 5³⁶ < 11²⁴

d) 2⁹¹ < 5³⁵

Đúng thì k, sai thì thôi

Câu a:

81^80 và 27^90

81^80 = (3^4)^80 = 3^320

27^90 = (3^3)^90 = 3^270 < 3^320

81^80 > 27^90

\(77^{33}=\left(11.7\right)^{33}=11^{33}.7^{33}=11^{33}.\left(7^3\right)^{11}=11^{33}.343\left(1\right)\)

\(33^{77}=\left(3.11\right)^{77}=3^{77}.11^{77}=\left(3^7\right)^{11}.11^{77}=2187^{11}.11^{77}\left(2\right)\)

Từ \(\left(1\right)+\left(2\right)\Leftrightarrow33^{77}>77^{33}\)

oh my god . Tôi đi vào bệnh viện đầy 

77².2²=(77.2)²=134²

Ngọc Nguyễn Minh sai rồi mà bạn

a, 97/583 < 13/77

b, \(-\left(\frac{9^{100}+4}{9^{100}-2}\right)< -\left(\frac{9^{100}}{9^{100}-6}\right)\)

chúc bạn hk tốt!!(nhớ k cho mình nha!!@@)

1) Ta có: \(80-\left(5.4^2-4.2^3\right)\)

\(=80-\left(80-32\right)\)

\(=80-80+32\)

\(=32\)

2) \(60-\left[120-\left(42-33\right)^2\right]\)

\(=60-\left(120-9^2\right)\)

\(=60-120+81\)

\(=21\)

\(a,80-\left(5.4^2-4.2^3\right)\)

\(=80-\left(80-32\right)\)

\(=80-80+32\)

\(=32\)

\(b,60-\left[120-\left(42-33\right)^2\right]\)

\(=60-\left(120-9^2\right)\)

\(=60-39\)

\(=21\)

Ta có :

\(3^{2n}=\left(3^2\right)^n=9^n\)

\(2^{3n}=\left(2^3\right)^n=8^n\)

Do 9 > 8 => \(9^n>8^n\Rightarrow3^{2n}>2^{3n}\)

Vậy \(3^{2n}>2^{3n}\)

  Ta có:

\(3^{2n}=\left(3^2\right)^n=9^n\)

\(2^{3n}=\left(2^3\right)^n=8^n\)

Vì \(9^n>8^n\Rightarrow3^{2n}>2^{3n}\)

_Hok tốt_

!!!

A= 10³⁰ = (10³ ) ¹⁰ = 1000¹⁰
B= 2¹⁰⁰ = (2¹⁰ ) ¹⁰ = 1024¹⁰
Vì 1000¹⁰ < 1024¹⁰
=> A<B
 

A=10³⁰=(10³)¹⁰=1000¹⁰

B=2¹⁰⁰=(2¹⁰)¹⁰=1024¹⁰

Vì 1000¹⁰<1024¹⁰ nên A<B