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Thanks A = \(\frac{3.4+3.7}{6.5+9}\)
A = \(\frac{3.\left(4+7\right)}{3.\left(10+3\right)}\)
A = \(\frac{11}{13}\)
B = \(\frac{6.9-2.17}{63.3-119}\)
B = \(\frac{2.\left(27-17\right)}{7.\left(27-17\right)}\)
B = \(\frac27\)
A = \(\frac{11}{13}\) = \(\frac{77}{91}\)
B = \(\frac27=\frac{26}{91}\)
Câu a:
\(\frac{3939-101}{3.2929+505}\)
= \(\frac{101.\left(39-1\right)}{101.\left(3.29+5\right)}\)
= \(\frac{38}{87+5}\)
= \(\frac{38}{92}\)
= \(\frac{19}{46}\)
Câu c:
\(\frac{6.9-2.17}{63.3-119}\)
= \(\frac{2.\left(3.9-17\right)}{7.\left(9.3-17\right)}\)
= \(\frac27\)
a/\(\frac{3939-101}{3.2929+505}=\frac{39.101-101}{8787+505}=\frac{101.\left(39-1\right)}{87.101+5.101}=\frac{101.38}{101.\left(87+5\right)}=\frac{38}{92}\)
\(=\frac{38}{92}\)
b/\(\frac{6.4+6.7}{6.5+12}=\frac{4+1.7}{1.5+2}=\frac{4+7}{5+2}=\frac{11}{7}\)
\(\frac{3.4+3.7}{6.5+9}=\frac{3\left(4+7\right)}{30+9}=\frac{3.11}{39}=\frac{33}{39}=\frac{11}{13}\)
\(\frac{3.4+3.7}{6.5+9}\)và \(\frac{6.9-2.17}{63.3-119}\)
\(\frac{3.4+3.7}{6.5+9}=\frac{3\left(4+7\right)}{30+9}=\frac{3.11}{39}=\frac{33}{39}=\frac{11}{13}\)
\(\frac{6.9-2.17}{63.3-119}=\frac{54-54}{63.3-11}=0\)
ta có:
\(\frac{3.4+3.7}{6.5+9}=\frac{3.\left(4+7\right)}{3.\left(2.5\right)+3.3}=\frac{3.\left(4+7\right)}{3.\left(2.5+3\right)}\)
\(=\frac{3.\left(4+7\right)}{3.\left(10+3\right)}=\frac{3.11}{3.13}=\frac{3}{3}.\frac{11}{13}=1.\frac{11}{13}=\frac{11}{13}\)
và \(\frac{6.9-2.17}{63.3-119}=\frac{2.\left(3.9\right)-2.17}{7.\left(9.3\right)-7.17}=\frac{2.\left(3.9-17\right)}{7.\left(9.3-17\right)}\)
\(=\frac{2}{7}.\frac{\left(3.9\right)-17}{\left(9.3\right)-17}=\frac{2}{7}.1=\frac{2}{7}\)
Vậy ta sẽ quy đồng mẫu số hai phân số: \(\frac{11}{13}\)và \(\frac{2}{7}\)(MSC: 91)
Ta có: \(\frac{11}{13}=\frac{11.7}{13.7}=\frac{77}{91}\)
và \(\frac{2}{7}=\frac{2.13}{7.13}=\frac{26}{91}\)
Ta còn quy đồng được tử số của hai phân số \(\frac{11}{13}\)và \(\frac{2}{7}\)(tử chung: 22)
ta có: \(\frac{11}{13}=\frac{11.2}{13.2}=\frac{22}{26}\)
và \(\frac{2}{7}=\frac{2.11}{7.11}=\frac{22}{77}\)
\(\frac{3.4+3.7}{6.5+9}\)
\(=\frac{3.\left(4+7\right)}{30+9}\)
\(=\frac{11}{13}\)
\(\frac{6.9-2.17}{63.3-119}\)
\(=\frac{54-34}{189-119}\)
\(=\frac{2}{7}\)
A = \(\frac{3.4+3.7}{6.5+9}\)
A = \(\frac{3.\left(4+7\right)}{3.\left(10+3\right)}\)
A = \(\frac{11}{13}\)
B = \(\frac{6.9-2.17}{63.3-119}\)
B = \(\frac{2.\left(27-17\right)}{7.\left(27-17\right)}\)
B = \(\frac27\)
A = \(\frac{11}{13}\) = \(\frac{77}{91}\)
B = \(\frac27=\frac{26}{91}\)
A = \(\frac{3.4+3.7}{6.5+9}\)
A = \(\frac{3.\left(4+7\right)}{3.\left(10+3\right)}\)
A = \(\frac{11}{13}\)
B = \(\frac{6.9-2.17}{63.3-119}\)
B = \(\frac{2.\left(27-17\right)}{7.\left(27-17\right)}\)
B = \(\frac27\) = \(\frac{26}{91}\)
A = \(\frac{11}{13}\) = \(\frac{77}{91}\)