Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: 1/54=1/54
5/6=45/54
b: 3/22=3/22
6/11=12/22
c: 1/2=6/12
2/3=8/12
3/4=9/12
\(\frac{7}{9}\)và\(\frac{6}{7}\)có \(BC:63\)
quy đồng : \(\frac{7\times7}{9\times7}=\frac{49}{63}\)và \(\frac{6\times9}{7\times9}=\frac{54}{63}\)
\(\Rightarrow\)Đáp án là : C
C. 49/63 và 42/63
C. 49/63 và 42/63
Bài 1:
a: Cách 1: \(\frac37=\frac{3\cdot9}{7\cdot9}=\frac{27}{63};\frac59=\frac{5\cdot7}{9\cdot7}=\frac{35}{63}\)
mà 27<35
nên \(\frac37<\frac59\)
Cách 2: Ta có: \(\frac37=\frac{3\cdot5}{7\cdot5}=\frac{15}{35}\)
\(\frac59=\frac{5\cdot3}{9\cdot3}=\frac{15}{27}\)
mà \(\frac{15}{35}<\frac{15}{27}\left(35>27\right)\)
nên \(\frac37<\frac59\)
b: Cách 1: \(\frac{6}{12}=\frac{6\cdot3}{12\cdot3}=\frac{18}{36};\frac49=\frac{4\cdot4}{9\cdot4}=\frac{16}{36}\)
mà 18>16
nên \(\frac{6}{12}>\frac49\)
Cách 2: \(\frac{6}{12}=\frac{6\cdot2}{12\cdot2}=\frac{12}{24};\frac49=\frac{4\cdot3}{9\cdot3}=\frac{12}{27}\)
mà \(\frac{12}{24}>\frac{12}{27}\left(24<27\right)\)
nên \(\frac{6}{12}>\frac49\)
c: Cách 1: \(\frac{15}{25}=\frac{15\cdot18}{25\cdot18}=\frac{270}{450};\frac{54}{90}=\frac{54\cdot5}{90\cdot5}=\frac{270}{450}\)
Do đó: \(\frac{15}{25}=\frac{54}{90}\)
Cách 2: \(\frac{15}{25}=\frac{15:5}{25:5}=\frac35;\frac{54}{90}=\frac{54:18}{90:18}=\frac35\)
do đó: \(\frac{15}{25}=\frac{54}{90}\)
d: Cách 1: \(\frac{25}{30}=\frac{25\cdot3}{30\cdot3}=\frac{75}{90};\frac{75}{28}=\frac{75\cdot1}{28\cdot1}=\frac{75}{28}\)
mà \(\frac{75}{90}<\frac{75}{28}\left(90>28\right)\)
nên \(\frac{25}{30}<\frac{75}{28}\)
Cách 2: \(\frac{25}{30}=\frac{25\cdot14}{30\cdot14}=\frac{350}{420}\)
\(\frac{75}{28}=\frac{75\cdot15}{28\cdot15}=\frac{1125}{420}\)
mà 350<1125
nên \(\frac{25}{30}<\frac{75}{28}\)
e: cách 1: \(\frac{27}{45}=\frac{27\cdot4}{45\cdot4}=\frac{108}{180};\frac{18}{36}=\frac{18\cdot5}{36\cdot5}=\frac{90}{180}\)
mà 108>90
nên \(\frac{27}{45}>\frac{18}{36}\)
Cách 2: \(\frac{27}{45}=\frac{27\cdot2}{45\cdot2}=\frac{54}{90}\)
\(\frac{18}{36}=\frac{18\cdot3}{36\cdot3}=\frac{54}{108}\)
mà \(\frac{54}{90}>\frac{54}{108}\left(90<108\right)\)
nên \(\frac{27}{45}>\frac{18}{36}\)
\(a,\dfrac{52}{32}=\dfrac{13}{8}\\ \dfrac{55}{65}=\dfrac{11}{13}\\ MSC:104\\ =>\dfrac{13}{8}=\dfrac{13.13}{8.13}=\dfrac{169}{104}\\ \dfrac{11}{13}=\dfrac{11.8}{13.8}=\dfrac{88}{104}\)
\(b,\dfrac{72}{64}=\dfrac{9}{8}\\ \dfrac{54}{81}=\dfrac{2}{3}\\ MSC:24\\ \dfrac{9}{8}=\dfrac{9.3}{8.3}=\dfrac{27}{24}\\ \dfrac{2}{3}=\dfrac{2.8}{3.8}=\dfrac{16}{24}\\ c,\dfrac{24}{36}=\dfrac{2}{3}\\ \dfrac{12}{30}=\dfrac{2}{5}\\ MSC:15\\ \dfrac{2}{3}=\dfrac{2.5}{3.5}=\dfrac{10}{15}\\ \dfrac{2}{5}=\dfrac{2.3}{3.5}=\dfrac{6}{15}\)
\(d,\dfrac{80}{40}=2\\ \dfrac{45}{63}=\dfrac{5}{7}\\ MSC:7\\ 2=\dfrac{14}{7}\\ e,\dfrac{150}{50}=3\\ \dfrac{100}{200}=\dfrac{1}{2}\\ MSC:2\\ 3=\dfrac{6}{2}\\ f,\dfrac{54}{81}=\dfrac{2}{3}\\ \dfrac{69}{93}=\dfrac{23}{21}\\ MSC:21\\ \dfrac{2}{3}=\dfrac{2.7}{3.7}=\dfrac{14}{21}\)
\(a.\dfrac{52}{32}\text{=}\dfrac{13}{8};\dfrac{55}{65}\text{=}\dfrac{11}{13}\)
\(\dfrac{13.13}{13.8}\text{=}\dfrac{169}{104};\dfrac{11.8}{13.8}\text{=}\dfrac{88}{104}\)
\(c.\dfrac{24}{36}\text{=}\dfrac{2}{3};\dfrac{12}{30}\text{=}\dfrac{2}{5}\)
\(\dfrac{2.5}{3.5}\text{=}\dfrac{10}{15};\dfrac{2.3}{5.3}\text{=}\dfrac{6}{15}\)
\(b.\dfrac{72}{64}\text{=}\dfrac{9.3}{8.3}\text{=}\dfrac{27}{24};\dfrac{54}{81}\text{=}\dfrac{2.8}{3.8}\text{=}\dfrac{16}{24}\)
\(d.\dfrac{80}{40}\text{=}\dfrac{2.63}{63}\text{=}\dfrac{126}{63};\dfrac{45}{63}\)
\(e.\dfrac{150}{50}\text{=}\dfrac{3.2}{2}\text{=}\dfrac{6}{2};\dfrac{100}{200}\text{=}\dfrac{1}{2}\)
\(f.\dfrac{54}{81}\text{=}\dfrac{2.31}{3.31}\text{=}\dfrac{62}{93};\dfrac{69}{93}\)
Ta có:
\(\frac{22}{99}=\frac{2}{9}=\frac{12}{54};\frac{40}{135}=\frac{8}{27}=\frac{16}{54}\)
=> các phân số lớn hơn \(\frac{22}{99}\)và bé hơn \(\frac{40}{135}\)có mẫu là 54 là: \(\frac{13}{54};\frac{14}{54};\frac{15}{54}\)

99/54=11/6=143/78
54/78=9/13=54/78
143/78
54/78
Ta có: \(\dfrac{99}{54}=\dfrac{11}{6}\);\(\dfrac{54}{78}=\dfrac{9}{13}\)
Quy đồng mẫu số hai phân số: \(\dfrac{11}{6}=\dfrac{143}{78}\);\(\dfrac{9}{13}=\dfrac{54}{78}\)