a: =>1/6x=-49/60

=>x=-49/60:1/6=-49/60*6=-49/10

b: =>3/2x-1/5=3/2 hoặc 3/2x-1/5=-3/2

=>x=17/15 hoặc x=-13/15

c: =>1,25-4/5x=-5

=>4/5x=1,25+5=6,25

=>x=125/16

d: =>2^x*17=544

=>2^x=32

=>x=5

i: =>1/3x-4=4/5 hoặc 1/3x-4=-4/5

=>1/3x=4,8 hoặc 1/3x=-0,8+4=3,2

=>x=14,4 hoặc x=9,6

j: =>(2x-1)(2x+1)=0

=>x=1/2 hoặc x=-1/2

a)

\(3(2x-\frac{1}{2})+2(\frac{3}{8}-x)=2,75\)

\(\Leftrightarrow 6x-\frac{3}{2}+\frac{3}{4}-2x=2,75\)

\(\Leftrightarrow 4x=\frac{7}{2}\Rightarrow x=\frac{7}{8}\)

b)

\(x-\frac{1}{3}(5-3x)=1\frac{1}{2}x+5\frac{1}{2}\)

\(\Leftrightarrow x-\frac{5}{3}+x=x+\frac{1}{2}x+\frac{11}{2}\)

\(\Leftrightarrow \frac{1}{2}x=\frac{43}{6}\) \(\Rightarrow x=\frac{43}{3}\)

c) \(\sqrt{x-1}=4\Rightarrow x-1=4^2\Rightarrow x=4^2+1=17\)

d)

\(|x|-5\frac{3}{7}|-x|-\frac{3}{4}=2|x|-1\frac{1}{7}\)

\(\Leftrightarrow |x|-\frac{38}{7}|x|-\frac{3}{4}=2|x|-\frac{8}{7}\)

\(\Leftrightarrow |x|(1-\frac{38}{7}-2)=\frac{3}{4}-\frac{8}{7}\)

\(\Leftrightarrow |x|.\frac{-45}{7}=\frac{-11}{28}\)

\(\Leftrightarrow |x|=\frac{11}{180}\Rightarrow \left[\begin{matrix} x=\frac{11}{180}\\ x=-\frac{11}{180}\end{matrix}\right.\)

a.

| x | = 5,6

=>\(\left[{}\begin{matrix}x=5,6\\x=-5,6\end{matrix}\right.\)

Vậy \(x\in\left\{-5,6;5,6\right\}\)

b, \(\left|x-3,5\right|=5\)

=>\(\left[{}\begin{matrix}x-3,5=5\\x-3,5=-5\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=8,5\\x=-1,5\end{matrix}\right.\)

Vậy \(x\in\left\{-1,5;8,5\right\}\)

c,\(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)

=> \(\left|x-\dfrac{3}{4}\right|=\dfrac{1}{2}\)

=>\(\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{1}{2}\\x-\dfrac{3}{4}=-\dfrac{1}{2}\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{1}{4}\end{matrix}\right.\)

Vậy \(x\in\left\{\dfrac{1}{4};\dfrac{5}{4}\right\}\)

d,\(\left|4x\right|-\left(\left|-13,5\right|\right)=\left|\dfrac{1}{4}\right|\)

=> \(\left|4x\right|-13,5=\dfrac{1}{4}\)

=> \(\left|4x\right|=13,75\)

=>\(\left[{}\begin{matrix}4x=13,75\\4x=-13,75\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=3,4375\\x=-3,4375\end{matrix}\right.\)

Vậy \(x\in\left\{-3,4375;3,4375\right\}\)

e, ( x - 1 ) ³ = 27

=> x - 1 = 3

=> x = 4

Vậy x = 4

f, ( 2x - 3)² = 36

=> \(\left[{}\begin{matrix}2x-3=6\\2x-3=-6\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}x=4,5\\x=-1,5\end{matrix}\right.\)

Vậy x\(\in\left\{-1,5;4,5\right\}\)

g, \(5^{x+2}=625\)

=> \(5^{x+2}=5^4\)

=> x + 2 = 4

=> x = 2

Vậy x = 2

h, ( 2x - 1)³ = -8

=> 2x - 1 = -2

=> x = \(\dfrac{-1}{2}\)

Vậy x = \(\dfrac{-1}{2}\)

i, \(\dfrac{1}{4}.\dfrac{2}{6}.\dfrac{3}{8}.\dfrac{4}{10}.\dfrac{5}{12}...\dfrac{30}{62}.\dfrac{31}{64}=2^x\)

=> \(\dfrac{1.2.3.4.5...30.31}{4.6.8.10.12...62.64}=2^x\)

=>\(\dfrac{1.2.3.4.5...30.31}{\left(2.3.4.5...30.31.32\right)\left(2.2.2.2...2.2_{ }\right)}=2^x\)(có 31 số 2)

=> \(\dfrac{1}{32.2^{31}}=2^x\)

=> \(\dfrac{1}{2^{36}}=2^x\)

=> x = -36

Vậy x = -36

a) 27^x : 3^x = 9

(27 : 3)^x = 9

9^x = 9¹

x = 1

b) 25 : 5^x =5

5^x = 25 : 5

5^x = 5¹

x = 1

c) 2 : (x + 2)² = \(\dfrac{1}{18}\)

(x + 2)² = 2 : \(\dfrac{1}{18}\)

(x + 2)² = 36

\(\Rightarrow\left[{}\begin{matrix}x+2=6\\x+2=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4\\x=-8\end{matrix}\right.\)

d) (5x - 1)² = \(\dfrac{36}{49}\)

(5x - 1)² = \(\left(\dfrac{6}{7}\right)^2\)

Bạn làm tiếp nha, mình có việc bận :v

a) C = 20013 - $\left|5-2x\right|$

$do\; \backslash (-\backslash left|5-2x\backslash right|\backslash le0\backslash forall\; x\backslash )$

=> 20013-\(\left|5-2x\right|\le20013\)

=>A≤20013

=> GTLN C =20013 khi 5-2x=0

=> 2x=5

=> x=\(\dfrac{5}{2}\)

vậy GTLN C = 20013 khi x=\(\dfrac{5}{2}\)

b) D = 7 - \(\left|\dfrac{2}{3}+\dfrac{1}{4}x\right|\)

do \(-\left|\dfrac{2}{3}+\dfrac{1}{4}x\right|\le0\forall x\)

=> 7-\(\left|\dfrac{2}{3}+\dfrac{1}{4}x\right|\le7\)

=> D≤7

=> GTLN D =7 khi \(\dfrac{2}{3}+\dfrac{1}{4}x=0\)

=> x=-\(\dfrac{8}{3}\)

1.Tính

a.\(\dfrac{7}{23}\left[(-\dfrac{8}{6})-\dfrac{45}{18}\right]=\dfrac{7}{23}.-\dfrac{12}{6}=-\dfrac{7}{6}\)

b.\(\dfrac{1}{5}\div\dfrac{1}{10}-\dfrac{1}{3}(\dfrac{6}{5}-\dfrac{9}{4})=2-(-\dfrac{7}{20})=\dfrac{47}{20}\)

c.\(\dfrac{3}{5}.(-\dfrac{8}{3})-\dfrac{3}{5}\div(-6)=-\dfrac{3}{2}\)

d.\(\dfrac{1}{2}.(\dfrac{4}{3}+\dfrac{2}{5})-\dfrac{3}{4}.(\dfrac{8}{9}+\dfrac{16}{3})=-\dfrac{19}{5}\)

e.\(\dfrac{6}{7}\div(\dfrac{3}{26}-\dfrac{3}{13})+\dfrac{6}{7}.(\dfrac{1}{10}-\dfrac{8}{5})=-\dfrac{61}{7}\)

Bài 2

a.\(1^2_5x+\dfrac{3}{7}=\dfrac{4}{5}\)

\(x=\dfrac{13}{49}\)

b.\(\left|x-1,5\right|=2\)

Xảy ra 2 trường hợp

TH1

\(x-1,5=2\)

\(x=3,5\)

TH2

\(x-1,5=-2\)

\(x=-0,5\)

Vậy \(x=3,5\) hoặc \(x=-0,5\) .

Ngại làm quá trời ơi,lần sau bn tách ra nhá làm vậy mỏi tay quá.

Ths bn nhé

Bài 1a:

3^3 = 3.3.3 = 9.3 = 27

b; (-3)^3 = - 3^3 = - 3.3.3 = - 9.3 = - 27

c; (1/2)^2 = 1/2.2 = 1/4

d; (-1/3)^2 = 1/3.3 = 1/9

e; (-2/5)^3 = - 2^3/5^3 = - 8/125

f; (-0,5)^2 = 0,5^2 = 0,025

Bài 1

g; (10,8)^0 = 1

h; (-2 1/3)^3 = (-7/3)^3 = - 343/27

i; (2^2)^2 = 4^2 = 16

j; [(-1/5)^2]^2

= (1/25)^2

= 1/625

k; 5^2.5^3

= 25.125

= 3125

l; (-3)^2.(-3)^3

= (-3)^5

= - 243

m; (1/5)^3.(1/5)^2

= 1/5^5

= 1/3125

n; (-2/3)^5 : (-2/3)^3

= (-2/3)^2

= 4/9

0; (-0,2)^5 : (-0,2)^3

= (-0,2)^2

= 0,04

p; (2017)^0. 2018

= 1.2018

= 2018

a: =>13/15x=3/4-1/2=1/4

=>x=15/52

b: =>x-3=4

=>x=7

c: =>2x+1=9

=>2x=8

=>x=4

d: =>x+3=-2

=>x=-5

e: =>(x+6)(x-4)=0

=>x=4 hoặc x=-6

f: =>(x-3)(x-7)=0

=>x=3 hoặc x=7