a) x=53

b) x=17

c) x=5;x=-5

d) x=17

e) x=5

g) ???

......

đáp số:?

\(a,\)\(-\frac{3}{5}\cdot x=\frac{1}{4}+0,75\)

\(-\frac{3}{5}\cdot x=\frac{1}{4}+\frac{3}{4}=\frac{4}{4}=1\)

\(x=1\div\left(-\frac{3}{5}\right)\)

\(x=-\frac{5}{3}\)

\(b,\)\(\left(\frac{1}{7}-\frac{1}{3}\right)\cdot x=\frac{28}{5}\times\left(\frac{1}{4}-\frac{1}{7}\right)\)

\(\left(\frac{3}{21}-\frac{7}{21}\right)\cdot x=\frac{28}{5}\cdot\left(\frac{7}{28}-\frac{4}{28}\right)\)

\(-\frac{4}{21}\cdot x=\frac{28}{5}\cdot\frac{3}{28}\)

\(-\frac{4}{21}\cdot x=\frac{3}{5}\)

\(x=\frac{3}{5}\div\left(-\frac{4}{21}\right)\)

\(x=-\frac{63}{20}\)

\(c,\)\(\frac{5}{7}\cdot x=\frac{9}{8}-0,125\)

\(\frac{5}{7}\cdot x=\frac{9}{8}-\frac{1}{8}\)

\(\frac{5}{7}\cdot x=1\)

\(x=1\div\frac{5}{7}\)

\(x=\frac{7}{5}\)

\(d,\)\(\left(\frac{2}{11}+\frac{1}{3}\right)\cdot x=\left(\frac{1}{7}-\frac{1}{8}\right)\cdot36\)

\(\left(\frac{6}{33}+\frac{11}{33}\right)\cdot x=\left(\frac{8}{56}-\frac{7}{56}\right)\cdot36\)

\(\frac{17}{33}\cdot x=\frac{1}{56}\cdot36\)

\(\frac{17}{33}\cdot x=\frac{9}{14}\)

\(x=\frac{9}{14}\div\frac{17}{33}\)

\(x=\frac{9}{14}\cdot\frac{33}{17}=\frac{297}{238}\)

a) x = 99/20

b) x = 7

c) x = 2

( chỉ lm đc đến đó thui nk )

Bài 1:

Câu a:

2/3.(x -5/6) + 1/4 = 22/9

2/3.(x -5/6) = 22/9 - 1/4

2/3.(x -5/6) = 79/36

x - 5/6 = 79/36 : 2/3

x - 5/6 = 79/24

x = 5/6 + 79/24

x = 33/8

Vậy x = 33/8

a, \(A=\frac{22}{27}\)

b,\(B=\frac{1}{57}\)

C,\(C=\frac{1}{50}\)

d, \(D=0\)

Câu a:

A = -1/2 - (-3)/5 + (-1/9) + 1/27 + 7/18 + 4/35 - (-2/7)

A = -1/2 + 3/5 - 1/9 + 1/27 + 7/18 + 4/35 + 2/7

A = (-1/2 - 1/9 + 7/18 + 1/27) + (3/5 + 4/35 + 2/7)

A = (-27/54 - 6/54 + 21/54 + 2/54) + (21/35 + 4/35 + 10/35)

A = -10/54 + 1

A = -5/27 + 1

A = 22/27

bài này không tồn tại x và y 

Câu hỏi thiếu dữ kiện bạn nhé

x=0 ,y=6 

chắc thế :|

1, =\(\frac{2\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}-\frac{1}{11}\right)}{4\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}-\frac{1}{11}\right)}=\frac{1}{2}\)

2, A=\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{99}{100}\)

= \(\frac{1\cdot2\cdot3\cdot....\cdot99}{2\cdot3\cdot4\cdot...\cdot100}=\frac{1}{100}\)

Vậy ......

hok tốt