rút gọn là được mà ! 

\(\frac{1}{2}\)

dau . la dau x

a/ 1.3.2.4.3.5.4.6.5.7/2.2.3.3.4.4.5.5.6.6=1.7/2.6=7/12

b/ ab.aba=abab

        aba=abab:ab

        aba=101

=>a=1     b=0

aabb : ab = 99 hay ab x 99 = aabb hay  ab x100 – ab = aabb

Ta có phép tính

                  __  ab00

                      ___ab___

                        aabb

 b=0 hoặc b=5

Nếu b=0 thì    a000 – a0 = aa00  (sai)

Nếu b=5 thì  

                   __  a500

                        __a5___

                        aa55

            a=4

c) thay a=7/6 b=6/5 thi 3 x a + 4 : b - 5/12=3.7/6+4.6/5-5/12=7/2+24/5-5/12=210/60+288/60-25/60=473/60

**** nha

\(\frac{1.3.2.4.3.5.4.6.5.7}{2.2.3.3.4.4.5.5.6.6}=\frac{\left(2.3.4.5.6\right).\left(3.4.5.7\right)}{\left(2.3.4.5.6\right).\left(2.3.4.5.6\right)}=\frac{7}{12}\)

\(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+....+\frac{1}{98\times99}+\frac{1}{99\times100}\)

\(=\frac{2-1}{1\times2}+\frac{3-2}{2\times3}+\frac{4-3}{3\times4}+....+\frac{99-98}{98\times99}+\frac{100-99}{99\times100}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\)

\(=1-\frac{1}{100}\)

\(=\frac{99}{100}\)

\(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{98\cdot99}+\frac{1}{99\cdot100}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)

\(=1-\frac{1}{100}\)

\(=\frac{99}{100}\)

1=3/3=4/4=5/5=...

=> 1+1/1*3=3/1*3=1/1

=> 1+1/2*4=4/2*4=1/2

=>...

Bieu thuc se con lai la 1*1/2*1/3*1/4*1/5

Vay A=1/120

\(A=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{2004\cdot2005}+\frac{1}{2005\cdot2006}\)

\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2004}-\frac{1}{2005}+\frac{1}{2005}-\frac{1}{2006}\)

\(A=1-\frac{1}{2006}=\frac{2005}{2006}\)

\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{2005.2006}\)

\(\Rightarrow A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2005}-\frac{1}{2006}\)

\(\Rightarrow A=1-\frac{1}{2006}\)

\(\Rightarrow A=\frac{2005}{2006}\)

kết quả cuối cùng là 198/100

\(\frac{2}{1X2}+\frac{2}{2X3}+\frac{2}{3X4}+...+\frac{2}{98X99}+\frac{2}{99X100}\)

\(2X\left(\cdot\frac{1}{1X2}+\frac{1}{2X3}+...+\frac{1}{98X99}+\frac{1}{99X100}\right)\)

\(2X\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)

\(2X\left(1-\frac{1}{100}\right)\)

\(2X\frac{99}{100}\)

\(\frac{99}{50}\)

mình chắc chắn là 8 . mình đã thi violympic rồi nên ko thể sai

câu 2:

A = 1/1*2 + 1/2*3  + 1/3*4 + ... + 1/98*99 + 1/99*100

A = 2-1/1*2 + 3-2/2*3 + 4-3/3*4 + ... + 99-98/98*99 + 100-99/99*100

A = 2/1*2 - 1/ 1*2 + 3/2*3 - 2/2*3 + 4/ 3*4 -3/3*4 +...+ 99/98*99 - 98/98*99 + 100/99*100 - 99/99*100

A = 1 - 1/ 100

A = 99 / 100

phần 2 mk ko =bít

bài 1, 3 mk ko bít

12×7×275×6×7×9​=(6×2)×7×(9×3)5×6×7×9​

Rút gọn \(6 , 7 , 9\):

\(= \frac{5}{2 \times 3} = \frac{5}{6} .\)

✅ Kết quả: \(\frac{5}{6}\).

a)

\(\frac{3 \times 4 \times 7}{12 \times 8 \times 9}\)

• Tử số = \(3 \times 4 \times 7 = 84\).
• Mẫu số = \(12 \times 8 \times 9 = 864\).

\(\frac{84}{864} = \frac{84 \div 12}{864 \div 12} = \frac{7}{72} .\)

✅ Kết quả: \(\frac{7}{72}\).

b)

\(\frac{4 \times 5 \times 6}{12 \times 10 \times 8}\)

• Tử số = \(4 \times 5 \times 6 = 120\).
• Mẫu số = \(12 \times 10 \times 8 = 960\).

\(\frac{120}{960} = \frac{1}{8} .\)

✅ Kết quả: \(\frac{1}{8}\).

c)

\(\frac{5 \times 6 \times 7}{12 \times 14 \times 15}\)

• Tử số = \(5 \times 6 \times 7 = 210\).
• Mẫu số = \(12 \times 14 \times 15 = 2520\).

\(\frac{210}{2520} = \frac{1}{12} .\)

✅ Kết quả: \(\frac{1}{12}\).

👉 Kết quả cuối cùng:

• a) \(\frac{7}{72}\)
• b) \(\frac{1}{8}\)
• c) \(\frac{1}{12}\)