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B = 5/2.1 +4/1.11+3/11.2+1/2.15+13/15.4
B/7 = 5/2.7 + 4/7.11 + 3/11.14 - 1/14.15 + 13/15.4
B/7 = 1/2 - 1/7 + 1/7 - 1/11 -...-1/15 - 1/28
B/7 = 1/2 - 1/28
B/7 = 13/28
B = 13/18 . 7 = 13/4
K MK NA <3
B = \(\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)\(=7\left(\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\right)\)\(=7\left(\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\right)\)
\(=7\left(\frac{1}{2}-\frac{1}{28}\right)=\frac{7}{2}-\frac{1}{4}=\frac{14}{4}-\frac{1}{4}=\frac{13}{4}\)
B = \(\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)
B = \(7.\left(\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\right)\)
B = \(7.\left(\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\right)\)
B = \(7.\left(\frac{1}{2}-\frac{1}{28}\right)\)
B = \(7.\frac{13}{28}\)
B = \(\frac{13}{4}\)
A = - (1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9 +1/9.10)
A = -( 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 + 1/9 - 1/10)
A = -( 1/4 - 1/10)
A = -3/20
B = 7(5/2.7 + 4/7.11 + 3/11.14 + 1/14.15 + 13/15.28)
B = 7(1/2 - 1/7 + 1/7 - 1/11 +......+ 1/15 - 1/28)
B = 7(1/2 - 1/28)
B = 7 . 13/28
B = 13/4
\(B=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)
\(B:7=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)
\(\frac{B}{7}=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.4}\)
\(\frac{B}{7}=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{15}-\frac{1}{28}\)
\(\frac{B}{7}=\frac{1}{2}-\frac{1}{28} \)
\(\frac{B}{7}=\frac{13}{28}\)
B=\(\frac{13}{28}\cdot7\)
B=\(\frac{13}{4}\left(=3\frac{1}{4}\right)\)
\(B=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)
\(\frac{B}{7}=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.4}\)
\(\frac{B}{7}=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{15}-\frac{1}{28}\)
\(\frac{B}{7}=\frac{1}{2}-\frac{1}{28}\)
\(\frac{B}{7}=\frac{13}{28}\)
\(B=\frac{13}{4}\left(=3\frac{1}{4}\right)\)
mình không biết đâu nhé
mình mới học lớp 4 thôi
đáp số mình học lớp 4
\(B=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)
\(\frac{B}{7}=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.4}\)
\(\frac{B}{7}=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{15}-\frac{1}{28}\)
\(\frac{B}{7}=\frac{1}{2}-\frac{1}{28}\)
\(\frac{B}{7}=\frac{13}{28}\)
\(B=\frac{13}{28}.7=\frac{13}{4}\)
B=\(\frac{13}{4}\)
B=5/1.2+4/1.11+3/11.2+1/2.15+13/15.4
B/7=5/2.7+4/7.11+3/11.14+1/14.15+13/15.4
B/7=1/2-1/7+1/7-1/11+...+1/15-1/28
B/7=1/2-1/28
B/7=13/28
B=13/28.7=13/4
Câu trả lời của bạn Ho nguyen ở dong 2 là sai vì 13/15.4 phai chuyen thanh 13/15/28
Nguyễn Đình Tuấn Hưng sai rồi vì \(\frac{13}{15.28}\)chứ không phải \(\frac{13}{\frac{15}{28}}\)
chính xác
B=\(\frac{5}{2.1}\)+\(\frac{4}{1.11}\)+\(\frac{3}{11.2}\)+\(\frac{1}{2.15}\)+\(\frac{13}{15.4}\) \(\frac{B}{5}\)=\(\frac{5}{2.5}\)+\(\frac{4}{5.11}\)+\(\frac{3}{11.10}\)+\(\frac{1}{10.15}\)+\(\frac{13}{15.20}\) \(\frac{B}{5}\)=\(\frac{1}{2}\)_\(\frac{1}{5}\)+\(\frac{1}{5}\)_\(\frac{1}{11}\)+\(\frac{1}{11}\)_\(\frac{1}{10}\)+\(\frac{1}{10}\)_\(\frac{1}{15}\)+\(\frac{1}{15}\)_\(\frac{1}{20}\) \(\frac{B}{5}\)=\(\frac{1}{2}\)_\(\frac{1}{20}\) \(\frac{B}{5}\)=\(\frac{10}{20}\)+ \(\left(-\frac{1}{20}\right)\) \(\frac{B}{5}\)=\(\frac{9}{20}\)
Cho mình hỏi tại sao lại nhân tất cả với 7