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5) 24*(15+49)+12*(50+42)
=24*64+12*92
=24*64+12*2*46
=24*64+24*46
=24*(64+46)
=24*110
=2640
Đặt \(A=\frac{19^{10}+1}{19^{11}+1};B=\frac{19^{19}+1}{19^{20}+1}\)
\(19A=\frac{19^{11}+19}{19^{11}+1}=1+\frac{18}{19^{11}+1}\)
\(19B=\frac{19^{20}+19}{19^{20}+1}=\frac{19^{20}+1+18}{19^{20}+1}=1+\frac{18}{19^{20}+1}\)
Ta có: \(19^{11}+1<19^{20}+1\)
=>\(\frac{18}{19^{11}+1}>\frac{18}{19^{20}+1}\)
=>\(\frac{18}{19^{11}+1}+1>\frac{18}{19^{20}+1}+1\)
=>19A>19B
=>A>B
1)(-6-25).(-6+2)=-31*(-4)=124
2) \(\frac{7\cdot3-9}{-6}=\frac{12}{-6}=-2\)
3) (-5+19).(-4)=14*(-4)=-56
4) \(\frac{872}{-6\cdot2+4}=\frac{872}{-12+4}=\frac{872}{-8}=-109\)
5) -3*7-4*(-5)+19=-21+20+19=18
6)\(18-\frac{10}{2}-71=18-5-71=-58\)
7) \(\frac{115}{-5}\cdot\left(-3\right)-8=69-8=61\)
8) \(\left(6\cdot8-\frac{20}{5}\right)+3\cdot\left(-7\right)=48-4-21=23\)
\(-\dfrac{25}{19}-\left(-\dfrac{6}{19}-\dfrac{1}{2022}\right)\)
\(=\dfrac{-25}{19}-\dfrac{-6}{19}-\dfrac{1}{2022}\)
\(=\dfrac{-25}{19}+\dfrac{6}{19}-\dfrac{1}{2022}\)
\(=\dfrac{-19}{19}-\dfrac{1}{2022}\)
\(=-1+\dfrac{1}{2022}\)
\(=-\dfrac{2021}{2022}\)