Câu hỏi của Sora

Question

Giúp em với mn.Mai em thi rùi😥😥 loading...

Lê Ng Hải Anh · Accepted Answer

a, $2Al+6HCl\rightarrow2AlCl_3+3H_2$

b, $n_{Al}=\dfrac{5,4}{27}=0,2\left(mol\right)$

Theo PT: $n_{HCl}=3n_{Al}=0,6\left(mol\right)\Rightarrow C_{M_{HCl}}=\dfrac{0,6}{0,1}=6\left(M\right)$

c, $m_{AlCl_3\left(5\%\right)}=50.5\%=2,5\left(g\right)$

$m_{AlCl_3\left(20\%\right)}=50.20\%=10\left(g\right)$

$\Rightarrow C\%_{AlCl_3}=\dfrac{2,5+10}{50+50}.100\%=12,5\%$

Câu trả lời:

a, $2Al+6HCl\rightarrow2AlCl_3+3H_2$

b, $n_{Al}=\dfrac{5,4}{27}=0,2\left(mol\right)$

Theo PT: $n_{HCl}=3n_{Al}=0,6\left(mol\right)\Rightarrow C_{M_{HCl}}=\dfrac{0,6}{0,1}=6\left(M\right)$

c, $m_{AlCl_3\left(5\%\right)}=50.5\%=2,5\left(g\right)$

$m_{AlCl_3\left(20\%\right)}=50.20\%=10\left(g\right)$

$\Rightarrow C\%_{AlCl_3}=\dfrac{2,5+10}{50+50}.100\%=12,5\%$