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a: 3x-5>15-x
=>4x>20
hay x>5
b: \(3\left(x-2\right)\left(x+2\right)< 3x^2+x\)
=>3x2+x>3x2-12
=>x>-12
\(x-\frac{2}{4}-\frac{2}{3}\ge5x-\frac{9}{12}\)
\(\Leftrightarrow x-\frac{7}{6}\ge5x-\frac{3}{4}\)
\(\Leftrightarrow-4x\ge\frac{5}{12}\)
\(\Leftrightarrow-\frac{5}{56}\ge x\)
a: 3x-5>15-x
=>3x+x>15+5
=>4x>20
=>x>5
b: \(3\left(x-2\right)\left(x+2\right)<3x^2+x\)
=>\(3\left(x^2-4\right)<3x^2+x\)
=>\(3x^2-12-3x^2-x<0\)
=>-x-12<0
=>x+12>0
=>x>-12
c: \(\left(2x+1\right)^2+3x\left(1-x\right)\le\left(x+2\right)^2\)
=>\(4x^2+4x+1+3x-3x^2\le x^2+4x+4\)
=>\(x^2+7x+1\le x^2+4x+4\)
=>7x+1<=4x+4
=>7x-4x<=4-1
=>3x<=3
=>x<=1
d: \(\frac{5x-20}{3}-\frac{2x^2+x}{2}>\frac{x\left(1-3x\right)}{3}-\frac{5x}{4}\)
=>\(\frac{4\left(5x-20\right)-6\left(2x^2+x\right)}{12}>\frac{4x\left(1-3x\right)-15x}{12}\)
=>\(4\left(5x-20\right)-6\left(2x^2+x\right)>4x\left(1-3x\right)-15x\)
=>\(20x-80-12x^2-6x>4x-12x^2-15x\)
=>14x-80>-11x
=>25x>80
=>\(x>\frac{80}{25}=\frac{16}{5}\)
e: 4-2x<=3x-6
=>-2x-3x<=-6-4
=>-5x<=-10
=>x>=2
f: \(\left(x+4\right)\left(5x-1\right)>5x^2+16x+2\)
=>\(5x^2-x+20x-4>5x^2+16x+2\)
=>19x-4>16x+2
=>3x>6
=>x>2
g: \(x\left(2x-1\right)-8<5-2x\left(1-x\right)\)
=>\(2x^2-x-8<5-2x+2x^2\)
=>-x-8<-2x+5
=>-x+2x<5+8
=>x<13
h: \(\frac{3x-1}{4}-\frac{3\left(x-2\right)}{8}-1>\frac{5-3x}{2}\)
=>\(\frac{2\left(3x-1\right)}{8}-\frac{3\left(x-2\right)}{8}-\frac88>\frac{4\left(5-3x\right)}{8}\)
=>2(3x-1)-3(x-2)-8>4(5-3x)
=>6x-2-3x+6-8>20-12x
=>3x-4>20-12x
=>15x>24
=>\(x>\frac{24}{15}\)
=>x>1,6
c: =>2x+4>=2x+2-3
=>4>=-1(luôn đúng)
a: 5x+10>3x+3
=>2x>-7
=>x>-7/2
2x + 4 > 5x - 11
<=> 2x - 5x > -11 - 4
<=> -3x > -15
<=> -3x : ( -3 ) < -15 : ( -3 )
<=> x < 5
Vậy tập nghiệm của bất phương trình là x < 5
a) 2x + 3 = 0 → x = -3/2. Vậy tập nghiệm của pt la S = {-3/2}.
k cho mk nha
\(a,2x-6< 0\Leftrightarrow2x>6\Leftrightarrow x>3\)
\(b,5x+2x< 4+25\Leftrightarrow7x< 29\Leftrightarrow x< \frac{29}{7}\)
\(c,-5x+6>8-10+8x\Leftrightarrow-5x-8x>8-10-6\)
\(-13x>-8\Leftrightarrow x< \frac{8}{13}\)
\(d,3x-12\le2-4x\Leftrightarrow3x+4x\le2+12\)
\(\Leftrightarrow7x\le14\Leftrightarrow x\le2\)
\(e,\frac{3\left(x-3\right)}{6}>\frac{2\left(2x-5\right)}{6}+\frac{6}{6}\Rightarrow3x-9>4x-10+6\)
\(\Leftrightarrow3x-4x>-4+9\Leftrightarrow x>-5\)
\(f,3\left(2x-3\right)>1+2\left(2+2x\right)\Leftrightarrow6x-9>1+4+4x\)
\(6x-4x>14\Leftrightarrow2x>14\Leftrightarrow x>7\)
Tự biểu diễn nha!
d: =>-2x<=1
=>x>=-1/2
e: =>3x<=10
=>x<=10/3
f: =>2x-6+12<=x+2
=>2x+6<=x+2
=>x<=-4