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a)\(\left(4\frac{5}{37}-3\frac45+8\frac{15}{29}\right)-\left(3\frac{5}{57}-6\frac{14}{29}\right)\)
=\(4\frac{5}{37}-3\frac45+8\frac{15}{29}-3\frac{5}{37}+6\frac{14}{29}\)
=\(\left(4\frac{5}{37}-3\frac{5}{37}\right)+\left(8\frac{15}{29}+6\frac{14}{29}\right)-3\frac45\)
=\(\left\lbrack\left(4-3\right)+\left(\frac{5}{37}-\frac{5}{37}\right)\right\rbrack+\left\lbrack\left(8+6\right)+\left(\frac{15}{29}\right.\right.\)+\(\frac{14}{29})\) -\(\frac{19}{5}\)
=\(1+0+14+1-\frac{19}{5}\)
=\(15+1-\frac{19}{5}\)
=\(16-\frac{19}{5}\)
=\(\frac{80}{5}-\frac{19}{5}\)
=\(\frac{61}{5}\)
j) \(\frac{8}{3}.\frac{2}{5}.\frac{3}{8}.10.\frac{19}{92}=\left(\frac{8}{3}.\frac{3}{8}\right).\left(\frac{2}{5}.10\right).\frac{19}{92}=1.4.\frac{19}{92}\)
\(=\frac{19}{23}\)
k)\(\frac{-5}{7}.\frac{2}{11}.\frac{-13}{17}.\frac{19}{12}.\frac{17}{13}=\left(\frac{2}{11}.\frac{19}{12}\right).\left(\frac{-13}{17}.\frac{17}{13}\right).\frac{-5}{7}\)
\(=\frac{-19}{66}.\frac{-5}{7}=\frac{95}{462}\)
l)\(\frac{12}{19}.\frac{7}{15}.\frac{-13}{17}.\frac{19}{12}.\frac{17}{13}=\left(\frac{12}{19}.\frac{19}{12}\right).\left(\frac{-13}{17}.\frac{17}{13}\right).\frac{7}{15}\)
\(=\frac{-7}{15}\)
cậu tham khảo trên này ạ, nếu đúng cho mk 1 t.i.c.k ạ, thank nhiều

\(\Rightarrow\left(\frac{13}{21}+x\right).\frac{7}{12}=\frac{13}{15}-\frac{7}{10}\)
\(\Rightarrow\left(\frac{13}{21}+x\right).\frac{7}{12}=\frac{1}{6}\)
\(\Rightarrow\frac{13}{21}+x=\frac{1}{6}.\frac{12}{7}=\frac{2}{7}\)
\(\Rightarrow x=\frac{2}{7}-\frac{13}{21}=\frac{-1}{3}\)
giải chi tiết nha
\(\Rightarrow\frac{13}{15}-\left(\frac{13}{21}+x\right)=\frac{6}{5}\)
\(\Rightarrow\left(\frac{13}{21}+x\right)=\frac{13}{15}-\frac{6}{5}=-\frac{1}{3}\)
\(\Rightarrow x=-\frac{1}{3}-\frac{13}{21}=-\frac{20}{21}\)
\(\Rightarrow\left(\frac{13}{21}+x\right)\times\frac{7}{12}=\frac{13}{15}-\frac{7}{10}\)
\(\Rightarrow\frac{13}{21}+x=\frac{1}{6}:\frac{7}{12}\)
\(\Rightarrow x=\frac{13}{21}-\frac{2}{7}\)
\(\Rightarrow x=\frac{1}{3}\)
\(\frac{13}{15}-\left(\frac{13}{21}+x\right)\times\frac{7}{12}=\frac{7}{10}\)
\(\left(\frac{13}{15}+x\right)\times\frac{7}{12}=\frac{13}{15}-\frac{7}{10}\)
\(\left(\frac{13}{15}+x\right)\times\frac{7}{12}=\frac{1}{6}\)
\(\frac{13}{15}+x=\frac{1}{6}:\frac{7}{12}\)
\(\frac{13}{15}+x=\frac{2}{7}\)
\(x=\frac{2}{7}-\frac{13}{15}\)
\(x=\frac{-61}{105}\)