- oxit axit: N2O: đinitơ oxit ; P2O5: điphotpho penta oxit; NO2: nitơ đioxit ; CO2: cacbon đioxit; SO3 : lưu huỳnh trioxit; NO: nitơ oxit; CO: cacbon oxit

- oxit bazo: Fe2O3: Sắt (III) oxit; K2O: Kali oxit; CuO: đồng (II) oxit; Al2O3: nhôm oxit; PbO: Chì (II) oxit; BaO: Bari oxit;

Mn2O7:mangan(VII)oxit; MnO2: mangan(IV)oxit ; ZnO: kẽm oxit

- Axit: H2SO4: axit sunfuric; HCl: axit clohidric

- Bazo: Ca(OH)2: canxi hidroxit

cảm ơn cậu :))

hại não ==

CÂN BẰNG PHƯƠNG TRÌNH

CH4 + 2O2 --> CO2 + 2H2O

2C2H2 + 5O2 --> 4CO2 + 2H2O

C3H8 + 5O2 --> 3CO2 + 4H2O

C2H4 + 3O2 --> 2CO2 + 2H2O

2C6H6 + 15O2 --> 12CO2 + 6H2O

CH₄ + 2O₂ \(\underrightarrow{to}\) CO₂ + 2H₂O

C₂H₂ + \(\dfrac{5}{2}\)O₂ \(\underrightarrow{to}\) 2CO₂ + H₂O

C₃H₈ + 5O₂ \(\underrightarrow{to}\) 3CO₂ + 4H₂O

C₂H₄ + 3O₂ \(\underrightarrow{to}\) 2CO₂ + 2H₂O

C₆H₆ + \(\dfrac{15}{2}\)O₂ \(\underrightarrow{to}\) 6CO₂ + 3H₂O

\(Fe_3O_4+2C\underrightarrow{t^o}3Fe+2CO_2\\ Na_2O+H_2O\rightarrow2NaOH\\ SO_2+\frac{1}{2}O_2\xrightarrow[V_2O_5]{t^o}SO_3\\ MgO+HCl\rightarrow MgCl_2+H_2O\\ Fe_2O_3+3CO\underrightarrow{t^o}2Fe+3CO_2\\ Fe_3O_4+4CO\underrightarrow{t^o}3Fe+4CO_2\\ CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\\ C_2H_4+3O_2\underrightarrow{t^o}2CO_2+2H_2O\\ C_2H_2+\frac{5}{2}O_2\underrightarrow{t^o}2CO_2+H_2O\\ C_6H_6+\frac{15}{2}O_2\underrightarrow{t^o}6CO_2+3H_2O\)

Phản ứng đầu không có \(t^o\) nhé!

a, FeO+CO-----------> Fe+CO₂

b, FeO₂ +CO-----------> FeO+CO₂

c, C₂H₄ + 3O₂ ------------> 2CO₂+ 2H₂O

\(Fe_xO_y+yCO\rightarrow xFe+yCO_2\)

CnH2n + 2nO2 → nCO2 + nH2O

CnH2n +2 +O2→ CO2 + H2O(?)

FexOy + (y-x)CO→ xFeO + (y-x)CO2

Cái còn lại ko bt làm.

\(C_nH_{2n}+\frac{3n}{2}O_2\rightarrow nCO_2+nH_2O\)

\(C_nH_{2n}+2+\left(\frac{3n+1}{2}\right)O_2\rightarrow nCO_2+\left(n+1\right)H_2O\)

\(Fe_xO_y+\left(y-x\right)CO\rightarrow xFeO+\left(y-x\right)CO_2\)

1) 2C_nH_2n + 3nO₂ -> 2nCO₂ + 2nH₂O

2) 2C_nH_2n+2 + (3n+1)O₂ -> 2nCO₂ + (2n+2)H₂O

3) 2C_nH_2n-2 + (3n-1)O₂ -> 2nCO₂ + (2n-2)H₂O

4) 2C_nH_2n-6 + (3n-3)O₂ -> 2nCO₂ + (2n-6)H₂O

5) 2C_nH_2n+2O + (3n+1)O₂ -> 2nCO₂ + (2n+2)H₂O

6) 4C_xH_y + (4x+y)O₂ -> 4xCO₂ + 2yH₂O

7) 4C_xH_yO_z + (4x+y-2z)O₂ -> 4xCO₂ + 2yH₂O

8)4C_xH_yO_zN_t +(4x+y-2z)O₂ ->4xCO₂ +2yH₂O +2tN₂

9) 4CH_x + (2y+x)O₂ -> 4CO_y + 2xH₂O

10) 2FeCl_x + (3-x)Cl₂ -> 2FeCl₃

2)C_nH_2n+2+(3n+1)/2O₂ -> nCO₂+(n+1)H₂O

3)C_nH_2n-2+(3n-1)/2O₂->nCO₂+(n-1)H₂O

4)C_nH_2n-6+3/2(n-1)O₂ -> nCO₂+(n-3)H₂O

a)C_xH_y+(x+\(\dfrac{y}{4}\))O₂->xCO₂+\(\dfrac{y}{2}\)H₂O

b)C_xH_yO_z+(x+\(\dfrac{y}{4}\)-\(\dfrac{z}{2}\))O₂->xCO₂+\(\dfrac{y}{2}\)H₂O

c)Fe_xO_y+yCO->xFe+yCO₂

d)Fe₃O₄+8HCl->FeCl₂+2FeCl₃+4H₂O

a)2C_xH_y+(4x+y)O₂->xCO₂+2yH₂O

b)C_xH_yO_z+(x+\(\dfrac{y}{4}\)-\(\dfrac{z}{2}\))O₂->xCO₂+\(\dfrac{y}{2}\)H₂O

c)Fe_xO_y+yCO->xFe+yCO₂

d)Fe₃O₄+8HCl->FeCl₂+2FeCl₃+4H₂O

Cân bằng các phương trình hóa học sau :

a ) 4Fe( OH )2 + O2 + 2H2O ---> 4Fe ( OH)3

b ) 4FeS2 + 11O2 ---> 2Fe2O3 + 8SO2

c ) 6KOH + P2O5 ---> 2K3PO4 + 3H2O

d ) 3Mg(OH)2 + 2H3PO4 ---> Mg3(PO4)2 + 6H2O

e ) Na + H2O ---> NaOH + H2

f ) Fe2O3 + 3CO ---->2 Fe + 3CO2

g ) Fe3O4 + 4CO ---> 3Fe + 4CO2

h ) Na2CO3 + 2HCl ---> 2NaCl + CO2 + H2O

i ) 2C3H8O + 9O2 ---> 6CO2 + 8H2O

a ) 4Fe( OH )₂ + O₂ + 2H₂O ---> 4Fe ( OH)₃

b ) 4FeS₂ + 11O₂ ---> 2Fe₂O₃ + 8SO₂

c ) 6KOH + P₂O₅ ---> 2K₃PO₄ + 3H₂O

d ) 3Mg ( OH)₂ + 2H₃PO₄ ---> \(Mg_3\left(PO_4\right)_2\)+ 6H₂O

e ) 2Na + 2H₂O ---> 2NaOH + H₂

f ) Fe₂O₃ + 3CO ----> 2Fe + 3CO₂

g ) Fe₃O₄ + 4CO ---> 3Fe + 4CO₂

h ) Na₂CO₃ + 2HCl ---> 2NaCl + CO₂ + H₂O

i ) 2C₃H₈O + 9O₂ ---> 6CO₂ + 8H₂O

a) Fe_xO_y + yH₂ → xFe + yH₂O

b) 2C_xH_y +\(\frac{4x-y}{2}O_2\) → 2xCO₂ + yH₂O

c) 2C_xH_yO_z + \(\frac{4x+y-2z}{2}\)O₂ → 2xCO₂ + yH₂O

d) Fe_xO_y + 2yHCl → xFeCl_2y/x + yH₂O

đ) C_nH_2n+2 + \(\frac{3n+1}{2}\)O₂ → nCO₂ + (n+1)H₂O

e) 2C_nH_2n + 3nO₂ → 2nCO₂ + 2nH₂O

f) C_nH_{2n - 2} + \(\frac{3n-1}{2}\)O₂ → nCO₂ + (n-1)H₂O

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