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a: \(A=\dfrac{16^5\cdot15^5}{2^{10}\cdot3^5\cdot5^4}=\dfrac{2^{20}\cdot3^5\cdot5^5}{2^{10}\cdot3^5\cdot5^4}=2^{10}\cdot5=5120\)
b: \(B=\dfrac{2^{15}\cdot3+2^{19}\cdot10}{2^{12}\cdot26}=\dfrac{2^{15}\left(3+2^4\cdot10\right)}{2^{13}\cdot13}=2^2\cdot\dfrac{163}{13}=\dfrac{652}{13}\)
a: \(-\frac{10}{3}+\frac{13}{10}-\frac16+\frac{7}{10}\)
\(=\left(-\frac{10}{3}-\frac16\right)+\left(\frac{13}{10}+\frac{7}{10}\right)\)
\(=-\frac{21}{6}+\frac{20}{10}=-\frac72+2=-\frac32\)
b: \(1-\frac{20}{6}+\frac{39}{30}-\frac{4}{24}+\frac{34}{50}\)
\(=1-\frac{20}{6}+\frac16+1,3+0,68\)
\(=1-\frac{19}{6}+1,98=2,98-\frac{19}{6}=\frac{298}{100}-\frac{19}{6}=\frac{-56}{300}=\frac{-14}{75}\)
c: \(\frac{15}{24}-\frac{6}{26}+\frac{28}{48}-\frac{30}{39}+\frac{10}{24}\)
\(=\left(\frac{15}{24}+\frac{10}{24}+\frac{28}{48}\right)-\left(\frac{3}{13}+\frac{10}{13}\right)\)
\(=\left(\frac{25}{24}+\frac{14}{24}\right)-1=\frac{39}{24}-1=\frac{15}{24}=\frac58\)
d: \(-\frac{5}{10}+\frac{12}{28}-\frac{3}{27}-\frac{7}{18}+\frac{20}{35}\)
\(=-\frac12+\frac37-\frac19-\frac{7}{18}+\frac47\)
\(=\left(-\frac12-\frac19-\frac{7}{18}\right)+\left(\frac37+\frac47\right)=-1+1=0\)
nhóm cứ hai số liên tiếp lại vs nhâu sẽ đk quy luật tổng của toàn số -2
A=2-4+6-8+10-12+14-16+18-20+22-24+26-28+30-32
A= (-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)
A= -16
\(\dfrac{4}{1.3}+\dfrac{12}{3.9}+\dfrac{16}{9.17}+\dfrac{30}{17.32}+\dfrac{26}{32.45}+\dfrac{10}{45.50}+\dfrac{34}{50.67} =2.\left(\dfrac{2}{1.3}+\dfrac{6}{3.9}+\dfrac{8}{9.17}+\dfrac{15}{17.32}+\dfrac{13}{32.45}+\dfrac{5}{45.50}+\dfrac{17}{50.67}\right)=2\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{17}+...\dfrac{1}{45}-\dfrac{1}{50}+\dfrac{1}{50}-\dfrac{1}{67}\right)=2\left(1-\dfrac{1}{67}\right)=2.\dfrac{66}{67}=\dfrac{132}{67}\)