a, \(\left(-a\right)\left(b-c-d\right)=-ab+ac+ad\)

b, \(x\left(y-z-2\right)=xy-xz-2x\)

c, \(\left(-3\right)\left(2x-5\right)=-6x+15\)

a) N = -{-(a + b) – [(a – b ) – (a + b)]}

N = - { - a + b - [ a - b - a + b ]}

N = - { -a + b - 0}

N = a - b

b) N = -5 - ( -3)

N = -2

hok tốt!!!

                                                 Bài giải

a, N = -{ -( a + b ) - [ ( a - b ) - ( a + b ) ]}

    N =  - { - a - b - [ a - b - a - b ]}

    N = - { - a - b + 2b } = - { - a + b } = a - b

b, Thay a = - 5 ; b = - 3 vào biểu thức N ta có :

N = - 5 + 3 = - 2

A = B-(B+A-C)+A

A = b - b - a + c + a 

A = c

B = a + a + 3 - 1 - 2 + a - 2

B = 3a -2

A= ( a - b) - ( a - b -c ) - ( 2a + c - a)

\(=a-b-a+b+a-2a-c+a\)

\(=\left(a-a+a+a-2a\right)+\left(-b+b\right)+c\)

\(=\left(2a-2a\right)+c\)

\(=c\)

A = (a - b) - (a - b - c) - (2a + c - a)

\(=a-b-a+b+c-2a-c+a\)

\(=\left(a-a+a+a-2a\right)+\left(-b+b\right)+c\)

\(=\left(2a-2a\right)+0+c\)

\(=c\)

N = -{a - b - (a - b - a - b)} = - {a - b - a + b + a + b} = -{a + b} = - a - b

a)\(N=-\left\{-\left(a+b\right)-\left[\left(a-b\right)-\left(a+b\right)\right]\right\}\)

\(N=-\left\{-\left(a+b\right)-\left[a-b-a-b\right]\right\}\)

\(N=-\left\{-a-b+2b\right\}\)

\(N=a+b-2b\)

\(N=a-b\)

b) \(N=-5-\left(-3\right)\)

\(N=-5+3\)

\(N=-2\)

a)(x+y).(x+y)=x(x+y)+y(x+y)=x^2+xy+xy+y^2=x^2+2xy+y^2

b)(x-y).(x-y)=x(x-y)-y(x-y)=x^2-xy-xy+y^2=x^2-2xy+y^2

c)(x+y).(x-y)=x(x-y)+y(x-y)=x^2-2xy+xy-y^2=x^2-y^2

nhớ liek nhé

a ,  = \(x^2+2xy+y^2\)

b, = \(x^2-2xy+y^2\)

c = \(x^2-y^2\)

(a+b)-(a-b)+(a-c)-(a+c)=a+b-a+b+a-c-a-c=a-a+b+b+a-a-c-c=2b-2c=2(b-c)

nhớ k cho mink nhé