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a.-1,75-(-\(\dfrac{1}{9}\)-2\(\dfrac{1}{8}\))
-1,75-\(\dfrac{1}{9}+\dfrac{17}{8}\)
\(-\dfrac{7}{4}-\dfrac{1}{9}+\dfrac{17}{8}\)
\(\dfrac{-126}{72}-\dfrac{8}{72}+\dfrac{153}{72}\)
=\(\dfrac{19}{72}\)
b.\(\dfrac{-1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\left(\dfrac{21}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\dfrac{21}{8}+\dfrac{1}{3}\)
\(\dfrac{-2}{24}-\dfrac{63}{24}+\dfrac{64}{24}\)
=\(\dfrac{-1}{24}\)
1.
a) \(\frac{-7}{9}.2\frac{3}{4}=\frac{-7}{9}.\frac{11}{4}=\frac{-77}{36}\)
b) \(\frac{2}{3}+\frac{1}{3}.\frac{-2}{5}=\frac{2}{3}+\frac{-2}{15}=\frac{8}{15}\)
c) \(\frac{3}{4}.15\frac{1}{3}-\frac{3}{4}.43\frac{1}{3}=\frac{3}{4}.\frac{46}{3}-\frac{3}{4}.\frac{130}{3}=\frac{23}{2}-\frac{65}{2}=-21\)
d) \(\left(-49,1\right).\frac{13}{27}-58,9.\frac{13}{27}=\frac{13}{27}.\left(-49,1-58,9\right)=\frac{13}{27}.\left(-108\right)=-52\)
e) \(0,375:\left(-4,5\right)=\frac{-1}{12}\)
f) \(3\frac{1}{7}:\left(-1\frac{3}{7}\right)=\frac{22}{7}:\frac{-10}{7}=\frac{-11}{5}\)
g) \(9\frac{1}{3}:4\frac{2}{3}-2=\frac{28}{3}:\frac{14}{3}-2=2-2=0\)
h) \(\left(7\frac{3}{4}:0,3125+4,5.2\frac{2}{45}\right):\left(-8,5\right)=\left(\frac{31}{4}:\frac{5}{16}+\frac{9}{2}.\frac{92}{45}\right):\frac{-17}{2}=\left(\frac{124}{5}+\frac{46}{5}\right):\frac{-17}{2}=34:\frac{-17}{2}=-4\)
Bài 1 : Tính:
a)
\(\frac{-7}{9}.2\frac{3}{4}=\frac{-7}{9}.\frac{11}{4}=\frac{-77}{36}\)
b)
\(\frac{2}{3}+\frac{1}{3}.\frac{-2}{5}=\frac{2}{3}+\frac{-2}{15}=\frac{10}{15}+\frac{-2}{15}=\frac{8}{15}\)
c)
\(\frac{3}{4}.15\frac{1}{3}-\frac{3}{4}.43\frac{1}{3}=\frac{3}{4}.\frac{46}{3}-\frac{3}{4}.\frac{130}{3}\)\(=\frac{23}{2}-\frac{65}{2}=\frac{-42}{2}=-21\)
....
Tự lm tiếp dạng như v
Bài 2 :
\(A=\frac{-6}{11}.\frac{7}{10}.\frac{11}{-6}.-20=\left(\frac{-6}{11}.\frac{11}{-6}\right).\left(\frac{7}{10}.-20\right)\)\(=1.\left(-14\right)=-14\)
.....
Bài 3 :
\(\frac{3}{7}.x-\frac{2}{5}.x=\frac{-17}{35}\)
\(\Leftrightarrow\frac{3}{7}-\frac{2}{5}.x=\frac{-17}{35}\)
\(\Leftrightarrow\frac{1}{35}x=\frac{-17}{35}\)
\(\Leftrightarrow x=\frac{-17}{35}:\frac{1}{35}\)
\(\Leftrightarrow x=\frac{-17}{35}.35=-17\)
A = ( 4/4 + 2/3 ) - ( 51/3 - 6/5 ) - ( 6 - 7/4 + 3/2 )
Sau đó quy đồng rồi trừ cả là đc
B tương tự
C=13/15
D cx thế . Bạn tự vận dụng đi . Xl vì ko giải đc . Mik đang gấp
1.
a)x=-1/30
b)1/15
c)x=9/2 hoặc 1/2
2.
a)12/25
b)-23/66
giải ra hộ bạn ơi ;-;
Bài 1:
a)
\(x-\dfrac{1}{15}=-\dfrac{1}{10}\\ \Rightarrow x=-\dfrac{1}{10}+\dfrac{1}{15}\\ \Rightarrow x=-\dfrac{1}{30}\)
b)
\(-x-\dfrac{1}{3}=-\dfrac{2}{5}\\ \Rightarrow-x=-\dfrac{2}{5}+\dfrac{1}{3}\\ \Rightarrow-x=-\dfrac{1}{15}\\ \Rightarrow x=\dfrac{1}{15}\)
c)
\(\left|2x-5\right|=4\\ \Rightarrow\left[{}\begin{matrix}2x-5=-4\\2x-5=4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=1\\2x=9\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{9}{2}\end{matrix}\right.\)
Bài 2:
a) \(-\dfrac{6}{25}+\left|-\dfrac{4}{5}\right|-\left|\dfrac{2}{25}\right|\)
\(=\dfrac{-6}{25}+\dfrac{4}{5}-\dfrac{2}{25}\\ =\dfrac{-6}{25}+\dfrac{20}{25}-\dfrac{2}{25}\\ =\dfrac{12}{25}\)
b) \(\left(-\dfrac{5}{9}\right).\dfrac{3}{11}+\left(-\dfrac{13}{18}\right).\dfrac{3}{11}\)
\(=\dfrac{3}{11}.\left[\left(-\dfrac{5}{9}\right)+\left(-\dfrac{13}{18}\right)\right]\)
\(=\dfrac{3}{11}\left(-\dfrac{5}{9}-\dfrac{13}{18}\right)\)
\(=\dfrac{3}{11}\left(-\dfrac{10}{18}-\dfrac{13}{18}\right)\)
\(=\dfrac{3}{11}.\left(-\dfrac{23}{18}\right)\)
\(=-\dfrac{23}{66}\)
Bài 1:
a) Ta có: \(x-\dfrac{1}{15}=-\dfrac{1}{10}\)
nên \(x=\dfrac{-1}{10}+\dfrac{1}{15}\)
hay \(x=-\dfrac{1}{30}\)
b) Ta có: \(-x-\dfrac{1}{3}=-\dfrac{2}{5}\)
nên \(-x=\dfrac{-2}{5}+\dfrac{1}{3}=-\dfrac{1}{15}\)
hay \(x=\dfrac{1}{15}\)
c) Ta có: \(\left|2x-5\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-5=4\\2x-5=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=9\\2x=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=\dfrac{1}{2}\end{matrix}\right.\)
Bài 2:
a) \(\dfrac{-6}{25}+\left|-\dfrac{4}{5}\right|-\left|\dfrac{2}{25}\right|\)
\(=\dfrac{-6}{25}+\dfrac{4}{5}-\dfrac{2}{25}\)
\(=\dfrac{-8}{25}+\dfrac{4}{5}=\dfrac{12}{25}\)
b) \(\left(-\dfrac{5}{9}\right)\cdot\dfrac{3}{11}+\left(-\dfrac{13}{18}\right)\cdot\dfrac{3}{11}\)
\(=\dfrac{3}{11}\cdot\left(-\dfrac{5}{9}-\dfrac{13}{18}\right)\)
\(=\dfrac{3}{11}\cdot\dfrac{-23}{18}=-\dfrac{23}{66}\)