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2. [(195 + 35: 7) : 8 + 195] - 400
=2.[(195 + 5) : 8 +195] - 400
=2.(200 : 8 + 195) - 400
=2.(25 + 195) - 400
=2.220-400
=440-400
=40
4.{3^2[(5^2 + 2^3) :11] -26} + 2010
=4.{3^2[(25 + 8) : 11] - 26 } +2010
=4.[3^2(33 :11)- 26] + 2010
=4.(3^2 . 3 - 26) + 2010
=4.(32+1 - 26) + 2010
=4.(3^3 - 26) + 2010
=4.(27-26) + 2010
=4.1+2010
=2014
Cách tính của minh hơi dài dòng một chút , xin lỗi bạn nha
62 : 32 + 52 - 33 . 3
= ( 32 . 22 ) : 32 + 25 - 34
= 32 . 22 : 32 + 35 - 81
= 4 + 35 - 81
= 39 - 81
= -42
b) -26 - ( x - 7 ) = 0
x - 7 = -26 - 0
x - 7 = -26
x = -26 + 7
x = -19
Bài 2 :
a) 3 - ( 17 - x ) = -12
( 17 - x ) = 3 - ( -12 )
( 17 - x ) = 15
x = 17 - 15
x = 2
[(195+35/7)/8+195]*2-400
=[(195+5)/8+195]*2-400
=[200/8+195]*2-400
=[25+195]*2-400
=220*2-400
=440-400
=40
a: \(\left(5x+3^4\right)\cdot6^8=6^9\cdot3^4\)
=>\(5x+3^4=6^9\cdot\frac{3^4}{6^8}=6\cdot3^4\)
=>\(5x=6\cdot3^4-3^4=5\cdot3^4\)
=>\(x=3^4=81\)
b: \(92-2x=2\cdot4^2-3\cdot4+120:15\)
=>\(92-2x=2\cdot16-12+8=24-12+8=12+8=20\)
=>2x=92-20=72
=>x=36
c: \(5^3\left(3x+2\right):13=10^3:\left(13^5:13^4\right)\)
=>\(125\left(3x+2\right):13=10^3:13\)
=>\(125\left(3x+2\right)=10^3=1000\)
=>3x+2=8
=>3x=6
=>x=2
a, = 390
b, = 2004
a) 390
b) 2004
a) \(2\cdot\left[\left(195+35:7\right):8+195\right]-400\)
\(=2\cdot\left[\left(195+5\right):8+195\right]-400\)
\(=2\cdot\left(200:8+195\right)-400\)
\(=2\cdot220-400\)
\(=440-400=40\)
b) \(4\cdot\left\{3^2\cdot\left[\left(5^2+2^3\right):11^1\right]-26\right\}+2000\)
\(=4\cdot\left[3^2\cdot\left(33:11\right)-26\right]+2000\)
\(=4\cdot\left(3^2\cdot3-26\right)+2000\)
\(=4\cdot1+2000=4+2000+2004\)
\(a,\text{ }2\cdot\left(\left\{195+35\text{ : }7\right\}\text{ : }8+195\right)-400\)
\(=2\cdot\left(\left\{195+5\right\}\text{ : }8+195\right)-400\)
\(=2\cdot\left(200\text{ : }8+195\right)-400\)
\(=2\cdot\left(25+195\right)-400\)
\(=2\cdot220-400\)
\(=440-400\)
\(=40\)