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\(1,x.\left(x+7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x+7=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=-7\end{cases}}}\)
\(2,\left(x+12\right).\left(x-3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+12=0\\x-3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-12\\x=3\end{cases}}}\)
\(3,\left(-x+5\right).\left(3-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}-x+5=0\\3-x=0\end{cases}\Rightarrow\orbr{\begin{cases}-x=-5\\x=3\end{cases}\Rightarrow}\orbr{\begin{cases}x=5\\x=3\end{cases}}}\)
\(4,24:\left(3x-2\right)=-3\)
\(3x-2=-8\)
\(3x=-6\)
\(x=-2\)
\(5,-45:5\left(-3-2x\right)=3\)
\(5\left(-3-2x\right)=-15\)
\(-3-2x=-3\)
\(2x=0\)
\(x=0\)
\(6,x.\left(2+x\right)\left(7-x\right)=0\)
\(x=0\) hoặc \(\orbr{\begin{cases}2+x=0\\7-x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-2\\x=7\end{cases}}}\)
\(7,\left(x-1\right)\left(x+2\right)\left(-x+3\right)=0\)
TH1: x-1=0 TH2 : x+2=0 TH3: -x+3=0
x=1 x=-2 -x=-3 => x=3
a) 2(4x-8)-7(3+x)=|-4|.(3-2)
8x-16-21-7x=4
8x-7x=4+16+21
x=41
Vậy x=41
b) 8(x-|-7|)-6(x-2)=|-8|.6-50
8x-56-6x+12=8.6-50
8x-6x=48-50+56-12
2x=42
x=42:2
x=21
Vậy x=21
c) -7(5-x)-2(x-10)=15
-35+7x-2x+20=15
7x-2x=15+35-20
5x=30
x=30:5
x=6
Vậy x=6
d) 4(x-1)-3(x-2)=-|-5|
4x-4-3x+6=-5
4x-3x=-5+4-6
x=-7
Vậy x=-7
e) -4(x+1)+(89x-3)=24
-4x-4+89x-3=24
-4x+89x=24+4+3
85x=31
x=31/85
f) 5(x-30)-2(x+6)=9
5x-150-2x-12=9
5x-2x=9+150+12
3x=171
x=171:3
x=57
Vậy x=57
g) -3(x-5)+6(x+2)=9
-3x+15+6x+12=9
-3x+6x=9-15-12
3x=-18
x=-18:3
x=-6
Vậy x=-6
h) 7(x-9)-5(6-x)=-6+11x
7x-63-30+5x=-6+11x
7x+5x-11x=-6+62+30
x=86
Vậy x=86
k) 10(x-7)-8(x+5)=6.(-5)+24
10x-70-8x-40=-30+24
10x-8x=-30+24+70+40
2x=104
x=104:2
x=52
Vậy x=52
cái chữ này cj nhìn khó hiểu quá nên em thông cảm nếu muốn bt đáp án thì viết rõ ra đc chứ^^
a. 3/5 . 15/7 - 15/7 . 8/5
= 15/7(3/5-8/5)
=15/7. -\(\frac{1}{1}\)
=22/7
b. 4/5 . 1 3/7 + 4/5 . 4/7
=4/5(13/7+4/7)
=4/5.17/7
= 68/35
Bài 1:
\(\frac{3}{5}+\frac{4}{15}=\frac{9}{15}+\frac{4}{15}=\frac{13}{15}\)
\(\frac{5}{6}:\frac{-7}{12}=\frac{5}{6}.\frac{-12}{7}=\frac{-60}{42}=\frac{-10}{7}\)
\(\frac{-21}{24}:\frac{-14}{8}=\frac{-21}{24}.\frac{-8}{14}=\frac{168}{336}=\frac{1}{2}\)
\(\frac{4}{5}:\frac{-8}{15}=\frac{4}{5}.\frac{-15}{8}=\frac{-60}{40}=\frac{-3}{2}\)
\(\frac{5}{12}-\frac{-7}{6}=\frac{5}{12}+\frac{7}{6}=\frac{5}{12}+\frac{14}{12}=\frac{19}{12}\)
\(\frac{-15}{16}.\frac{8}{25}=\frac{-120}{400}=\frac{-3}{10}\)
Bài 2 :
\(6\frac{4}{5}-\left(1\frac{2}{3}+3\frac{4}{5}\right)\)
\(=\frac{34}{5}-\left(\frac{5}{3}+\frac{19}{5}\right)\)
\(=\frac{34}{5}-\frac{5}{3}-\frac{19}{5}\)
\(=\left(\frac{34}{5}-\frac{19}{5}\right)-\frac{5}{3}\)
\(=3-\frac{5}{3}\)
\(=\frac{4}{3}\)
\(6\frac{5}{7}-\left(1\frac{2}{3}+2\frac{5}{7}\right)\)
\(=\frac{47}{7}-\left(\frac{5}{3}+\frac{19}{7}\right)\)
\(=\frac{47}{7}-\frac{5}{3}-\frac{19}{7}\)
\(=\left(\frac{47}{7}-\frac{19}{7}\right)-\frac{5}{3}\)
\(=4-\frac{5}{3}\)
\(=\frac{7}{3}\)
\(\frac{4}{19}.\frac{-3}{7}+\frac{-3}{7}.\frac{15}{19}+\frac{5}{7}\)
\(=\left(\frac{4}{19}+\frac{15}{19}\right).\frac{-3}{7}+\frac{5}{7}\)
\(=1.\frac{-3}{7}+\frac{5}{7}\)
\(=\frac{-3}{7}+\frac{5}{7}\)
\(=\frac{2}{7}\)
\(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{5}{9}.1\)
\(=\frac{5}{9}\)
Bài 3 :
\(\frac{x}{5}=\frac{2}{3}\)
\(\Rightarrow x.3=5.2\)
\(\Rightarrow x.3=10\)
\(\Rightarrow x=\frac{10}{3}\)
\(\frac{x}{3}-\frac{1}{2}=\frac{1}{5}\)
\(\frac{x}{3}=\frac{1}{5}+\frac{1}{2}\)
\(\frac{x}{3}=\frac{7}{10}\)
\(\Rightarrow x.10=3.7\)
\(\Rightarrow x.10=21\)
\(\Rightarrow x=\frac{21}{10}\)
\(\frac{4}{5}+x=\frac{2}{3}\)
\(x=\frac{2}{3}-\frac{4}{5}\)
\(x=\frac{-2}{15}\)
\(\frac{3}{4}-x=\frac{1}{3}\)
\(x=\frac{3}{4}-\frac{1}{3}\)
\(x=\frac{5}{12}\)
\(x-\frac{5}{9}=\frac{-2}{3}\)
\(x=\frac{-2}{3}+\frac{5}{9}\)
\(x=\frac{-1}{9}\)
\(\frac{1}{2}x+\frac{1}{2}=\frac{5}{2}\)
\(\frac{1}{2}x=\frac{5}{2}-\frac{1}{2}\)
\(\frac{1}{2}x=2\)
\(x=2:\frac{1}{2}\)
\(x=4\)
\(\frac{-2}{3}-\frac{1}{3}.\left(2x-5\right)=\frac{3}{2}\)
\(\frac{1}{3}.\left(2x-5\right)=\frac{-2}{3}-\frac{3}{2}\)
\(\frac{1}{3}.\left(2x-5\right)=\frac{-19}{10}\)
\(2x-5=\frac{-19}{10}:\frac{1}{3}\)
\(2x-5=\frac{-57}{10}\)
\(2x=\frac{-57}{10}+5\)
\(2x=\frac{-7}{10}\)
\(x=\frac{-7}{10}:2\)
\(x=\frac{-7}{20}\)
\(3\frac{1}{3}+\frac{5}{6}x=3\frac{2}{1}\)
\(\frac{10}{3}+\frac{5}{6}x=5\)
\(\frac{5}{6}x=5-\frac{10}{3}\)
\(\frac{5}{6}x=\frac{5}{3}\)
\(x=\frac{5}{3}:\frac{5}{6}\)
\(x=2\)
\(\frac{3}{8}-\frac{1}{6}x=\frac{1}{4}\)
\(\frac{1}{6}x=\frac{3}{8}-\frac{1}{4}\)
\(\frac{1}{6}x=\frac{1}{8}\)
\(x=\frac{1}{8}:\frac{1}{6}\)
\(x=\frac{3}{4}\)
Bài 4 :
Ta có :\(\frac{2}{3}=\frac{2.4}{3.4}=\frac{8}{12};\frac{1}{4}=\frac{1.3}{4.3}=\frac{3}{12}\)
Vì 8 > 3 nên \(\frac{8}{12}>\frac{3}{12}\)hay \(\frac{2}{3}>\frac{1}{4}\)
Ta có : 10 > 8 nên \(\frac{7}{10}< \frac{7}{8}\)
Ta có : \(\frac{14}{21}=\frac{14.24}{21.24}=\frac{336}{504};\frac{60}{72}=\frac{60.7}{72.7}=\frac{420}{504}\)
Vì 336 < 420 nên \(\frac{336}{504}< \frac{420}{504}\)hay \(\frac{14}{21}< \frac{60}{72}\)
Ta có : \(\frac{11}{45}=\frac{11.37}{45.37}=\frac{407}{1665};\frac{22}{37}=\frac{22.45}{45.37}=\frac{990}{1665}\)
Vì 407 < 990 nên \(\frac{407}{1665}< \frac{990}{1665}\)hay \(\frac{11}{45}< \frac{22}{37}\)
Bài 1
a.61/60
b.4/35
c.-10/7
d.1/ hai
e.3/- hai
f.-hai3/hai muoi
g.19/1hai
h.-3/10
Bài hai.
a.4/3
b.9/4
c.5/4
d.11/7
e.-6/5
f-hai/3
g.hai/7
h.5/9
Bài 3.
a.10/3
b.hai1/10
c.hai/3
d.5/1hai
e.-1/9
f.4
g.
h.3/4
i.1/5
bài5
A. -hai5/19 ; -13/19 ; 9/19 ; 14/19 ;hai0/19 ; 30/19 ; 4hai/19