có duyên ghê mấy cách cũng được miễn sau 2 cách

c1,

a,1+2+3+1=7

b,3+5+8+36+9=61

c,1+2+3+4+5+6+7+8+9=45

c2,

a,(1+1)+(2+3)=7

b,(3+5+8)+(36+9)=61

c,(9+1)+(8+2)+(7+3)+(6+4)+5=45

cich cho minh nha

Giải hộ mk nha!

a, 6-15=-9 

6+4=10 và 15+5 =20

\(\frac{a}{4}=\frac{b}{6}\)\(,\)\(\frac{b}{5}=\frac{c}{8}\)

\(\Rightarrow\left(a=\frac{2b}{3}\right)\)\(,\)\(\left(b=\frac{5c}{8}\right)\)

\(\Rightarrow3a=2b\)\(,\)\(8b=5c\)

\(\Rightarrow b=\frac{3a}{2}\)\(,\)\(c=\frac{12a}{5}\)

\(\Rightarrow a=10\)\(,\)\(b=15\)\(,\)\(c=24\)

\(\frac{a}{4}=\frac{b}{6}.\frac{b}{5}=\frac{c}{8}\)

\(\Rightarrow\left(3a=2b,8b=5c\right)\)

\(\Rightarrow b=\frac{3a}{2}.c=\frac{12a}{5}\)

\(\Rightarrow a=10,b=15,c=24\)

a) 1 + 1 - 2 = 2 - 2 = 0

b) 2 + 6 - 2 = 8 - 2 = 6

c) 5 + 1 - 4 = 6 - 4 = 2

d) 3 + 5 - 2 = 8 - 2 = 6

a) 1 + 1 - 2 = 0.

b) 2 + 6 - 2 = 6.

c) 5 + 1 - 4 = 2.

d) 3 + 5 - 2 = 6.

Tick cho mình đi bạn!

Câu 1:
\(4\sqrt[4]{\left(a+1\right)\left(b+4\right)\left(c-2\right)\left(d-3\right)}\le a+1+b+4+c-2+d-3=a+b+c+d\)

Dấu = xảy ra khi a = -1; b = -4; c = 2; d= 3

\(\frac{a^2}{b^5}+\frac{1}{a^2b}\ge\frac{2}{b^3}\)\(\Leftrightarrow\)\(\frac{a^2}{b^5}\ge\frac{2}{b^3}-\frac{1}{a^2b}\)

\(\frac{2}{a^3}+\frac{1}{b^3}\ge\frac{3}{a^2b}\)\(\Leftrightarrow\)\(\frac{1}{a^2b}\le\frac{2}{3a^3}+\frac{1}{3b^3}\)

\(\Rightarrow\)\(\Sigma\frac{a^2}{b^5}\ge\Sigma\left(\frac{5}{3b^3}-\frac{2}{3a^3}\right)=\frac{1}{a^3}+\frac{1}{b^3}+\frac{1}{c^3}+\frac{1}{d^3}\)

A.4,2,1,0,3

TL

1+5=6

6+5=11

5+4=9

9+3=12

6+3=9

6-2=4

3-2=1

7-4=3

9-5=4

7-7=0

HT

a)

1 + 5 = 6

6 + 5 = 11

5 + 4 = 9

9 + 3 = 12

6 + 3 = 9

b)

6 - 2 = 4

3 - 2 = 1

7 - 4 = 3

9 - 5 = 4

7 - 7 = 0

k nhé:))