Câu a:

(128,4 - 73,2) : 2,4 + 18,32

= 55,2 : 2,4 + 18,32

= 23 + 18,32

= 41,32

Câu b:

Tìm \(x\) biết: 210 : \(x\) = 14,92 - 6,52

210 : \(x\) = 8,4

\(x\) = 210 : 8,4

\(x\) = 25

\(\frac{x}{y}=\frac{-1}{2}\Leftrightarrow2x=-y\Leftrightarrow y=-2x\)

Thay y=-2x vào biểu thức cần tính sẽ ra

\(250\times12-\left(242+302\times2,5\right)\)

\(=3000-997\)

\(=2003\)

BẠN LẤY CÁI 5/30+45/270 NHA

NHỚ K NHA

=117x(631-630)

=117x1

=117

Đ/s 117

\(A=\frac{4\cdot0,125\cdot20,2\cdot800\cdot0,25}{1,01\cdot75+0,26\cdot101-1,01}\)   

\(=\frac{4\cdot0,25\cdot0,125\cdot800\cdot20,2}{1,01\cdot75+0,26\cdot100\cdot1,01-1,01}\)   

\(=\frac{1\cdot100\cdot20,2}{1,01\cdot\left(75+26-1\right)}\)   

\(=\frac{100\cdot20,2}{100\cdot1,01}\)   

= 20 

\(B=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot\left(\frac{80}{56}-\frac{15}{12}:\frac{7}{8}\right)\)   

\(=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot\left(\frac{10}{7}-\frac{5}{4}\cdot\frac{8}{7}\right)\)   

\(=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot\left(\frac{10}{7}-\frac{10}{7}\right)\)   

\(=\left(\frac{178}{179}+\frac{179}{180}+\frac{180}{181}\right)\cdot0\)   

= 0 

B = (1999x1998 + 1998x1997)x(1+1/2: 1 1/2 - 11/3)

B = (1999x1998 + 1998x1997)x(1+1/2:3/2-4/3)

B = (1999x1998 +1998 x1997) x (1+1/2x2/3 - 4/3)

B = (1999 x 1998 + 1998 x 1997) x(1+1/3 - 4/3)

B = (1999 x 1998 + 1998 x 1997) x (4/3 - 4/3)

B = (1999 x 1998 + 1998 x 1997) x 0

B = 0

ko biết làm

a=6;A=2260