\(\frac{12}{24}\)+  \(\frac{24}{32}\)
K
Khách

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15 tháng 7 2017

A) (12/24 + 24/32 - 5/20) : 4/5

   = (1/2 + 3/4 - 1/4) : 4/5

   =(1/2 + 1/2) : 4/5

   =     1        : 4/5 

   =           5/4

B) 75/100 + 1/5 - 11/3 + 25/100

    = 3/4    + 1/5 - 11/3 + 1/4

    = (3/4 + 1/4) - 1/5+11/3

    =       1        -  1/5 + 11/3

    =             4/5        +  11/3

    =             67/15

   ( mk ko chắc câu B) 

         

16 tháng 5 2018

a/=(74-(-1937)1)

   =74-(-1937)

   =2011

b/=4/7+5/6:5-3/8*(-4)

   =4/7+1/6-(-3/2)

   =31/42-(-3/2)

   =47/21

minh chi biet bay nhieu

25 tháng 4 2018

a) = 3/3 x ( -24/54 +45/54 ) : 7/12

   = 1 x 21/54 x 12/7

   = 18/27 

( hiện tại mik chỉ lm đc thế này thui. thông cảm nk )

7 tháng 1

S = \(\frac12\times\frac13\) + \(\frac13\times\frac14\) + \(\frac14\times\frac15\) + \(\frac15\times\frac16\) + \(\frac17\times\frac18\) + \(\frac18\times\frac19\)

S = \(\frac12\) - \(\frac13\) + \(\frac13\) - \(\frac14\) + \(\frac14\) - \(\frac15\) + \(\frac15\) - \(\frac16\) + \(\frac17\) - \(\frac18\) + \(\frac18\) - \(\frac19\)

S = \(\frac12\) - \(\frac19\)

S = \(\frac{9}{18}-\frac{2}{18}\)

S = \(\frac{7}{18}\)


22 tháng 4 2017

Bài 1:

\(g.\frac{5}{11}+\frac{6}{11}=\frac{5+6}{11}=\frac{11}{11}=1\)\(\)

\(e.\frac{-17}{25}.\frac{20}{33}+\frac{-17}{25}.\frac{13}{33}+\frac{-3}{25}=\frac{-17}{25}.\left(\frac{20}{33}+\frac{13}{33}\right)+\frac{-3}{25}\)

\(=\frac{-17}{25}.1+\frac{-3}{25}=\frac{-17}{25}+\frac{-3}{25}=\frac{-17-3}{25}=\frac{-20}{25}=\frac{-4}{5}\)

\(d.\frac{5}{7}.\frac{19}{23}+\frac{5}{7}.\frac{5}{23}-\frac{5}{7}.\frac{1}{23}=\frac{5}{7}\left(\frac{19}{23}+\frac{5}{23}-\frac{1}{23}\right)\)

\(=\frac{5}{7}\left(\frac{19+5-1}{23}\right)=\frac{5}{7}.1=\frac{5}{7}\)

\(c.\left(-11\right).\frac{9}{22}=\frac{\left(-11\right).9}{22}=\frac{-99}{22}=\frac{-9}{2}\)

\(b.\frac{5}{6}-\frac{1}{8}=\frac{5.4}{6.4}-\frac{1.3}{8.3}=\frac{20}{24}-\frac{3}{24}=\frac{17}{24}\)

\(a.\frac{2}{3}+\frac{1}{5}-\frac{1}{6}=\frac{2.10}{3.10}+\frac{1.6}{5.6}-\frac{1.5}{6.5}=\frac{20}{30}+\frac{6}{30}-\frac{5}{30}\)

\(=\frac{20+6-5}{30}=\frac{21}{30}=\frac{7}{10}\)

Bài 2:

\(a.\frac{3}{4}+x=\frac{11}{12}\)

\(\Leftrightarrow x=\frac{11}{12}-\frac{3}{4}\)

\(\Leftrightarrow x=\frac{11}{12}-\frac{9}{12}\)

\(\Leftrightarrow x=\frac{2}{12}=\frac{1}{6}\)

\(b.x-\frac{11}{12}=0,5\)

\(\Leftrightarrow x=\frac{1}{2}-\frac{11}{12}\)

\(\Leftrightarrow x=\frac{6}{12}+\frac{11}{12}\)

\(\Leftrightarrow x=\frac{17}{12}\)

8 tháng 7 2020

Trả lời

\(A=\frac{7}{12}+\frac{5}{12}\div6-\frac{11}{36}\)

\(A=\frac{7}{12}+\frac{5}{12}\times\frac{1}{6}-\frac{11}{36}\)

\(A=\frac{7}{12}+\frac{5}{72}-\frac{11}{36}\)

\(A=\frac{25}{72}\)

    \(B=12\frac{1}{3}-\frac{5}{7}\div\left(24-23\frac{5}{7}\right)\)

\(B=\frac{37}{3}-\frac{5}{7}\div\left(24-\frac{166}{7}\right)\)

\(B=\frac{37}{3}-\frac{5}{7}\div\frac{2}{7}\)

\(B=\frac{37}{3}-\frac{5}{7}\times\frac{7}{2}\)

\(B=\frac{37}{3}-\frac{5}{2}\)

\(B=\frac{59}{6}\)

8 tháng 7 2020

Bài làm:

Ta có: 

\(A=\frac{7}{12}+\frac{5}{12}\div6-\frac{11}{36}\)

\(A=\frac{7}{12}+\frac{5}{72}-\frac{11}{36}\)

\(A=\frac{42+5-22}{72}=\frac{25}{72}\)

\(B=12\frac{1}{3}-\frac{5}{7}\div\left(24-23\frac{5}{7}\right)\)

\(B=\frac{37}{3}-\frac{5}{7}\div\left(24-23-\frac{5}{7}\right)\)

\(B=\frac{37}{3}-\frac{5}{7}\div\left(1-\frac{5}{7}\right)\)

\(B=\frac{37}{3}-\frac{5}{7}+1\)

\(B=\frac{265}{21}\)

3 tháng 8 2020

a) \(\frac{7}{5}.\frac{-31}{125}.\frac{1}{2}.\frac{10}{17}.\frac{-1}{2^3}=\frac{7.\left(-31\right).1.10.\left(-1\right)}{5.2.125.17.2^3}=\frac{31.7}{17.125.2^3}=\frac{217}{17000}\)

b) \(\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{20}{31}\right).\left(\frac{-5}{12}+\frac{1}{4}+\frac{1}{6}\right)=\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{20}{31}\right).0=0\)

c) \(\left(\frac{1}{2}+1\right).\left(\frac{1}{3}+1\right).\left(\frac{1}{4}+1\right)...\left(\frac{1}{99}+1\right)=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}...\frac{100}{99}=\frac{3.4.5...100}{2.3.4...99}=\frac{100}{2}=50\)

d) \(\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right)\left(\frac{1}{4}-1\right)...\left(\frac{1}{100}-1\right)=\frac{-1}{2}.\frac{-2}{3}.\frac{-3}{4}...\frac{-99}{100}=\frac{-\left(1.2.3..99\right)}{2.3.4...100}=-\frac{1}{100}\)

e) \(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}...\frac{899}{30^2}=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}...\frac{29.31}{30.30}=\frac{1.3.2.4.3.5...29.31}{2.2.3.3.4.4...30.30}=\frac{\left(1.2.3..29\right).\left(3.4.5...31\right)}{\left(2.3.4...30\right).\left(2.3.4...30\right)}\)

\(=\frac{1.31}{30.2}=\frac{31}{60}\)

14 tháng 1

Câu a:

{3849 - 2.[146 - (2.14 + 6: 2)]} : 32

= {3849 - 2.[146 - (28 + 3)]} : 32

= {3489 - 2.[146 - 31]} : 32

= {3489 - 2.115} : 32

= {3489 - 230} : 32

= 3259 : 32

= 3259/32

14 tháng 1

Câu b:

134 - 2.{156 - 6[54 - 2.(9 + 6)]}

= 134 - 2.{156 - 6.[54- 2. 15]}

= 134 - 2.{156 - 6.[54 - 30]}

= 134 - 2.{156 - 6.24]

= 134 - 2.12

= 134 - 24

= 110